Java 没有得到想要的结果，我很困

我遇到了一个问题，它没有像应该的那样打印出来，并且无法弄清楚它是什么

现在我的代码正在打印以下内容：

***#

***##

***###

当它应该像这样打印出来时：

***#

**##

*###

以下是我目前的代码：

import static java.lang.System.*;

public class Box
{
  private int size;

public Box()
{




}

public Box(int count)
{
    size = count;
}

public void setSize(int count)
{
    size = count;
}

public int getSize()
{
    return size;
}

public String toString()
{
    String output="";
    for(int i = 1; i <= size; i++)
    {
        for(int k = size; k >0; k--)
        {
            output += "*";
        }
        for(int j = size; j >size-i; j--)
        {
            output += "#";
        }
        output += "\n"; 
    }
    
    return output;
}
}

---

我的想法是，我很快就能得到它，但就是不知道是什么。

（i i＝1；我尝试使用描述性变量名。而不是i，j，k考虑行、COL等），我的实验表与这个实验室相关联的是什么，这就是原因。我不确定行、COL等在这个实验室中应用得很好，如果有一种方法，用2的方法在主环内嵌套，只需循环。已将此版本添加到解决方案中。要查看发生的情况有点困难，但会为每个项目保存一个条件。
    for(int i = 1; i <= size; i++)
    {
        // Using a single for to make sure we don't create too many items.
        // Also note the +1. It seems that when size = 3, you want 4 chars
        // per line, so this take that extra char into account.
        for(int k = 0; k < size + 1; k++)
        {
            // Use an if to decide if we print * or #.
                // As 'i' gets bigger, we need to put less *, so
                // we subtract 'i' from the total size. This tells
                // when the midpoint has passed and we should start
                // writing #s.
            if (k <= size - i)
                output += "*";
            else
                output += "#";
        }

        output += "\n"; 
    }

    for(int i = 1; i <= size; i++)
    {
        // Using a single for to make sure we don't create too many items.
        // Also note the +1. It seems that when size = 3, you want 4 chars
        // per line, so this take that extra char into account.
        for(int k = 0; k < size + 1; k++)
        {
            // Use an if to decide if we print * or #.
                // As 'i' gets bigger, we need to put less *, so
                // we subtract 'i' from the total size. This tells
                // when the midpoint has passed and we should start
                // writing #s.
            if (k <= size - i)
                output += "*";
            else
                output += "#";
        }

        output += "\n"; 
    }

    for(int i = 1; i <= size; i++)
    {
        // Adds a number of * inversely proportional to the current
        // value of 'i'.
        for(int k = 0; k <= size - i; k++)
        {
            output += "*";
        }

        // Start adding # where we stopped the *.
        for(int j = size - i; j < size; j++)
        {
            output += "#";
        }

        output += "\n"; 
    }