需要帮助在Java中创建正则表达式吗
我正在尝试对字符串应用正则表达式,以获得以下格式的输出 输入字符串:需要帮助在Java中创建正则表达式吗,java,regex,Java,Regex,我正在尝试对字符串应用正则表达式,以获得以下格式的输出 输入字符串: params=Param1{index}~[Value1|Value2|....]^Param2~[Value1|Value2|....] 输出应为Map 例如 代码: 她就是我要做的代码 String textPatt = "params"; String key = textPatt.replace("/[\\[]/", "\\[").replace("/[\\]]/", "\\]"); String pattern =
params=Param1{index}~[Value1|Value2|....]^Param2~[Value1|Value2|....]
输出应为Map
例如
代码:
她就是我要做的代码
String textPatt = "params";
String key = textPatt.replace("/[\\[]/", "\\[").replace("/[\\]]/", "\\]");
String pattern = new String("[\\?&]" + key + "=([^&#]*)");
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(masterUrl);
List<String> paramList = new ArrayList<String>();
if (m.find()) {
String param = m.group();
if(param != null){
String[] multiParamArr = null;
if(param.indexOf("^") != -1){
multiParamArr = param.split("\\^");
}else{
multiParamArr = new String[1];
multiParamArr[0] = param;
}
if(multiParamArr != null && multiParamArr .length > 0){
Pattern refinePattern = null;
Matcher refineMatcher = null;
String paramKeyy = null;
String paramVal = null;
HashMap<String,List<String>> ParamMap = new HashMap<String,List<String>>();
List<String list = new ArrayList<String>();
for(int i=0;i<multiParamArr.length;i++){
String[] multiParam = null;
String patternKey = "^[^\\~]*";
refinePattern = Pattern.compile(patternKey);
refineMatcher = refinePattern.matcher(multiRefineArr[i]);
if(refineMatcher.find()){
paramKey = refineMatcher.group();
if(paramKey.indexOf("=") !=-1){
patternKey = patternKey.substring(patternKey.indexOf("=")+1);
}
if(paramKey.indexOf("{") !=-1){
patternKey = patternKey.substring(patternKey.indexOf("=")+1,patternKey.indexOf("{"));
}
}
if(multiParamArr[i].indexOf("|") != -1){
multiParam = multiParamArr[i].split("\\|");
int startIndex;
int endIndex;
for(int j=0;j<multiParam.length;j++){
startIndex = 0;
endIndex = 0;
ifmultiParamArr[j].indexOf("[") > -1){
startIndex = multiParamArr[j].indexOf("[")+1;
}
ifmultiParamArr[j].indexOf("]") > -1){
endIndex = multiParamArr[j].indexOf("]");
}else{
endIndex = multiParamArr[j].length();
}
paramVal = multiParamArr[j].substring(startIndex,endIndex);
}
}else{
paramVal = multiParamArr[i].substring(multiParamArr[i].indexOfmultiParamArr[i].indexOf("]"));
}
list.add(paramVal);
}
paramMap.put((paramKey,list);
}
}
String textPatt=“params”;
String key=textPatt.replace(“/[\\[]”,“\\[”)。replace(“/[\\]]”,“\\]”);
字符串模式=新字符串(“[\?&]”+key+“=([^&]*)”;
Pattern p=Pattern.compile(Pattern);
Matcher m=p.Matcher(masterUrl);
List paramList=new ArrayList();
if(m.find()){
字符串参数=m.group();
如果(参数!=null){
字符串[]multiParamArr=null;
if(参数indexOf(“^”)!=-1){
multiParamArr=param.split(\\^);
}否则{
multiParamArr=新字符串[1];
multiParamArr[0]=参数;
}
if(multiParamArr!=null&&multiParamArr.length>0){
Pattern=null;
匹配器优化匹配器=null;
字符串paramKeyy=null;
字符串paramVal=null;
HashMap ParamMap=新HashMap();
List不需要创建复杂的正则表达式并对其进行维护,您可以通过以下几个步骤以更简单、更易读的方式完成:
在^
现在您有了一个字符串数组,每个字符串都包含一个参数及其值
在~
上拆分每个字符串-您将得到一个包含两个字符串的数组,从第一个字符串中提取Param1
(Param2
等)
从第二个开始,您可以通过在上拆分来提取值列表
|
(管道)
显示您解决此问题的尝试。请解释您已经尝试了什么,尝试时发生了什么,以及这与您希望发生的情况有何不同。她就是我正在尝试执行的代码。我添加了我的代码。我希望通过拆分和子字符串函数的正则表达式索引来实现这一点
String textPatt = "params";
String key = textPatt.replace("/[\\[]/", "\\[").replace("/[\\]]/", "\\]");
String pattern = new String("[\\?&]" + key + "=([^&#]*)");
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(masterUrl);
List<String> paramList = new ArrayList<String>();
if (m.find()) {
String param = m.group();
if(param != null){
String[] multiParamArr = null;
if(param.indexOf("^") != -1){
multiParamArr = param.split("\\^");
}else{
multiParamArr = new String[1];
multiParamArr[0] = param;
}
if(multiParamArr != null && multiParamArr .length > 0){
Pattern refinePattern = null;
Matcher refineMatcher = null;
String paramKeyy = null;
String paramVal = null;
HashMap<String,List<String>> ParamMap = new HashMap<String,List<String>>();
List<String list = new ArrayList<String>();
for(int i=0;i<multiParamArr.length;i++){
String[] multiParam = null;
String patternKey = "^[^\\~]*";
refinePattern = Pattern.compile(patternKey);
refineMatcher = refinePattern.matcher(multiRefineArr[i]);
if(refineMatcher.find()){
paramKey = refineMatcher.group();
if(paramKey.indexOf("=") !=-1){
patternKey = patternKey.substring(patternKey.indexOf("=")+1);
}
if(paramKey.indexOf("{") !=-1){
patternKey = patternKey.substring(patternKey.indexOf("=")+1,patternKey.indexOf("{"));
}
}
if(multiParamArr[i].indexOf("|") != -1){
multiParam = multiParamArr[i].split("\\|");
int startIndex;
int endIndex;
for(int j=0;j<multiParam.length;j++){
startIndex = 0;
endIndex = 0;
ifmultiParamArr[j].indexOf("[") > -1){
startIndex = multiParamArr[j].indexOf("[")+1;
}
ifmultiParamArr[j].indexOf("]") > -1){
endIndex = multiParamArr[j].indexOf("]");
}else{
endIndex = multiParamArr[j].length();
}
paramVal = multiParamArr[j].substring(startIndex,endIndex);
}
}else{
paramVal = multiParamArr[i].substring(multiParamArr[i].indexOfmultiParamArr[i].indexOf("]"));
}
list.add(paramVal);
}
paramMap.put((paramKey,list);
}
}