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Java edittext在输入类型android studio中设置有限字符_Java_Android - Fatal编程技术网

Java edittext在输入类型android studio中设置有限字符

Java edittext在输入类型android studio中设置有限字符,java,android,Java,Android,我希望edittext只能以编程方式输入这些字符“0123456789ABCDEF” numOriginal.setText(""); base = Integer.parseInt(selectorBaseOriginal.getSelectedItem().toString()); String digits =""; for(int i=0;i<base;i++){ digits+=digitos.charAt(i); }

我希望edittext只能以编程方式输入这些字符“0123456789ABCDEF”

    numOriginal.setText("");
    base = Integer.parseInt(selectorBaseOriginal.getSelectedItem().toString());
    String digits ="";
    for(int i=0;i<base;i++){
       digits+=digitos.charAt(i);
    }
    if(base<=10){
        //numbers
        numOriginal.setKeyListener(DigitsKeyListener.getInstance(digits));
    }else{
        //i want numbers an characters "0123456789ABCDEF"
    }
numOriginal.setText(“”);
base=Integer.parseInt(selectorBaseOriginal.getSelectedItem().toString());
字符串数字=”;

对于(inti=0;i我想这个问题的答案可以在这里找到

只需对您案例的代码进行一些调整:

 InputFilter filter = new InputFilter() {
            public CharSequence filter(CharSequence source, int start, int end,
                    Spanned dest, int dstart, int dend) {
                for (int i = start; i < end; i++) {
                    if (!"0123456789ABCDEF".contains(source.charAt(i))) {
                        Toast.makeText(context,"Invalid Input",Toast.LENGTH_SHORT).show();
                        return "";
                    }
                }
                return null;
            }

        };

 numOriginal.setFilters(new InputFilter[] { filter });
InputFilter过滤器=新的InputFilter(){
公共CharSequence筛选器(CharSequence源、int开始、int结束、,
跨越目的地、内部数据起点、内部数据起点){
for(int i=start;i