Java 检查它是否可被某个数字整除，并将其除

你好！我有一个代码，可以找到一个点的轨迹方程。我可以让我的输出看看它是否可以被某个数字整除，如果可以，我可以把它除以吗

这是我的密码：

    private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         

        //DecimalFormat fmt = new DecimalFormat("+##");
        int x1 , y1, x2, y2,
            inverted_x1, inverted_y1, inverted_x2, inverted_y2,
            x1Times2, x2Times2, y1Times2, y2Times2,
            x1raised, y1raised, x2raised, y2raised,
            computeX, computeY, computeS,
            x2inverted, y2inverted, invertedx2times2, invertedy2times2;

        try{
            x1 = Integer.parseInt(jTextField1.getText());
            y1 = Integer.parseInt(jTextField2.getText());
            x2 = Integer.parseInt(jTextField3.getText());
            y2 = Integer.parseInt(jTextField4.getText());           

            int[] array = new int[4];
                  array[0] = x1;
                  array[1] = x2;
                  array[2] = y1;
                  array[3] = y2;

            inverted_x1 = x1 *= -1;
            inverted_y1 = y1 *= -1;
            inverted_x2 = x2 *= -1;      
            inverted_y2 = y2 *= -1;                                 

            jTextField5.setText("= (x" + formatSign(inverted_x1)  + ")² + (y" + formatSign(inverted_y1) + ")²" 
                    + " = (x" + formatSign(inverted_x2) + ")² + (y" + formatSign(inverted_y2) + ")²" );

            x1Times2 = inverted_x1*2;
            y1Times2 = inverted_y1*2;           
            x2Times2 = inverted_x2*2;
            y2Times2 = inverted_y2*2;                                   
            x1raised = inverted_x1*inverted_x1;
            y1raised = inverted_y1*inverted_y1;         
            x2raised = inverted_x2*inverted_x2;
            y2raised = inverted_y2*inverted_y2;

            jTextField9.setText("= x²" + formatSign(x1Times2) + "x" + formatSign(x1raised) + "+y²" + formatSign(y1Times2)
                    + "y" + formatSign(y1raised) + "= x²" + formatSign(x2Times2) + "x" + formatSign(x2raised) + "+y²"
                    + formatSign(y2Times2) + "y" + formatSign(y2raised));            

            x2inverted = x2raised *= -1;
            y2inverted = y2raised *= -1;
            invertedx2times2 = x2Times2 *= -1;
            invertedy2times2 = y2Times2 *= -1;
            computeX = x1Times2 + invertedx2times2;
            computeY = y1Times2 + invertedy2times2;
            computeS = x2inverted + y2inverted + x1raised + y1raised;

            jTextField17.setText("= " + formatSign(computeX) + "x" + formatSign(computeY) + "y" + formatSign(computeS) + "=0");                                                                                 

            XYLineChart_AWT chart = new XYLineChart_AWT("Locus of Point Graph", "", array);
            chart.pack( );          
            RefineryUtilities.centerFrameOnScreen( chart );          
            chart.setVisible( true );             

        }catch(Exception e){
            JOptionPane.showMessageDialog(null, "Please fill necessary inputs");
        }

以下是我的示例输出：

红色是我的输出，所有变量都可以被6整除。我可以检查它是否可以被某个数字整除，如果可以，我可以把它除吗

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提前谢谢你

是，您要找的是%运算符，它将给您一个余数。
创建一个接受所有3个数字的方法，并检查id GCD（最大公约数）

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我认为在这种情况下，

netbeans

标记不会引起任何兴趣。

private int gcd(int xcoef,int ycoef, int constant) {
    int gcd = 1;
    for(int i=2; i<=xcoef && i<=ycoef && i<=constant;i++) {
        if(xcoef%i==0 && ycoef%i==0 && constant%i==0) {
            gcd = i;
        }
    }
    return gcd;
}

int gcd = gcd(computeX, computeY, computeS);
jTextField17.setText("= " + formatSign(computeX/lcm) + "x" + formatSign(computeY/lcm) + "y" + formatSign(computeS/lcm) + "=0");