使用GSON解析Java中的JSON文件
我试图用java中的GSON解析这个JSON文件,但遇到了一些困难使用GSON解析Java中的JSON文件,java,json,string,gson,Java,Json,String,Gson,我试图用java中的GSON解析这个JSON文件,但遇到了一些困难 {"group": [ { "name": "Team1 Student2", "email": "ctc-t1-s2", "contribution": { "score": 16.6, "comment": "From 'Team1 Student2' about 'Team1 Student2'\nAnd they said, \"You'll never get it done!
{"group": [
{
"name": "Team1 Student2",
"email": "ctc-t1-s2",
"contribution": {
"score": 16.6,
"comment": "From 'Team1 Student2' about 'Team1 Student2'\nAnd they said, \"You'll never get it done!\""
}
}
,{
"name": "Team1 Student4",
"email": "mmi-t1-s4",
"contribution": {
"score": 0.4,
"comment": "From 'Team1 Student2' about 'Team1 Student4'\nAnd they said, \"You'll never get it done!\""
}
}
,{
"name": "Team1 Student3",
"email": "pco-t1-s3",
"contribution": {
"score": 39.1,
"comment": "From 'Team1 Student2' about 'Team1 Student3'\nAnd they said, \"You'll never get it done!\""
}
}
,{
"name": "Team1 Student1",
"email": "eyr-t1-s1",
"contribution": {
"score": 23.9,
"comment": "From 'Team1 Student2' about 'Team1 Student1'\nAnd they said, \"You'll never get it done!\""
}
}],"confidential_comments": "That's all! It was \"fun\"! (said Team1 Student2)\nDon't forget: Bring your towel \\ the cake is a lie."}
现在我有三个班,其中一个是团体班:
public class Group {
private List<Student> group[];
public Group(List<Student> students[]){
this.group = students;
}
public void setStudents(List<Student> students[]) {
this.group = students;
}
public List<Student>[] getStudents() {
return group;
}
@Override
public String toString() {
return "Group{" +
"students=" + Arrays.toString(group) +
'}';
}
}
在我的主函数中,当我运行它时,我最终打印了一个空对象
Gson gson = new Gson();
JsonParser jsonParser = new JsonParser();
try(Reader reader = new FileReader("FILE PATH")) {
JsonElement jsonObject = jsonParser.parse((reader));
System.out.println(jsonObject);
Group students = gson.fromJson(jsonObject, Group.class);
System.out.println(students);
Student student = gson.fromJson(jsonObject, Student.class);
System.out.println(student);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
我想知道如何解析输入文件,以便将JSON字符串放入一个对象或对象列表中?很抱歉问了这么长的问题 我认为出现问题的地方是,在JSON
组中
已经是一个列表
,但您正在尝试从gson检索组对象。我认为您需要的是一个不同的对象,比如阅读器
或响应
,如下所示:
class Response {
private Group group;
}
然后做一些类似的事情:
Response response = gson.fromJson(jsonObject, Response.class);
Group = response.getGroup();
请注意,要使GSON正常工作,类中的字段名需要与JSON匹配。(因此sfu_电子邮件中的Student
应按照JSON阅读email
)
希望这能有所帮助,我想问题出在你的JSON组中
已经是一个列表
,但是你正在尝试从gson检索组对象。我认为您需要的是一个不同的对象,比如阅读器
或响应
,如下所示:
class Response {
private Group group;
}
然后做一些类似的事情:
Response response = gson.fromJson(jsonObject, Response.class);
Group = response.getGroup();
请注意,要使GSON正常工作,类中的字段名需要与JSON匹配。(因此sfu_电子邮件中的Student
应按照JSON阅读email
)
希望这有助于组
类包含列表
,再次无需在组
变量名称末尾添加[]
public class Group {
private List<Student> group;
public void setStudents(List<Student> students) {
this.group = students;
}
public List<Student> getStudents() {
return group;
}
@Override
public String toString() {
return "Group [group=" + group + "]";
}
}
尝试使用上述解决方案。组
类包含列表
,同样不需要在组
变量名称末尾添加[]
public class Group {
private List<Student> group;
public void setStudents(List<Student> students) {
this.group = students;
}
public List<Student> getStudents() {
return group;
}
@Override
public String toString() {
return "Group [group=" + group + "]";
}
}
尝试上述解决方案