Java 为什么我的HTTP POST请求不发送到我的网页？_Java_Php

Java 为什么我的HTTP POST请求不发送到我的网页？

java php

Java 为什么我的HTTP POST请求不发送到我的网页？,java,php,Java,Php,我在这里和整个互联网上看了很多其他的帖子，我似乎无法解决这个问题因此，我基本上编写了以下Java代码： public void sendReport(CommandSender sender, Player target, String reason) { HttpURLConnection connectionStandard = null; String email = config.getString("rp.site.email"); String passwo

我在这里和整个互联网上看了很多其他的帖子，我似乎无法解决这个问题

因此，我基本上编写了以下Java代码：

public void sendReport(CommandSender sender, Player target, String reason)
{
    HttpURLConnection connectionStandard = null;
    String email = config.getString("rp.site.email");
    String password = config.getString("rp.site.password");
    String senderName = sender.getName();
    String targetName = target.getDisplayName();
    String reasonString = reason;

    try
    {

        URL url = new URL("http://www.website.net/folder/connect.php");    
        HttpURLConnection request = (HttpURLConnection)url.openConnection();
        request.setRequestProperty("Content-type","application/x-www-form-urlencoded");
        request.setRequestMethod("POST");
        request.setDoOutput(true);
        OutputStreamWriter post = new OutputStreamWriter(request.getOutputStream());
        String data = URLEncoder.encode("email", "UTF-8") + "=" + URLEncoder.encode(email.toString(), "UTF-8");
        data += "&" + URLEncoder.encode("password", "UTF-8") + "=" + URLEncoder.encode(password.toString(), "UTF-8");
        data += "&" + URLEncoder.encode("reporter", "UTF-8") + "=" + URLEncoder.encode(senderName, "UTF-8");
        data += "&" + URLEncoder.encode("reported", "UTF-8") + "=" + URLEncoder.encode(targetName, "UTF-8");
        data += "&" + URLEncoder.encode("reason", "UTF-8") + "=" + URLEncoder.encode(reasonString, "UTF-8");
        post.write(data);
        post.flush();
    } catch (MalformedURLException e)
    {
        e.printStackTrace();
    } catch (IOException e)
    {
        e.printStackTrace();
    } finally
    {
        if(null != connectionStandard)
        {
            connectionStandard.disconnect();
        }
    }
}

基本上，我的php代码如下所示：

<?php

 require_once "db.php";

 $reporter->startSecureSession();

 foreach ($_POST as $post => $value) {
  $post = strip_tags($post);
  $value = strip_tags($value);
 }

 if(!(isset($_POST['email'])) or (!isset($_POST['password'])) or (!isset($_POST['reporter'])) or (!isset($_POST['reported'])) or (!isset($_POST['reason']))) {
  exit("Invalid Request");
 }

 $password = hash("sha512", $_POST['password']);

 $reporter->login(array("email" => $_POST['email'], "password" => $password), "plugin");
 if($reporter->validateClient()) {

  $reporter->sendReport($_POST);
  header("Location: logout.php");
  exit();

 } else {
  exit();
 }

?>

当我通过chrome将我的详细信息发送到网页时，它会工作并将内容发送到我的数据库，但当我通过发送请求的命令在bukkit服务器上执行此操作时，它不会：/

感谢您的帮助：）

好的，从URLConnection的javadoc：

1）连接对象是通过调用openConnection方法创建的在URL上

2）设置参数和常规请求属性如下所示操纵

3）与远程对象的实际连接是使用连接方法

4）远程对象变为可用。标题可以访问远程对象的字段和内容

您似乎没有调用

URLConnection#connect

那么，从URLConnection的javadoc：