Java 使用Joda Time获得平均时间

我使用一个Joda时间段对多个时间值求和。从00:00:00开始，我将每个时间量相加，以获得所有活动的总时间量。我想通过求和所有时间值得到的总时间除以总距离，得到每个测量单位的平均时间

代码：

输出：

    Orig Time: 00:00:00

    Run - 00:16:08 - 2.0 miles
    Adding Time: 00:16:08
    Altered Time: 00:16:08

    Run - 00:18:09 - 2.21 miles
    Adding Time: 00:34:17
    Altered Time: 00:34:17

    Run - 00:23:35 - 2.69 miles
    Adding Time: 00:57:52
    Altered Time: 00:57:52

    Run - 00:34:45 - 4.29 miles
    Adding Time: 00:91:97
    Altered Time: 01:32:37

    Run - 00:36:15 - 4.17 miles
    Adding Time: 01:68:52
    Altered Time: 02:08:52

    Run - 00:18:03 - 2.14 miles
    Adding Time: 02:26:55
    Altered Time: 02:26:55

    Run - 00:17:27 - 2.19 miles
    Adding Time: 02:43:82
    Altered Time: 02:44:22

    Run - 00:43:43 - 5.1 miles
    Adding Time: 02:87:65
    Altered Time: 03:28:05

    Distance: 24.79
    Final Time: 03:28:05

将最终时间03:28:05除以24.79得到单位平均时间的最佳方法是什么？

这里是我最后的答案：

  PeriodFormatterBuilder builder = new PeriodFormatterBuilder();

  PeriodFormatter formatter =
    builder.printZeroAlways()
      .minimumPrintedDigits(2)
      .appendHours()
      .appendSeparator(":")
      .appendMinutes()
      .appendSeparator(":")
      .appendSeconds()
      .toFormatter();

  String zero = "00:00:00";
  Period period = formatter.parsePeriod(zero);
  float total = 0;

  for (Activity temp : last7acts) {
    System.out.println(
      temp.getCatName() + " - " + temp.getTime()
      + " - " + temp.getDistance() + " " + temp.getUnits());
    total += temp.getDistance();
    period = period.plus(formatter.parsePeriod(temp.getTime()));
  }

  period = period.normalizedStandard(PeriodType.dayTime().withDaysRemoved());
  System.out.println("Final Distance: " + total);
  System.out.println("Final Time: " + formatter.print(period));

  long secs = period.toStandardDuration().getStandardSeconds();
  NumberFormat nf = NumberFormat.getInstance(Locale.getDefault());
  System.out.println(nf.format(secs / total) + " seconds/mile");

  long minutes = secs / 60;
  System.out.println(nf.format(minutes / total) + " minutes/mile");

---

看看这个循环有多短！不可变的

Period

类型通常是更好的选择，它提供了规范化功能，您需要并尝试以冗长的方式手动执行这些功能。

您的变量start是什么意思？哪种类型？将时间转换为秒除以你的英里数，你得到的是每英里多少秒？感谢gfgaxiola，这是一种选择，但很好奇是否有功能可以在不转换的情况下按时执行除法。显然不是。Meno-开始变量是可变周期类型。我用“00:00:00”时间初始化它，并用它将时间相加。

  PeriodFormatterBuilder builder = new PeriodFormatterBuilder();

  PeriodFormatter formatter =
    builder.printZeroAlways()
      .minimumPrintedDigits(2)
      .appendHours()
      .appendSeparator(":")
      .appendMinutes()
      .appendSeparator(":")
      .appendSeconds()
      .toFormatter();

  String zero = "00:00:00";
  Period period = formatter.parsePeriod(zero);
  float total = 0;

  for (Activity temp : last7acts) {
    System.out.println(
      temp.getCatName() + " - " + temp.getTime()
      + " - " + temp.getDistance() + " " + temp.getUnits());
    total += temp.getDistance();
    period = period.plus(formatter.parsePeriod(temp.getTime()));
  }

  period = period.normalizedStandard(PeriodType.dayTime().withDaysRemoved());
  System.out.println("Final Distance: " + total);
  System.out.println("Final Time: " + formatter.print(period));

  long secs = period.toStandardDuration().getStandardSeconds();
  NumberFormat nf = NumberFormat.getInstance(Locale.getDefault());
  System.out.println(nf.format(secs / total) + " seconds/mile");

  long minutes = secs / 60;
  System.out.println(nf.format(minutes / total) + " minutes/mile");