Java 使用jackson时registerModule代码应位于何处
这是我的测试代码Java 使用jackson时registerModule代码应位于何处,java,jackson,Java,Jackson,这是我的测试代码 DynaBean bean1 = new LazyDynaBean(); bean1.set("p1", 1); bean1.set("p2", 2); ObjectMapper mapper = new ObjectMapper(); try { LOGGER.error(mapper.writeValueAsString(bean1)); } catch (JsonProcessingException ex) { LOGGER.catching(ex);
DynaBean bean1 = new LazyDynaBean();
bean1.set("p1", 1);
bean1.set("p2", 2);
ObjectMapper mapper = new ObjectMapper();
try {
LOGGER.error(mapper.writeValueAsString(bean1));
} catch (JsonProcessingException ex) {
LOGGER.catching(ex);
}
SimpleModule simpleModule = new SimpleModule("SimpleModule", new Version(1, 0, 0, null, "com.bolan", "oa"));
simpleModule.addSerializer(DynaBean.class, new DynaBeanSerializer());
mapper.registerModule(simpleModule);
DynaBean bean2 = new LazyDynaBean();
bean2.set("p1", 1);
bean2.set("p2", 2);
try {
LOGGER.error(mapper.writeValueAsString(bean2));
} catch (JsonProcessingException ex) {
LOGGER.catching(ex);
}
这是DynaBeanSerializer的来源:
public class DynaBeanSerializer extends JsonSerializer<DynaBean> {
private final static Logger LOGGER = LogManager.getLogger(DynaBeanSerializer.class);
@Override
public void serialize(DynaBean value, JsonGenerator gen, SerializerProvider serializers) throws IOException, JsonProcessingException {
LOGGER.info("serializing the byna bean!");
gen.writeStartObject();
DynaProperty[] dynaProperties = value.getDynaClass().getDynaProperties();
for (DynaProperty dynaProperty : dynaProperties) {
try {
gen.writeObjectField(dynaProperty.getName(), PropertyUtils.getProperty(value, dynaProperty.getName()));
} catch (IllegalAccessException | InvocationTargetException | NoSuchMethodException ex) {
LOGGER.error(ex);
}
}
gen.writeEndObject();
}
@Override
public Class<DynaBean> handledType() {
LOGGER.info("get JsonSerializer type!");
return DynaBean.class;
}
}
然而,我希望输出如下:
10:21:03.933 [JavaFX Application Thread] ERROR com.bolan.test.javafx.test.FXMLController - {"p1":1,"p2":2}
此外,如果我按照以下方式编辑测试代码:
DynaBean bean1 = new LazyDynaBean();
bean1.set("p1", 1);
bean1.set("p2", 2);
ObjectMapper mapper = new ObjectMapper();
SimpleModule simpleModule = new SimpleModule("SimpleModule", new Version(1, 0, 0, null, "com.bolan", "oa"));
simpleModule.addSerializer(DynaBean.class, new DynaBeanSerializer());
mapper.registerModule(simpleModule);
DynaBean bean2 = new LazyDynaBean();
bean2.set("p1", 1);
bean2.set("p2", 2);
try {
LOGGER.error(mapper.writeValueAsString(bean2));
} catch (JsonProcessingException ex) {
LOGGER.catching(ex);
}
输出结果是我希望~这非常奇怪。在第一次使用
ObjectMapper
之前,必须注册所有要使用的模块。使用后的注册可能有效,也可能无效;但是,由于序列化程序和反序列化程序的缓存,为已经序列化/反序列化的类型添加自定义(反)序列化程序将不会产生效果。这是我的resteasy代码,用于将objectmapper演示到框架:
@Provider
@Produces({MediaType.APPLICATION_JSON})
public class CustomJsonProvider implements ContextResolver<ObjectMapper> {
private final static Logger LOGGER = LogManager.getLogger(CustomJsonProvider.class);
private final ObjectMapper mapper;
public CustomJsonProvider() {
LOGGER.info("Register provider CustomJsonProvider for resteasy");
this.mapper = new CustomObjectMapper();
}
@Override
public ObjectMapper getContext(Class<?> type) {
LOGGER.info("Get provider CustomJsonProvider for resteasy");
return mapper;
}
}
问题中给出了DynaBeanSerializer的源代码
这是我的web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<display-name>Restful Test</display-name>
<context-param>
<param-name>resteasy.jndi.resources</param-name>
<param-value>java:app/service/LocatingResourceBean,java:app/service/SimpleResourceBean</param-value>
</context-param>
<context-param>
<param-name>resteasy.providers</param-name>
<param-value>com.bolan.rest.provider.CustomJsonProvider,com.bolan.rest.provider.CustomJsonBodyWriter</param-value>
</context-param>
<context-param>
<param-name>resteasy.scan.providers</param-name>
<param-value>true</param-value>
</context-param>
<!-- <listener>
<listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>-->
<servlet>
<servlet-name>oa</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>oa</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>
静息试验
resteasy.jndi.resources
java:app/service/LocatingResourceBean,java:app/service/SimpleResourceBean
resteasy.providers
com.bolan.rest.provider.CustomJsonProvider,com.bolan.rest.provider.CustomJsonBodyWriter
resteasy.scan.providers
符合事实的
骨性关节炎
org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
骨性关节炎
/*
30
事实上,我正在使用resteasy。我想自定义某个类的序列化程序。但它不起作用。调试时,我发现自定义objectmapper是由reateasy创建的,但自定义序列化程序无法工作。我将在下面的回复中显示我的代码。我想知道RestEasy是否有任何代理类创建。你的代码在我看来是正确的,没有问题。
public class CustomObjectMapper extends ObjectMapper {
private static final Logger LOGGER = LogManager.getLogger(CustomObjectMapper.class);
public CustomObjectMapper() {
SimpleModule simpleModule = new SimpleModule("SimpleModule", new Version(1, 0, 0, null, "com.bolan", "oa"));
simpleModule.addSerializer(DynaBean.class, new DynaBeanSerializer());
registerModule(simpleModule);
}
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<display-name>Restful Test</display-name>
<context-param>
<param-name>resteasy.jndi.resources</param-name>
<param-value>java:app/service/LocatingResourceBean,java:app/service/SimpleResourceBean</param-value>
</context-param>
<context-param>
<param-name>resteasy.providers</param-name>
<param-value>com.bolan.rest.provider.CustomJsonProvider,com.bolan.rest.provider.CustomJsonBodyWriter</param-value>
</context-param>
<context-param>
<param-name>resteasy.scan.providers</param-name>
<param-value>true</param-value>
</context-param>
<!-- <listener>
<listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>-->
<servlet>
<servlet-name>oa</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>oa</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>