Java 我需要一个替代Android中HttpClient的选项来将数据发送到PHP,因为它不再受支持
目前,我正在使用Java 我需要一个替代Android中HttpClient的选项来将数据发送到PHP,因为它不再受支持,java,android,api,http-post,apache-commons-httpclient,Java,Android,Api,Http Post,Apache Commons Httpclient,目前,我正在使用HttpClient,HttpPost从Android应用程序向我的PHP服务器发送数据,但所有这些方法在API 22中都被弃用,在API 23中被删除,那么有哪些替代选项呢 我到处搜索,但什么也没找到。已弃用,现在已删除: org.apache.http.client.HttpClient: 此接口在API级别22中被弃用。 请改用openConnection()。详情请浏览本网页 这意味着您应该切换到java.net.URL.openConnection() 另请参见新文档
HttpClient
,HttpPost
从Android应用程序
向我的PHP服务器
发送数据,但所有这些方法在API 22中都被弃用,在API 23中被删除,那么有哪些替代选项呢
我到处搜索,但什么也没找到。已弃用,现在已删除:
org.apache.http.client.HttpClient
:
此接口在API级别22中被弃用。
请改用openConnection()。详情请浏览本网页
这意味着您应该切换到java.net.URL.openConnection()
另请参见新文档
以下是您如何做到这一点:
URL url = new URL("http://some-server");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
// read the response
System.out.println("Response Code: " + conn.getResponseCode());
InputStream in = new BufferedInputStream(conn.getInputStream());
String response = org.apache.commons.io.IOUtils.toString(in, "UTF-8");
System.out.println(response);
IOUtils
文档:IOUtils
Maven依赖项:以下代码位于异步任务中:
在我的后台进程中:
String POST_PARAMS = "param1=" + params[0] + "¶m2=" + params[1];
URL obj = null;
HttpURLConnection con = null;
try {
obj = new URL(Config.YOUR_SERVER_URL);
con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("POST");
// For POST only - BEGIN
con.setDoOutput(true);
OutputStream os = con.getOutputStream();
os.write(POST_PARAMS.getBytes());
os.flush();
os.close();
// For POST only - END
int responseCode = con.getResponseCode();
Log.i(TAG, "POST Response Code :: " + responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) { //success
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// print result
Log.i(TAG, response.toString());
} else {
Log.i(TAG, "POST request did not work.");
}
} catch (IOException e) {
e.printStackTrace();
}
参考:
我也遇到了这个问题,我自己制作了一个类来解决这个问题。 它基于java.net,最多支持android的API 24 请查看: 使用该类,您可以轻松地:
GET
请求POST
请求PUT
请求DELETE
HTTP状态码
HTTP头文件(使用varargs)
String
查询添加到请求HashMap
{key=value}字符串
JSONObject
//Consider next request:
HttpRequest req=new HttpRequest("http://host:port/path");
示例1:
//prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29, return true - if worked
req.prepare(HttpRequest.Method.POST).withData("name=Bubu&age=29").send();
// prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29 and read server's response as JSONObject
HashMap<String, String>params=new HashMap<>();
params.put("name", "Groot");
params.put("age", "29");
req.prepare(HttpRequest.Method.POST).withData(params).sendAndReadJSON();
//Send Http PUT request to: "http://some.url" with request header:
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
HttpRequest req=new HttpRequest(url);//HttpRequest to url: "http://some.url"
req.withHeaders("Content-Type: application/json");//add request header: "Content-Type: application/json"
req.prepare(HttpRequest.Method.PUT);//Set HttpRequest method as PUT
req.withData(json);//Add json data to request body
JSONObject res=req.sendAndReadJSON();//Accept response as JSONObject
//Equivalent to previous example, but in a shorter way (using methods chaining):
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
//Shortcut for example 5 complex request sending & reading response in one (chained) line
JSONObject res=new HttpRequest(url).withHeaders("Content-Type: application/json").prepare(HttpRequest.Method.PUT).withData(json).sendAndReadJSON();
//Downloading file
byte [] file = new HttpRequest("http://some.file.url").prepare().sendAndReadBytes();
FileOutputStream fos = new FileOutputStream("smile.png");
fos.write(file);
fos.close();
示例2:
// prepare http get request, send to "http://host:port/path" and read server's response as String
req.prepare().sendAndReadString();
示例3:
//prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29, return true - if worked
req.prepare(HttpRequest.Method.POST).withData("name=Bubu&age=29").send();
// prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29 and read server's response as JSONObject
HashMap<String, String>params=new HashMap<>();
params.put("name", "Groot");
params.put("age", "29");
req.prepare(HttpRequest.Method.POST).withData(params).sendAndReadJSON();
//Send Http PUT request to: "http://some.url" with request header:
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
HttpRequest req=new HttpRequest(url);//HttpRequest to url: "http://some.url"
req.withHeaders("Content-Type: application/json");//add request header: "Content-Type: application/json"
req.prepare(HttpRequest.Method.PUT);//Set HttpRequest method as PUT
req.withData(json);//Add json data to request body
JSONObject res=req.sendAndReadJSON();//Accept response as JSONObject
//Equivalent to previous example, but in a shorter way (using methods chaining):
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
//Shortcut for example 5 complex request sending & reading response in one (chained) line
JSONObject res=new HttpRequest(url).withHeaders("Content-Type: application/json").prepare(HttpRequest.Method.PUT).withData(json).sendAndReadJSON();
//Downloading file
byte [] file = new HttpRequest("http://some.file.url").prepare().sendAndReadBytes();
FileOutputStream fos = new FileOutputStream("smile.png");
fos.write(file);
fos.close();
示例6:
//prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29, return true - if worked
req.prepare(HttpRequest.Method.POST).withData("name=Bubu&age=29").send();
// prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29 and read server's response as JSONObject
HashMap<String, String>params=new HashMap<>();
params.put("name", "Groot");
params.put("age", "29");
req.prepare(HttpRequest.Method.POST).withData(params).sendAndReadJSON();
//Send Http PUT request to: "http://some.url" with request header:
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
HttpRequest req=new HttpRequest(url);//HttpRequest to url: "http://some.url"
req.withHeaders("Content-Type: application/json");//add request header: "Content-Type: application/json"
req.prepare(HttpRequest.Method.PUT);//Set HttpRequest method as PUT
req.withData(json);//Add json data to request body
JSONObject res=req.sendAndReadJSON();//Accept response as JSONObject
//Equivalent to previous example, but in a shorter way (using methods chaining):
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
//Shortcut for example 5 complex request sending & reading response in one (chained) line
JSONObject res=new HttpRequest(url).withHeaders("Content-Type: application/json").prepare(HttpRequest.Method.PUT).withData(json).sendAndReadJSON();
//Downloading file
byte [] file = new HttpRequest("http://some.file.url").prepare().sendAndReadBytes();
FileOutputStream fos = new FileOutputStream("smile.png");
fos.write(file);
fos.close();
示例7:
//prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29, return true - if worked
req.prepare(HttpRequest.Method.POST).withData("name=Bubu&age=29").send();
// prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29 and read server's response as JSONObject
HashMap<String, String>params=new HashMap<>();
params.put("name", "Groot");
params.put("age", "29");
req.prepare(HttpRequest.Method.POST).withData(params).sendAndReadJSON();
//Send Http PUT request to: "http://some.url" with request header:
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
HttpRequest req=new HttpRequest(url);//HttpRequest to url: "http://some.url"
req.withHeaders("Content-Type: application/json");//add request header: "Content-Type: application/json"
req.prepare(HttpRequest.Method.PUT);//Set HttpRequest method as PUT
req.withData(json);//Add json data to request body
JSONObject res=req.sendAndReadJSON();//Accept response as JSONObject
//Equivalent to previous example, but in a shorter way (using methods chaining):
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it
