请在我的对话框中使用onkey/onclick侦听器更正我的Android Java代码

我正在触发一个密码验证对话框，但我不明白为什么输入错误的密码会导致异常。需要一些绝地大师来帮助这个学徒

@Override
private void LaunchPwdDialog(){
    LayoutInflater li = LayoutInflater.from(context);
    View promptsView = li.inflate(R.layout.prompts, null);
    AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(context);
    alertDialogBuilder.setView(promptsView);
    final EditText userInput = (EditText) promptsView.findViewById(R.id.edtPasswordInput);
    alertDialogBuilder
    .setCancelable(true)
    .setPositiveButton("Finish", 
    new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id){
        if (userInput.getText().toString().compareTo(strAdminPassword) == 0){
                disableKioskMode();
                    }
            else{
                Log.i(TAG, "Function LaunchPwdDialog - Admin password incorrect. User entered: " + edt.getText().toString());
                Toast.makeText(getBaseContext(), "Incorrect Password", Toast.LENGTH_SHORT).show();

            }
        }
    })
    .setNegativeButton("Cancel",
    new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int id){
                disableKioskMode();
                dialog.dismiss();
            }
        })
    .setOnKeyListener(new DialogInterface.OnKeyListener() {
            @Override 
            public boolean onKey(DialogInterface dialog, int keyCode, KeyEvent event){
                if (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)
                    if (userInput.getText().toString().compareTo(strAdminPassword) == 0)
                    {
                        disableKioskMode();
                        userInput.setText("");
                        dialog.dismiss();
                    }
                    else {
                        Log.i(TAG, "Function LaunchPwdDialog - Admin password incorrect. User entered: " + edt.getText().toString());
                        Toast.makeText(getBaseContext(), "Incorrect Password", Toast.LENGTH_SHORT).show();
                        if (CurrentAttempt % MaxAttempts == 0) {
                            Log.i(TAG, "You are unauthorised to access this feature.");
                            Toast.makeText(getBaseContext(), "You are unauthorised to access this feature.", Toast.LENGTH_SHORT).show();
                            finish();
                        }
                    }
                return false;
            }
        });
    AlertDialog alertDialog = alertDialogBuilder.create();
    alertDialog.show();
}

我已经让它在成功验证密码后成功地执行disableKioskMode（）函数，但是如果我没有输入任何内容或输入错误的密码，那么它就会崩溃。不确定这是否有帮助，但这里是日志：

06-01 05:55:24.910 12311 12311 D   AndroidRuntime com.androiddev.kiosk               Shutting down VM
06-01 05:55:24.910 12311 12311 W   dalvikvm com.androiddev.kiosk                     threadid=1: thread exiting with uncaught exception (group=0x41759c08)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               FATAL EXCEPTION: main
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               Process: com.androiddev.kiosk, PID: 12311
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               java.lang.NullPointerException
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at com.androiddev.kiosk.KioskLauncher$100000000.onClick(KioskLauncher.java:413)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at com.android.internal.app.AlertController$ButtonHandler.handleMessage(AlertController.java:170)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at android.os.Handler.dispatchMessage(Handler.java:102)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at android.os.Looper.loop(Looper.java:146)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at android.app.ActivityThread.main(ActivityThread.java:5653)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at java.lang.reflect.Method.invokeNative(Native Method)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at java.lang.reflect.Method.invoke(Method.java:515)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1291)
06-01 05:55:24.915 12311 12311 E   AndroidRuntime com.androiddev.kiosk               at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1107)

---

在对其进行任何操作之前，请检查

userInput.getText（）.toString（）

是否为空。

当用户输入错误的密码时，您尝试将以下变量记录到LogCat中

edt.getText().toString()

应该是吗

userInput.getText().toString()

---

如果您想记录用户输入的密码？

我在以前的编辑中确实有这样的密码。。当我输入了错误的密码时，崩溃就发生了。天哪，你是对的，我感到非常尴尬和羞愧，以至于我花了好几个小时都没有运气！我得停止用安卓平板电脑编码了！无法相信日志导致了异常！