Java Mapstruct 1.4.x-iterable到nonit。示例使用目标点运算符工作
我想采用这里的样品 不同的是,使用“myString”运算符而不是某些嵌套属性。给定示例,我希望得到“myString”作为结果,因此字符串将成为新的目标 但是,使用点运算符什么都不会发生。什么都不会发生意味着mapstruct只创建一个新的String实例,而没有iterable到noniterable的映射。这是一种期望的行为吗 如本文所述,示例(取自上述样本): 不打印任何内容,因为生成的代码如下所示:Java Mapstruct 1.4.x-iterable到nonit。示例使用目标点运算符工作,java,mapstruct,Java,Mapstruct,我想采用这里的样品 不同的是,使用“myString”运算符而不是某些嵌套属性。给定示例,我希望得到“myString”作为结果,因此字符串将成为新的目标 但是,使用点运算符什么都不会发生。什么都不会发生意味着mapstruct只创建一个新的String实例,而没有iterable到noniterable的映射。这是一种期望的行为吗 如本文所述,示例(取自上述样本): 不打印任何内容,因为生成的代码如下所示: @Generated( value = "org.mapstruc
@Generated(
value = "org.mapstruct.ap.MappingProcessor",
date = "2021-02-13T15:34:11+0100",
comments = "version: 1.4.2.Final, compiler: javac, environment: Java 11.0.5 (JetBrains s.r.o)"
)
public class SourceTargetMapperImpl implements SourceTargetMapper {
@Override
public String toTarget(Source s) {
if ( s == null ) {
return null;
}
String string = new String();
return string;
}
}
其他类保持原样
另一个例子: 嗨,菲利普,很抱歉迟到了。我想向你展示另一个对我不起作用的用例,或者正如我所期望的那样,使用“qualifiedBy”-阿曲布他。我遗漏了什么 班级地址:
public class Address {
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Address(String name) {
this.name = name;
}
private String name;
@Override
public String toString() {
return "Address{" +
"name='" + name + '\'' +
'}';
}
}
使用地址列表对客户进行分类:
public class CustomerManyAddresses {
public List<Address> getAddresses() {
return addresses;
}
public void setAddresses(List<Address> addresses) {
this.addresses = addresses;
}
private List<Address> addresses;
}
以及测试:
public class CustomerAddressMapperTest {
private AddressMapper addressMapper = Mappers.getMapper(AddressMapper.class);
@Test
public void testCustomerMapper() {
CustomerManyAddresses customerManyAddresses = new CustomerManyAddresses();
Address address1 = new Address("first");
Address address2 = new Address("second");
Address address3 = new Address("third");
customerManyAddresses.setAddresses(Arrays.asList(address1, address2, address3));
Address singleAddress = addressMapper.toSingle(customerManyAddresses);
System.out.println(singleAddress);
}
}
…它只打印新生成的地址,这里没有iterable到non iter。再次使用。生成的类:
@Generated(
value = "org.mapstruct.ap.MappingProcessor",
date = "2021-02-20T11:05:53+0100",
comments = "version: 1.4.2.Final, compiler: javac, environment: Java 11.0.5 (JetBrains s.r.o)"
)
public class AddressMapperImpl extends AddressMapper {
@Override
Address toSingle(CustomerManyAddresses customerManyAddresses) {
if ( customerManyAddresses == null ) {
return null;
}
String name = null;
Address address = new Address( name );
return address;
}
}
MapStruct不允许映射到
字符串
。当您使用target=“.”
时,您的意思是要将第一个元素的属性映射到目标的属性
您可以做的是将目标字符串包装到bean中,然后像那样进行映射
不过,我的建议是,当您只想取回字符串时,编写您自己的自定义方法。您能在这里提供一个问题示例吗?当然。我刚刚更改了上面提到的示例:将类型返回到字符串,将目标返回到.operator,源仍然是myIntegers。但我稍后会提供它……好的。它可以根据定义不允许?或根据“尚未实施”不允许?;))非常感谢。但是Filip,对于非字符串的对象,也会观察到相同的行为。如果目标是直接对象,则不会映射。将只会有一个新实例。因此,如果您将类型字符串替换为所需的对象类型,您将得到该类型的空对象…,我的意思是使用“.”运算符在默认情况下工作。但是,当使用namedBy时,它不适用。您可以确认或伪造此语句吗?请仔细考虑一下,在使用自定义映射方法时使用“.”运算符并没有真正意义。“”运算符用于告诉MapStruct如何进行映射,当您自己进行映射时,它不会带来太多价值不,我们彼此误解。我将在接下来的几个小时内提供另一个示例。
@Mapper(uses = IterableNonInterableUtil.class)
public abstract class AddressMapper {
@Mapping(target = ".", source = "addresses", qualifiedBy = FirstElement.class)
abstract Address toSingle(CustomerManyAddresses customerManyAddresses);
}
public class CustomerAddressMapperTest {
private AddressMapper addressMapper = Mappers.getMapper(AddressMapper.class);
@Test
public void testCustomerMapper() {
CustomerManyAddresses customerManyAddresses = new CustomerManyAddresses();
Address address1 = new Address("first");
Address address2 = new Address("second");
Address address3 = new Address("third");
customerManyAddresses.setAddresses(Arrays.asList(address1, address2, address3));
Address singleAddress = addressMapper.toSingle(customerManyAddresses);
System.out.println(singleAddress);
}
}
@Generated(
value = "org.mapstruct.ap.MappingProcessor",
date = "2021-02-20T11:05:53+0100",
comments = "version: 1.4.2.Final, compiler: javac, environment: Java 11.0.5 (JetBrains s.r.o)"
)
public class AddressMapperImpl extends AddressMapper {
@Override
Address toSingle(CustomerManyAddresses customerManyAddresses) {
if ( customerManyAddresses == null ) {
return null;
}
String name = null;
Address address = new Address( name );
return address;
}
}