//Shortcut for example 5 complex request sending & reading response in one (chained) line
JSONObject res=new HttpRequest(url).withHeaders("Content-Type: application/json").prepare(HttpRequest.Method.PUT).withData(json).sendAndReadJSON();
//Downloading file
byte [] file = new HttpRequest("http://some.file.url").prepare().sendAndReadBytes();
FileOutputStream fos = new FileOutputStream("smile.png");
fos.write(file);
fos.close();
这是我应用于httpclient在这个版本的android 22中不推荐使用的问题的解决方案`
public static final String USER_AGENT = "Mozilla/5.0";
public static String sendPost(String _url,Map<String,String> parameter) {
StringBuilder params=new StringBuilder("");
String result="";
try {
for(String s:parameter.keySet()){
params.append("&"+s+"=");
params.append(URLEncoder.encode(parameter.get(s),"UTF-8"));
}
String url =_url;
URL obj = new URL(_url);
HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("User-Agent", USER_AGENT);
con.setRequestProperty("Accept-Language", "UTF-8");
con.setDoOutput(true);
OutputStreamWriter outputStreamWriter = new OutputStreamWriter(con.getOutputStream());
outputStreamWriter.write(params.toString());
outputStreamWriter.flush();
int responseCode = con.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + params);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine + "\n");
}
in.close();
result = response.toString();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}catch (Exception e) {
e.printStackTrace();
}finally {
return result;
}
}
publicstaticfinalstringuser\u-AGENT=“Mozilla/5.0”;
公共静态字符串sendPost(字符串_url,映射参数){
StringBuilder参数=新StringBuilder(“”);
字符串结果=”;
试一试{
对于(字符串s:parameter.keySet()){
参数追加(&“+s+”=”);
params.append(URLEncoder.encode(parameter.get),“UTF-8”);
}
字符串url=\uURL;
URL obj=新URL(_URL);
HttpsURLConnection con=(HttpsURLConnection)obj.openConnection();
con.setRequestMethod(“POST”);
con.setRequestProperty(“用户代理”,用户代理);
con.setRequestProperty(“接受语言”、“UTF-8”);
con.设置输出(真);
OutputStreamWriter OutputStreamWriter=新的OutputStreamWriter(con.getOutputStream());
outputStreamWriter.write(params.toString());
outputStreamWriter.flush();
int responseCode=con.getResponseCode();
System.out.println(“\n向URL发送'POST'请求:“+URL”);
System.out.println(“Post参数:“+params”);
System.out.println(“响应代码:“+responseCode”);
BufferedReader in=新的BufferedReader(新的InputStreamReader(con.getInputStream());
字符串输入线;
StringBuffer响应=新的StringBuffer();
而((inputLine=in.readLine())!=null){
响应。追加(inputLine+“\n”);
}
in.close();
结果=response.toString();
}捕获(不支持的编码异常e){
e、 printStackTrace();
}捕获(格式错误){
e、 printStackTrace();
}捕获(协议例外e){
e、 printStackTrace();
}捕获(IOE异常){
e、 printStackTrace();
}捕获(例外e){
e、 printStackTrace();
}最后{
返回结果;
}
}
我在使用HttpClent和HttpPost方法时遇到了类似的问题,因为我不想更改我的代码,所以我在build.gradle(模块)文件中找到了替代选项,从buildToolsVersion“23.0.1 rc3”中删除了“rc3”,这对我很有效。希望有帮助
哪个客户最好
ApacheHTTP客户端在Eclair和Froyo上的bug较少。这是最好的
这些版本的选择
对于姜饼和更好的产品,HttpURLConnection是最佳选择。它的
简单的API和小尺寸使它非常适合Android
更多信息参考(Android开发者博客)您可以继续使用HttpClient。谷歌只反对他们自己版本的Apache组件。您可以安装Apache的HttpClient的全新、功能强大且未弃用的版本,如我在本文中所述:如果针对API 22及更旧版本,则应在build.gradle中添加以下行
dependencies {
compile group: 'org.apache.httpcomponents' , name: 'httpclient-android' , version: '4.3.5.1'
}
dependencies {
compile group: 'cz.msebera.android' , name: 'httpclient', version: '4.4.1.1'
}
如果针对API 23及更高版本,则应在build.gradle中添加以下行
dependencies {
compile group: 'org.apache.httpcomponents' , name: 'httpclient-android' , version: '4.3.5.1'
}
dependencies {
compile group: 'cz.msebera.android' , name: 'httpclient', version: '4.4.1.1'
}
如果仍要使用httpclient库,在Android Marshmallow(sdk 23)中,您可以添加:
useLibrary 'org.apache.http.legacy'
在android{}部分中构建.gradle作为一种解决方法。这似乎是谷歌自己的一些gms库所必需的 您可以使用我的易于使用的自定义类。 只需创建抽象类(匿名)的对象并定义onsuccess()和onfail()方法。
您应该澄清您所处的平台(java、php、ruby?)和您现在使用的library+版本,以及您试图更新到的library+版本(包括确切版本和库名)。我正在使用HttpPost和HttpClient从Android应用程序向PHP发送数据,但这些方法在API 22的新更新中已被弃用,因此我需要一些选项来解决此问题。您的答案中的
IOUtils
是什么?通过添加指向公用IO
的链接来改进答案(IOUtils
)文档和maven搜索站点。看起来