不断获得;java.lang.IllegalArgumentException:没有为该名称定义查询;即使我有一个合适的@NamedQuery名称
我有HibernateJPA应用程序。我在DAO类的函数中不断得到“java.lang.IllegalArgumentException:没有为该名称[Singer.findAll]定义查询”,即使我在@NamedQuery中正确定义了该名称。这是我的实体类不断获得;java.lang.IllegalArgumentException:没有为该名称定义查询;即使我有一个合适的@NamedQuery名称,java,hibernate,jpa,Java,Hibernate,Jpa,我有HibernateJPA应用程序。我在DAO类的函数中不断得到“java.lang.IllegalArgumentException:没有为该名称[Singer.findAll]定义查询”,即使我在@NamedQuery中正确定义了该名称。这是我的实体类 package ch8.entities; import javax.persistence.*; import java.io.Serializable; import java.util.Date; import java.util.
package ch8.entities;
import javax.persistence.*;
import java.io.Serializable;
import java.util.Date;
import java.util.HashSet;
import java.util.Set;
@Entity
@Table(name = "singer")
@NamedQueries({
@NamedQuery(name = Singer.FIND_BY_ID,
query = "select distinct s from Singer s "
+ "left join fetch s.albums a "
+ "left join fetch s.instruments i "
+ "where s.id = :id"),
@NamedQuery(name = Singer.FIND_ALL_WITH_ALBUM,
query = "select distinct s from Singer s "
+ "left join fetch s.albums a "
+ "left join fetch s.instruments i"),
@NamedQuery(name = Singer.FIND_ALL,
query = "select s from Singer s")
})
@SqlResultSetMapping(name = "singerResult",
entities = @EntityResult(entityClass = Singer.class))
public class Singer implements Serializable {
private Long id;
private String firstName;
private String lastName;
private Date birthDate;
private Long version;
private Set<Album> albums = new HashSet<>();
private Set<Instrument> instruments = new HashSet<>();
public static final String FIND_ALL = "Singer.findAll";
public static final String FIND_BY_ID = "Singer.findById";
public static final String FIND_ALL_WITH_ALBUM = "Singer.findAllWithAlbum";
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
@Column(name = "FIRST_NAME")
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
@Column(name = "LAST_NAME")
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Temporal(TemporalType.DATE)
@Column(name = "BIRTH_DATE")
public Date getBirthDate() {
return birthDate;
}
public void setBirthDate(Date birthDate) {
this.birthDate = birthDate;
}
@Version
@Column(name = "VERSION")
public Long getVersion() {
return version;
}
public void setVersion(Long version) {
this.version = version;
}
@OneToMany(mappedBy = "singer", cascade = CascadeType.ALL, orphanRemoval = true)
public Set<Album> getAlbums() {
return albums;
}
public void setAlbums(Set<Album> albums) {
this.albums = albums;
}
@ManyToMany
@JoinTable(name = "singer_instrument",
joinColumns = @JoinColumn(name = "SINGER_ID"),
inverseJoinColumns = @JoinColumn(name = "INSTRUMENT_ID"))
public Set<Instrument> getInstruments() {
return instruments;
}
public void setInstruments(Set<Instrument> instruments) {
this.instruments = instruments;
}
@Override
public String toString () {
return "Singer - Id: " + id + ", First name: "
+ firstName + ", Last name: " + lastName
+ ", Birthday: " + birthDate;
}
public boolean addAlbum(Album album) {
if (albums == null) {
albums = new HashSet<Album>();
albums.add(album);
return true;
}
if (albums.contains(album))
return false;
albums.add(album);
return true;
}
public boolean removeAlbum(Album album) {
if (album == null)
return false;
if (!albums.contains(album))
return false;
albums.remove(album);
return true;
}
}
包ch8.1;
导入javax.persistence.*;
导入java.io.Serializable;
