Java 该应用程序没有';开始
我想做一个新的编辑文本,当我点击按钮时,它一直崩溃,我不知道为什么?(我对这个很陌生)Java 该应用程序没有';开始,java,android,xml,Java,Android,Xml,我想做一个新的编辑文本,当我点击按钮时,它一直崩溃,我不知道为什么?(我对这个很陌生) 有人知道我做错了什么吗?你忘了绑定你的addLayout 试试这个 @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); addButton = (Button)
有人知道我做错了什么吗?你忘了绑定你的
addLayout
试试这个
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
addButton = (Button) findViewById(R.id.button);
// bind your LinearLayout here
addLayout = (LinearLayout) findViewById(R.id.addLayout);
addButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final LayoutParams params = new LayoutParams(MATCH_PARENT, MATCH_PARENT);
EditText editText = new EditText(getApplicationContext());
editText.setLayoutParams(params);
addLayout.addView(editText);
}
});
}
汉克斯的人在哪!愚蠢的错误XD@blokhunt很乐意帮忙you@blokhunt您可以通过单击勾号接受此ans
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
addButton = (Button) findViewById(R.id.button);
// bind your LinearLayout here
addLayout = (LinearLayout) findViewById(R.id.addLayout);
addButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final LayoutParams params = new LayoutParams(MATCH_PARENT, MATCH_PARENT);
EditText editText = new EditText(getApplicationContext());
editText.setLayoutParams(params);
addLayout.addView(editText);
}
});
}