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Java 该应用程序没有';开始_Java_Android_Xml - Fatal编程技术网

Java 该应用程序没有';开始

Java 该应用程序没有';开始,java,android,xml,Java,Android,Xml,我想做一个新的编辑文本,当我点击按钮时,它一直崩溃,我不知道为什么?(我对这个很陌生) 有人知道我做错了什么吗?你忘了绑定你的addLayout 试试这个 @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); addButton = (Button)

我想做一个新的编辑文本,当我点击按钮时,它一直崩溃,我不知道为什么?(我对这个很陌生)


有人知道我做错了什么吗?

你忘了绑定你的
addLayout

试试这个

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    addButton = (Button) findViewById(R.id.button);

    // bind your LinearLayout here 
    addLayout = (LinearLayout) findViewById(R.id.addLayout);

    addButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            final LayoutParams params = new LayoutParams(MATCH_PARENT, MATCH_PARENT);
            EditText editText = new EditText(getApplicationContext());
            editText.setLayoutParams(params);
            addLayout.addView(editText);


        }
    });
}

汉克斯的人在哪!愚蠢的错误XD@blokhunt很乐意帮忙you@blokhunt您可以通过单击勾号接受此ans
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    addButton = (Button) findViewById(R.id.button);

    // bind your LinearLayout here 
    addLayout = (LinearLayout) findViewById(R.id.addLayout);

    addButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            final LayoutParams params = new LayoutParams(MATCH_PARENT, MATCH_PARENT);
            EditText editText = new EditText(getApplicationContext());
            editText.setLayoutParams(params);
            addLayout.addView(editText);


        }
    });
}