Java 弹簧3安全j_弹簧安全检查

我正在努力学习spring安全性是如何工作的，所以我下载了一些示例项目，然后我尝试在我的项目中实现该解决方案。但是当我尝试登录时，我得到了

404

错误，并且在地址栏中出现了

http://localhost:8080/fit/j_spring_security_check

。我试图在这里研究类似的问题，但我没有意识到，如何将其应用到我的项目中。如果有更有经验的人能帮助我，我会非常感激的

我的应用程序结构如下所示：

applicationContext.xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:security="http://www.springframework.org/schema/security"
   xsi:schemaLocation="
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<context:annotation-config/>

<context:component-scan base-package="cz.cvut.fit"/>

<import resource="classpath:applicationContext-security.xml"/>

</beans>

applicationContext-web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xmlns:mvc="http://www.springframework.org/schema/mvc"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:security="http://www.springframework.org/schema/security"
   xsi:schemaLocation="
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<context:annotation-config/>

<context:component-scan base-package="cz.cvut.fit" />

<mvc:annotation-driven />

<security:global-method-security jsr250-annotations="enabled"
                                 proxy-target-class="true"/>
</beans>

applicationContext-security.xml：

<beans xmlns:security="http://www.springframework.org/schema/security"
   xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://www.springframework.org/schema/beans
             http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
             http://www.springframework.org/schema/security
             http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<security:http pattern="/css/**" security="none"/>
<security:http pattern="/views/login.jsp*" security="none"/>
<security:http pattern="/views/denied.jsp" security="none"/>

<security:http auto-config="true" access-denied-page="/denied.jsp" servlet-api-provision="false">
    <security:intercept-url pattern="/views/login.jsp*" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
    <security:intercept-url pattern="/views/edit/**" access="ROLE_EDIT"/>
    <security:intercept-url pattern="/views/admin/**" access="ROLE_ADMIN"/>
    <security:intercept-url pattern="/**" access="ROLE_USER"/>
    <security:form-login login-page="/views/login.jsp" authentication-failure-url="/denied.jsp"
                         default-target-url="/home.jsp"/>
    <security:logout/>
</security:http>

<security:authentication-manager>
    <security:authentication-provider>
        <security:user-service>
            <security:user name="adam" password="adampassword" authorities="ROLE_USER"/>
            <security:user name="jane" password="janepassword" authorities="ROLE_USER, ROLE_ADMIN"/>
            <security:user name="sue" password="suepassword" authorities="ROLE_USER, ROLE_EDIT"/>
        </security:user-service>
    </security:authentication-provider>
</security:authentication-manager>

</beans>

---

您正在尝试根据网页的当前上下文路径验证uri。JSTL标记库可用于确保根据应用程序的上下文轻松生成正确的URL。如果希望快速实现，可以通过使用标记库来实现这一点。为此，您可以将jstl标记库添加到jsp的顶部：

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>

然后，您可以使用以下命令发布到登录servlet

<form action="<c:url value="/j_spring_security_check"></c:url>" method="post" role="form">

这样可以确保您始终将邮件发送到/j_spring_security_check

jstl的参考资料：

springSecurityFilterChain
org.springframework.web.filter.DelegatingFilterProxy
springSecurityFilterChain
/*

---

添加您的web.xml文件。它是springSecurityFilterChain的创建Bean。然后您得到响应。

路径

/j\u spring\u security\u check

在spring 4中已更改为

/login

，并在

用户名密码验证筛选器中进行处理

您可以在这里找到它的来源：
j\u spring\u security\u check
是一个Servlet，在这里进行实际身份验证，您必须将登录表单的操作映射到此Servlet。您是否在登录页面上执行此操作-
…
？请显示您的web.xml/j_spring_security_check URL必须由springSecurityFilterChain筛选器处理。是的，我是。。。但我不知道下一步该怎么做才能让它正常工作-/我假设web.xml的这部分就足够了：
springSecurityFilterChain org.springframework.web.filter.DelegatingFilterProxy springSecurityFilterChain/*
这是我的登录表单：
用户名：
密码：

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>
        org.springframework.web.filter.DelegatingFilterProxy
    </filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>