导入java.util.Date;
导入java.util.HashSet;
导入java.util.Set;
@实体
@表(name=“singer”)
@命名查询({
@NamedQuery(name=Singer.FIND_BY_ID,
query=“从Singer s中选择不同的s”
+“左加入获取s.albums a”
+“左连接获取s.i”
+“其中s.id=:id”),
@NamedQuery(name=Singer.FIND_ALL_WITH_相册,
query=“从Singer s中选择不同的s”
+“左加入获取s.albums a”
+“左联取s.i”),
@NamedQuery(name=Singer.FIND_ALL,
query=“从Singer s中选择s”)
})
@SQLResultsMapping(name=“singerResult”,
entities=@EntityResult(entityClass=Singer.class))
公共类Singer实现了可序列化{
私人长id;
私有字符串名;
私有字符串lastName;
私人生日;
私人长版;
私有集相册=新HashSet();
私有集合工具=新HashSet();
公共静态最终字符串FIND_ALL=“Singer.findAll”;
公共静态最终字符串FIND_BY_ID=“Singer.findById”;
public static final String FIND_ALL_WITH_ALBUM=“Singer.findAllWithAlbum”;
@身份证
@GeneratedValue(策略=GenerationType.IDENTITY)
@列(name=“ID”)
公共长getId(){
返回id;
}
公共无效集合id(长id){
this.id=id;
}
@列(name=“FIRST_name”)
公共字符串getFirstName(){
返回名字;
}
public void setFirstName(字符串firstName){
this.firstName=firstName;
}
@列(name=“LAST_name”)
公共字符串getLastName(){
返回姓氏;
}
public void setLastName(字符串lastName){
this.lastName=lastName;
}
@时态(TemporalType.DATE)
@列(name=“出生日期”)
公共日期getBirthDate(){
返回出生日期;
}
公共无效设置出生日期(日期出生日期){
this.birthDate=生日;
}
@版本
@列(name=“VERSION”)
公共长getVersion(){
返回版本;
}
公共版本(长版本){
this.version=版本;
}
@OneToMany(mappedBy=“singer”,cascade=CascadeType.ALL,orphan=true)
公共集getAlbums(){
归还相册;
}
公共无效设置相册(设置相册){
this.albums=相册;
}
@许多
@可接合(name=“singer_instrument”,
joinColumns=@JoinColumn(name=“SINGER\u ID”),
inverseJoinColumns=@JoinColumn(name=“INSTRUMENT\u ID”))
公共集合仪表(){
返回仪器;
}
公用仪器(成套仪器){
这个。仪器=仪器;
}
@凌驾
公共字符串toString(){
返回“Singer-Id:+Id+”,名字:
+姓氏:“+lastName”
+,生日:“+生日;
}
公共布尔添加相册(相册){
如果(相册==null){
albums=新的HashSet();
相册。添加(相册);
返回true;
}
if(相册包含(相册))
返回false;
相册。添加(相册);
返回true;
}
公共布尔removeAlbum(相册){
如果(相册==null)
返回false;
如果(!albums.contains(album))
返回false;
相册。删除(相册);
返回true;
}
}
和刀类
package ch8.dao;
import ch8.entities.Singer;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import java.util.Collection;
@Transactional
@Repository("singerDao")
public class SingerDao implements Dao<Singer> {
@PersistenceContext
private EntityManager entityManager;
...some other functions...
@Override
@Transactional(readOnly = true)
public Collection<Singer> findAll() {
return entityManager.createNamedQuery(Singer.FIND_ALL, Singer.class).getResultList();
}
...some other functions...
}
包ch8.dao;
导入ch8.entities.Singer;
导入org.slf4j.Logger;
导入org.slf4j.LoggerFactory;
导入org.springframework.stereotype.Repository;
导入org.springframework.transaction.annotation.Transactional;
导入javax.persistence.EntityManager;
导入javax.persistence.PersistenceContext;
导入java.util.Collection;
@交易的
@存储库(“singerDao”)
公共类SingerDao实现Dao{
@持久上下文
私人实体管理者实体管理者;
…其他一些功能。。。
@凌驾
@事务(只读=真)
公共集合findAll(){
返回entityManager.createNamedQuery(Singer.FIND_ALL,Singer.class).getResultList();
}
…其他一些功能。。。
}
我认为这可能与类映射有关,因为常规的createQuery(字符串,类)不起作用。多亏了JLazar0的建议,我找到了解决问题的方法。和往常一样,问题不是因为错误的逻辑、错误的配置或坚持。我之所以一直得到“没有为该名称定义查询”,尽管一切似乎都很好,是因为我在LocalContainerEntityManagerFactoryBean.setPackagesToScan()中有错误的包名。在方法参数中进行了一些小的修改之后,我的代码通过了所有的测试。
无论如何,感谢所有试图提供帮助的人首先,一切似乎都是正确的,您能否通过在命名查询定义的名称和createNamedQuery方法中都添加字符串“test”来执行测试?如果我理解正确,您所说的是这样的
@NamedQuery(name=“test”,query=“从Singer s中选择s”)
和返回entityManager.createNamedQuery(“test”,Singer.class).getResultList()
在本例中,结果是相同的(java.lang.IllegalArgumentException:No query defined for the name[test]),在persistence.xml中设置事务类型