Java 无法从JLable复制/粘贴
我正在使用下面的代码显示一个消息对话框:Java 无法从JLable复制/粘贴,java,jframe,jlabel,Java,Jframe,Jlabel,我正在使用下面的代码显示一个消息对话框: String msg = "<html>You need to download it from here: <br><b> ttp://chromedriver.storage.googleapis.com/index.html?path=2.20/ </b <br></html>"; JLabel label = new JLabel(msg); label.setFont(new j
String msg = "<html>You need to download it from here: <br><b> ttp://chromedriver.storage.googleapis.com/index.html?path=2.20/ </b <br></html>";
JLabel label = new JLabel(msg);
label.setFont(new java.awt.Font("serif", java.awt.Font.PLAIN, 14));
JOptionPane.showMessageDialog(null, label);
但是用户无法复制和粘贴链接,所以,有点小技巧不太好,但也不太好 使用绝地武士窗格
我很想在JLabel中添加一个MouseListener,然后在鼠标左键上单击,简单地跟随链接,但这就是我您考虑过使用一个底层JTextField吗?还有一些超链接组件实现漂浮在webs@MadProgrammer是的,但我不喜欢它的样子like@Reimeus请解释更多?忘记了JTextField不呈现HTML:P
public class TestPane extends JPanel {
public TestPane() {
JEditorPane field = new JEditorPane();
field.setContentType("text/html");
field.setText("<html><a href='https://google.com'>Google it</a></html>");
field.setEditable(false);
field.setBorder(null);
field.setOpaque(false);
setLayout(new GridBagLayout());
add(field);
}
}
public class TestPane extends JPanel {
public TestPane() {
JLabel field = new JLabel("<html><a href='https://google.com'>Google it</a></html>");
field.setCursor(Cursor.getPredefinedCursor(Cursor.HAND_CURSOR));
setLayout(new GridBagLayout());
GridBagConstraints gbc = new GridBagConstraints();
gbc.gridwidth = GridBagConstraints.REMAINDER;
add(field, gbc);
add(new JTextField(20), gbc);
JPopupMenu menu = new JPopupMenu();
menu.add(new CopyAction("https://google.com"));
menu.add(new OpenAction("https://google.com"));
field.setComponentPopupMenu(menu);
}
public class CopyAction extends AbstractAction {
private String url;
public CopyAction(String url) {
super("Copy");
this.url = url;
}
@Override
public void actionPerformed(ActionEvent e) {
Toolkit tk = Toolkit.getDefaultToolkit();
Clipboard cb = tk.getSystemClipboard();
cb.setContents(new StringSelection(url), null);
}
}
public class OpenAction extends AbstractAction {
private String url;
public OpenAction(String url) {
super("Follow");
this.url = url;
}
@Override
public void actionPerformed(ActionEvent e) {
Desktop desktop = Desktop.getDesktop();
if (desktop.isSupported(Action.BROWSE)) {
try {
desktop.browse(new URL(url).toURI());
} catch (IOException | URISyntaxException ex) {
ex.printStackTrace();
}
}
}
}
}