解密信用卡号时返回javax.crypto.IllegalBlockSizeException
我的加密方法是:解密信用卡号时返回javax.crypto.IllegalBlockSizeException,java,jakarta-ee,encryption,cryptography,Java,Jakarta Ee,Encryption,Cryptography,我的加密方法是: private static final String ALGORITHM = "AES/ECB/PKCS5Padding"; private static final byte[] KEY = "StBet9834#$10BCy".getBytes(); private String encryptCreditCard(String ccNumber) { // do some encryption if (ccNumber == null || ccNum
private static final String ALGORITHM = "AES/ECB/PKCS5Padding";
private static final byte[] KEY = "StBet9834#$10BCy".getBytes();
private String encryptCreditCard(String ccNumber) {
// do some encryption
if (ccNumber == null || ccNumber.length() == 0) {
return "";
}
Key key = new SecretKeySpec(KEY, "AES");
try {
Cipher c = Cipher.getInstance(ALGORITHM);
c.init(Cipher.ENCRYPT_MODE, key);
//return Base64.encodeBytes(c.doFinal(ccNumber.getBytes()));
byte[] ccNumberBytes = ccNumber.getBytes();
byte[] encCCNumber = c.doFinal(ccNumberBytes);
return new String(Base64.encodeBase64(encCCNumber));
} catch (Exception e) {
throw new RuntimeException(e);
}
}
我使用以下方法解密我的信用卡详细信息:
public void decryptCreditCard() {
Key key = new SecretKeySpec(KEY, "AES");
try {
String ccNumber = this.cardNumber;
if (ccNumber == null || ccNumber.length() == 0) {
return;
}
Cipher c = Cipher.getInstance(ALGORITHM);
c.init(Cipher.DECRYPT_MODE, key);
byte[] ccENCBytes = Base64.decodeBase64(ccNumber);
byte[] ccDECBytes = c.doFinal(ccENCBytes);
this.plainCardNumber = new String(ccDECBytes);
this.last4CreditCard = plainCardNumber.substring(this.plainCardNumber.length() - 4);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
我的测试卡号字符串是:5123456789012346。执行此行时:
byte[] ccDECBytes = c.doFinal(ccENCBytes);
我得到以下例外情况:
Caused by: javax.crypto.IllegalBlockSizeException: Input length must be multiple of 16 when decrypting with padded cipher
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:750)
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:676)
at com.sun.crypto.provider.AESCipher.engineDoFinal(AESCipher.java:313)
at javax.crypto.Cipher.doFinal(Cipher.java:2087)
at stbet.model.core.CustomerAccount.decryptCreditCard(CustomerAccount.java:527)
这个错误表示什么?非常感谢您的帮助。您的算法必须用填充表示密码:例如:AES/CBC/PKCS5Padding 编码消息的字符串表示不能丢失字节。您正在对字符串使用defualt编码,因此很可能是UTF-8,这不合适。您需要字节到字节的映射,例如:“ISO-8859-1” 返回新字符串(Base64.encodeBase64(encCCNumber),“ISO-8859-1”)
或者简单地使用Base64.encodeBase64String来完成这项工作 @ArtjomB。添加了加密方法。您的代码看起来很好。您确定解密方法中的
ccNumber
是加密方法的实际输出吗?@ArtjomB。是的,输出值是相同的:(我刚刚尝试了你的代码,它应该可以工作。完整的代码对你有效吗?如果有效,那么问题就在加密和解密之间。@ArtjomB。感谢你宝贵的时间。我正在尝试你的代码。我正在使用“org.apache.commons.codec.binary.Base64”当您使用util.Base64时,这可能是问题所在。(当我们的项目使用该库时)java版本也是7。字符串/字节转换必须保留“字节”。请参阅完整答案。我也尝试了您的解决方案。但错误仍然是一样的。虽然这些都是好主意,但它们不应导致出现IllegalBlockSizeException