Java Quartz计划程序无法获取JNDI DB资源,但仍将启动
我正在使用QuartzInitializerListener初始化Tomcat8中的Quartz调度程序 当Quartz无法连接到my DB(JNDI资源)时:Java Quartz计划程序无法获取JNDI DB资源,但仍将启动,java,tomcat,jdbc,quartz-scheduler,jndi,Java,Tomcat,Jdbc,Quartz Scheduler,Jndi,我正在使用QuartzInitializerListener初始化Tomcat8中的Quartz调度程序 当Quartz无法连接到my DB(JNDI资源)时: 15-Dec-2014 09:26:58.201信息[http-nio-8080-exec-10]org.apache.catalina.startup.HostConfig.deployDirectory部署web应用程序目录/home/../org.quartz.schedulerConfigeException:作业恢复期间发生故
15-Dec-2014 09:26:58.201信息[http-nio-8080-exec-10]org.apache.catalina.startup.HostConfig.deployDirectory部署web应用程序目录/home/../org.quartz.schedulerConfigeException:作业恢复期间发生故障。[请参阅嵌套异常:org.quartz.JobPersistenceException:未能从数据源“DBConnectionPool”获取DB连接:java.sql.SQLException:无法通过JNDI url“java:comp/env/jdbc/DBConnectionPool”检索数据源java.sql.SQLException:无法创建PoolableConnectionFactory(通信链接失败)
根据quartz.propertiesn,它无论如何都会启动。它没有做任何事情……但如果发生这种情况,我希望quartz停止
我怎样才能做到这一点
问候
Sebastian您可以像这样使用自定义类,而不是使用quartzlistner。 将其用作满足您需求的框架
@WebServlet(value="/QuartzTest",loadOnStartup=1)
public class QuartzInit extends HttpServlet {
private static final long serialVersionUID = 1L;
public static int count=0;
/**
* @see HttpServlet#HttpServlet()
*/
public QuartzInit() {
super();
// TODO Auto-generated constructor stub
try {
System.out.println("TRying to start Quartz");
JobDetail job = JobBuilder.newJob(AppCheckerJob.class)
.withIdentity("AppCrawlerJob", "InfraStatus_Group").build();
JobDetail job_email = JobBuilder.newJob(EmailJob.class)
.withIdentity("AppCrawlerEmailJob", "InfraStatus_Group").build();
Trigger trigger = TriggerBuilder
.newTrigger()
.withIdentity("AppCrawlerJobTRigger", "InfraStatus_Group")
.withSchedule(
CronScheduleBuilder.cronSchedule("0 /15 * * * ?")
).build();
Trigger trigger_email = TriggerBuilder
.newTrigger()
.withIdentity("AppCrawlerEmailJobTRigger", "InfraStatus_Group")
.withSchedule(
CronScheduleBuilder.dailyAtHourAndMinute(13,16)
).build();
// schedule it
Scheduler scheduler = new StdSchedulerFactory().getScheduler();
scheduler.start();
//if (sched.checkExists(job.getKey())) {sched.rescheduleJob(trigger.getKey(), trigger); } else {sched.scheduleJob(job, trigger); }
if(scheduler.checkExists(job.getKey())){
System.out.println("deleting old job netry");
scheduler.deleteJob(job.getKey());
//scheduler.rescheduleJob(trigger.getKey(), trigger);
}
if(scheduler.checkExists(job_email.getKey())){
System.out.println("deleting old email job netry");
scheduler.deleteJob(job_email.getKey());
//scheduler.rescheduleJob(trigger.getKey(), trigger);
}
scheduler.scheduleJob(job, trigger);
scheduler.scheduleJob(job_email, trigger_email);
} catch (Exception se) {
se.printStackTrace();
throw new RuntimeException("Error while initializing quartz!!!");
}
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
您希望quartz停止或停止整个应用程序stop@dev这两个选项对我来说都是可以的。如果有任何选项来处理QuartzInitializerListener的错误,它也将是合适的。这似乎更像是我的一个解决方法。是否有一个选项来改变quartz的行为?quartz有许多未知的行为,这就是为什么我总是初始化它我自己对quartz进行了序列化。我希望你能找到一些处理它的标准方法。几分钟前,我终于在网上找到了一个解决方案:你可以使用调度程序ListenerThank获取信息,我也会尝试使用它。