Java：询问用户是否想再次玩？

我正在做一个石头剪刀游戏，一旦电脑或用户有了一个最好的2/3，它就会提示他们是否想再次玩这个游戏。如果“是”，则程序重新启动，如果“否”，则系统退出

我该怎么做

    public static void main(String[] args) {
    Random r = new Random();
    int gameCount = 0;
    int computerWins = 0;
    int playerWins = 0;
    int rock, paper, scissors;
    rock = 1;
    paper = 2;
    scissors = 3;
    int playerChoice = 0;
    int computerChoice;

    System.out.println("Welcome to Rock Paper Scissors! Best 2 out of 3!");

    //While the game count is less than 3, the loop will repeat
    while (gameCount < 3) {
        computerChoice = r.nextInt(3) + 1;
        System.out.println("Enter \"Rock\", \"Paper\", or \"Scissors\"");
        String USER_Input = userInput.next();
        if (USER_Input.equalsIgnoreCase("Rock")) {
            playerChoice = 1;
        }
        if (USER_Input.equalsIgnoreCase("Paper")) {
            playerChoice = 2;
        }
        if (USER_Input.equalsIgnoreCase("Scissors")) {
            playerChoice = 3;
        }
        //If player enters anything besides rock, paper, or scissors
        if (playerChoice <= 0 || playerChoice > 3) {
            System.out.println("That wasn't an option");
            computerWins++;
            gameCount++;
            System.out.println("Not a valid input! Computer Wins!\n" +
                    "Player has won " +playerWins + " times and the computer " +
                    "has won " + computerWins + " times");

            //The game goes on, and the winners are added up!
        } else if (playerChoice == 1 && computerChoice == 2) {
            computerWins++;
            gameCount++;
            System.out.println("Rock v Paper! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 1) {
            playerWins++;
            gameCount++;
            System.out.println("Paper v Rock! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 3) {
            computerWins++;
            gameCount++;
            System.out.println("Paper v Scissors! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 2) {
            playerWins++;
            gameCount++;
            System.out.println("Scissors v Paper! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 1) {
            computerWins++;
            gameCount++;
            System.out.println("Scissors v Rock! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 3) {
            playerWins++;
            gameCount++;
            System.out.println("Rock v Scissors! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 1) {
            gameCount++;
            System.out.println("Rock v Rock! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 2) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 3) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        }

        //Check if game count reaches max games then chooses a winner
        if (gameCount == 3 && computerWins > playerWins || computerWins == 2) {
            System.out.println("The Computer Wins!");
            break;
        } else if (gameCount == 3 && computerWins < playerWins || playerWins ==2) {
            System.out.println("The Player Wins!");
        } else if (gameCount == 3 && computerWins == playerWins) {
            System.out.println("The game is a tie!");
        }
    }
}

publicstaticvoidmain（字符串[]args）{
随机r=新随机（）；
int gameCount=0；
int=0；
int playerWins=0；
石头、布、剪刀；
岩石=1；
纸张=2；
剪刀=3；
int playerChoice=0；
国际计算机选择；
System.out.println（“欢迎来到石头剪刀！三分之二最好！”）；
//当游戏计数小于3时，循环将重复
而（游戏数<3）{
computerChoice=r.nextInt（3）+1；
System.out.println（“输入“岩石”、“纸”或“剪刀”）；
字符串USER_Input=userInput.next（）；
if（用户输入。等效信号情况（“岩石”））{
playerChoice=1；
}
if（用户输入。相等信号情况（“纸张”））{
playerChoice=2；
}
if（用户输入。等效信号情况（“剪刀”））{
playerChoice=3；
}
//如果玩家输入除石头、布或剪刀以外的任何东西
如果（玩家选择3）{
System.out.println（“这不是一个选项”）；
computerWins++；
gameCount++；
System.out.println（“不是有效的输入！计算机获胜！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
//游戏继续进行，赢家加起来了！
}else if（playerChoice==1&&computerChoice==2）{
computerWins++；
gameCount++；
System.out.println（“岩石对纸张！计算机获胜！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==2&&computerChoice==1）{
playerWins++；
gameCount++；
System.out.println（“纸对石！玩家赢！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==2&&computerChoice==3）{
computerWins++；
gameCount++；
System.out.println（“纸对剪刀！计算机赢！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==3&&computerChoice==2）{
playerWins++；
gameCount++；
System.out.println（“剪刀对布！玩家赢！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==3&&computerChoice==1）{
computerWins++；
gameCount++；
System.out.println（“剪刀对石头！电脑赢！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==1&&computerChoice==3）{
playerWins++；
gameCount++；
System.out.println（“石头对剪刀！玩家赢！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==1&&computerChoice==1）{
gameCount++；
System.out.println（“岩石对岩石！领带！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==2&&computerChoice==2）{
gameCount++；
System.out.println（“纸张对纸张！领带！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}else if（playerChoice==3&&computerChoice==3）{
gameCount++；
System.out.println（“纸张对纸张！领带！\n”+
“玩家赢得了”+玩家+“时代和电脑”+
“已赢得”+计算机赢得”+“时代”）；
}
//检查游戏计数是否达到最大游戏数，然后选择赢家
如果（gameCount==3&&computerWins>playerWins | | computerWins==2）{
System.out.println（“计算机赢了！”）；
打破
}否则如果（游戏计数=3&&computerWins

您的整个逻辑都在main（）方法中。我建议您将while{}-part移动到一个新方法中，比如play（）

在main（）中，实现一个新的while（），提示消息并从键盘读取输入：

public static void main(String args[]) {
        Scanner inputScanner = new Scanner(System.in);
        String userInput = "";
        do {
            play();
            System.out.print("Do you want to play again ([Y] / n)? ");
            userInput = inputScanner.nextLine();
            System.out.println(userInput);
        } while (userInput.equals("Y") || userInput.equals(""));
}

---

HTH，SiS

您的整个逻辑都在main（）方法中。我建议您将while{}-part移动到一个新方法中，比如play（）

在main（）中，实现一个新的while（），提示消息并从键盘读取输入：

public static void main(String args[]) {
        Scanner inputScanner = new Scanner(System.in);
        String userInput = "";
        do {
            play();
            System.out.print("Do you want to play again ([Y] / n)? ");
            userInput = inputScanner.nextLine();
            System.out.println(userInput);
        } while (userInput.equals("Y") || userInput.equals(""));
}

---

HTH，SiS

一个可能的解决方案是将游戏放入另一个while循环（包围gameCount的while循环），并在while循环中为变量创建一个switch语句，比如说

gameContinue

。在游戏结束时，用户将收到提示，说明是否继续。根据他们的回答，您可以更改变量的值

gameContinue

，然后就可以开始了。

一个可能的解决方案是将游戏放入另一个while循环（包围gameCount的while循环）中，并在