Java 猜数字程序错误？

我正在尝试创建一个数字猜测程序，用户输入一个数字，程序会告诉您输入的数字是否过高、过低或正确。程序在0-100之间选择一个随机数。问题是当我开始测试程序时，当我选择1时，程序告诉我猜测太高。但这是错误的，因为该程序只能处理整数。如果用户输入的数字不等于随机数，则1必须太低。 谁能看看我的代码，看看有没有什么奇怪的地方

int guess;
    int guess2;
    int guess3;
    int guess4;
    int guess5;
    int random = (int)Math.random() * 100;
    Scanner input = new Scanner(System.in);

    System.out.println("Try to guess a number between 0-100. You have five chances.");
    guess = input.nextInt();
    if(guess >= 100 || guess <= 0){
        System.out.println("Error, that is not a number between 0-100.");
    } else if(guess > random){
        System.out.println("The guess is too high.");
    } else if(guess < random){
        System.out.println("The guess is too low.");
    } else if(guess == random){
        System.out.println("YOU WIN");
    } else{
    }

    System.out.println("Second guess.");
    guess2 = input.nextInt();
    if(guess2 >= 100 || guess2 <= 0){
        System.out.println("Error, that is not a number between 0-100.");
    } else if(guess2 > random){
        System.out.println("The guess is too high.");
    } else if(guess2 < random){
        System.out.println("The guess is too low.");
    } else if(guess2 == random){
        System.out.println("YOU WIN");
    } else{
    }

    System.out.println("Third guess.");
    guess3 = input.nextInt();
    if(guess3 >= 100 || guess3 <= 0){
        System.out.println("Error, that is not a number between 0-100.");
    } else if(guess3 > random){
        System.out.println("The guess is too high.");
    } else if(guess3 < random){
        System.out.println("The guess is too low.");
    } else if(guess3 == random){
        System.out.println("YOU WIN");
    } else{
    }

    System.out.println("Fourth guess.");
    guess4 = input.nextInt();
    if(guess4 >= 100 || guess4 <= 0){
        System.out.println("Error, that is not a number between 0-100.");
    } else if(guess4 > random){
        System.out.println("The guess is too high.");
    } else if(guess4 < random){
        System.out.println("The guess is too low.");
    } else if(guess4 == random){
        System.out.println("YOU WIN");
    } else{
    }

    System.out.println("Last guess.");
    guess5 = input.nextInt();
    if(guess5 >= 100 || guess5 <= 0){
        System.out.println("Error, that is not a number between 0-100.");
    } else if(guess5 > random){
        System.out.println("The guess is too high.");
    } else if(guess5 < random){
        System.out.println("The guess is too low.");
    } else if(guess5 == random){
        System.out.println("YOU WIN");
    } else{
    }

---

更改int random=intMath.random*100；to int random=intMath.random*100

看起来不错，但您需要更改此行的演员阵容：

int random = (int)Math.random() * 100;

致：

当前您的随机数始终为0。为什么？因为您将Math.random强制转换为int，在Java中，这意味着小数点后的所有内容都将丢失。因此，0.85将变为0。0 * 100 = 0. 通过在Math.random之后添加括号，我们将其乘以100

另外，请注意，您的随机数可能是0，但永远不会是100。Math.random返回一个大于或等于0且小于1的数字。当您将其转换为int时，99.9999将变为99

如果您希望它真的是0-100，您会希望：

int random = (int)(Math.random() * 101);

此外，您可能希望在玩家获胜后终止游戏。因此，改变这一点：

System.out.println("YOU WIN");

为此：

System.out.println("YOU WIN");
return;  //end

---

最后，您的empty else子句永远不会被调用。您有超出范围、大于随机、小于随机和等于随机的条件。您可以安全地删除死代码。

您的代码有两个主要问题：

第一:

您未能立即强制转换随机变量，因此“随机值”的值始终为0

正确的样式是：

int random = (int)(Math.random() * 100);

第二：

你的if结构很糟糕：

例如：

if(guess >= 100 || guess <= 0){

---

说明：如果浇注数介于100和0之间，请执行以下操作。如果没有，请告诉用户他或她超出范围

您可以这样编写代码。可以很容易地使用for循环

    int guess;
    int random = (int) (Math.random() * 100);
    Scanner input = new Scanner(System.in);

    System.out.println("Try to guess a number between 0-100. You have five chances.");
    for (int i = 0; i < 5; i++) {
        System.out.println("Chance " + (i + 1));
        guess = input.nextInt();
        if (guess >= 100 || guess <= 0) {
            System.out.println("Error, that is not a number between 0-100.");
        } else if (guess > random) {
            System.out.println("The guess is too high.");
        } else if (guess < random) {
            System.out.println("The guess is too low.");
        } else if (guess == random) {
            System.out.println("YOU WIN");
            break;
        }
    }
    System.out.println(random);

---

那么，语句是否应该在开始时再次定义它，然后在语句结束时定义错误呢？我有点困惑为什么需要ifguess=0，因为程序员已经知道了这一点。是的，我更改了我的代码，你了解了Java中的循环概念吗？我了解了while和for循环的功能，但是老师从来没有真正说过如何组织格式。哦，好吧，如果你愿意的话，我可以为你添加一些信息，你可以改进你的代码吗？@noctune当你在其他部分遇到问题时，你是如何接受答案的？所以return在if语句中结束程序的？return标志着方法的结束。在本例中，您处于程序的main方法main中，因此它将结束程序。@nostromo您好吗？只是友好点你看到这条线了吗？如果猜2>=100 | |猜2看，我是老同学，所以我总是被教导所有函数/方法都有一个入口点和一个出口点。与其在每个赢的状态下敲打一个返回语句，不如将所有逻辑都包含在一个循环中，然后打破循环-但这只是在你的帖子中添加了一些解释，这可能有助于其他人快速理解。赢的时候打破循环，否则你会一直重复猜测。。。

if (guess <= 100 && guess >= 0) {
        if (guess > random) {
            System.out.println("The guess is too high.");
        } else if (guess < random) {
            System.out.println("The guess is too low.");
        } else if (guess == random) {
            System.out.println("YOU WIN");
        }
     } else {
        System.out.println("Error, that is not a number between 0-100.");
    }

    int guess;
    int random = (int) (Math.random() * 100);
    Scanner input = new Scanner(System.in);

    System.out.println("Try to guess a number between 0-100. You have five chances.");
    for (int i = 0; i < 5; i++) {
        System.out.println("Chance " + (i + 1));
        guess = input.nextInt();
        if (guess >= 100 || guess <= 0) {
            System.out.println("Error, that is not a number between 0-100.");
        } else if (guess > random) {
            System.out.println("The guess is too high.");
        } else if (guess < random) {
            System.out.println("The guess is too low.");
        } else if (guess == random) {
            System.out.println("YOU WIN");
            break;
        }
    }
    System.out.println(random);