在Java中创建对象实例时出错
代码: 输出: 黄金32德国牧羊犬 黄金32德国牧羊犬在Java中创建对象实例时出错,java,Java,代码: 输出: 黄金32德国牧羊犬 黄金32德国牧羊犬 虽然我正在创建两个对象实例,但只打印其中一个的字段。错误在哪里?您已经使用了静态访问修饰符,并且静态变量为每个类对象共享内存。如果不想,只需从年龄、名称和品种中删除静态 public class Dog{ static int age; static String name; static String breed; public Dog(String name,int ag
虽然我正在创建两个对象实例,但只打印其中一个的字段。错误在哪里?您已经使用了静态访问修饰符,并且静态变量为每个类对象共享内存。如果不想,只需从年龄、名称和品种中删除静态
public class Dog{
static int age;
static String name;
static String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
System.out.println(low.name+" "+low.age+" "+low.breed);
System.out.println(high.name+" "+high.age+" "+high.breed);
}
}
所有的静态字段都是共享的,每个类都有静态字段,但您希望每个实例都有实例字段。改变
public class Dog{
int age;
String name;
String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
System.out.println(low.name+" "+low.age+" "+low.breed);
System.out.println(high.name+" "+high.age+" "+high.breed);
}
}
到
而且您可能应该有访问器getters方法——如果您添加一个toString,您的打印将会简化。像
然后你就可以用它来打印了
@Override
public String toString() {
return name + " " + age + " " + breed;
}
在代码中将静态更改为私有: 例如: 输出:
public class Dog{
private int age;
private String name;
private String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
System.out.println(low.name+" "+low.age+" "+low.breed);
System.out.println(high.name+" "+high.age+" "+high.breed);
}
}
而且:
luffy 19 pomerian
gold 32 german shepherd
输出:
public class Dog{
private int age;
private String name;
private String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
void toStrig (){
System.out.println(name+" "+ age+" "+breed);
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
high.toStrig();
low.toStrig();
}
}
不要使用静态字段如果希望类的每个实例都有不同的值,那么就不要使用静态字段。但是,如果您希望类的每个实例都具有相同的值,那么请使用static.Ah!我明白了。所以静态是属于类的东西,一旦做了更改,就会反映在整个类中。谢谢
public class Dog{
private int age;
private String name;
private String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
System.out.println(low.name+" "+low.age+" "+low.breed);
System.out.println(high.name+" "+high.age+" "+high.breed);
}
}
luffy 19 pomerian
gold 32 german shepherd
public class Dog{
private int age;
private String name;
private String breed;
public Dog(String name,int age,String breed){
this.name=name;
this.age=age;
this.breed=breed;
}
public Dog(String name,int age){
this(name,age,"greed");
}
void toStrig (){
System.out.println(name+" "+ age+" "+breed);
}
public static void main(String args[]){
Dog high=new Dog("luffy",19,"pomerian");
Dog low=new Dog("gold",32,"german shepherd");
high.toStrig();
low.toStrig();
}
}
luffy 19 pomerian
gold 32 german shepherd