Java try catch返回假变量

当我将字符串'decision'的值输入为'Yes'时，if语句通过执行line System.out.println（“请继续购物”），就好像decision的值不是'Yes'；我能做些什么来解决这个问题？以下是问题所在的班级：

 //paying for this instance of a basket
public void payBasket(double cash){
    String decision;
    double balance;
    System.out.println("You have £" +cash);
    decision = null;
    if(cash > endTotal)
    {System.out.println("You have enough money to pay for this basket");
    }
    else 
    {System.out.println("You need more money before you can pay for these items");};
    BufferedReader reader;
    reader = new BufferedReader(new InputStreamReader(System.in));
    System.out.println("Would you like to pay for this basket?");
    try{
     decision = reader.readLine();
    }
    catch (IOException ioe){
        System.out.println("an unecpected error");
    }

    if(decision == "Yes"){balance = endTotal - cash;
        System.out.println("Your current balance is " + balance);}
        else {System.out.println("Please continue shopping");
        }
}

---

要比较字符串对象，请使用

equals（String myValue）

方法，而不是

=

在java中使用.equals（）方法而不是“==”运算符来比较对象

改变

if(decision == "Yes")

到

如果要忽略大小写，请使用.equalsIgnoreCase（）方法

这里 ->

if（decision==“Yes”）

使用

使用.equals（）比较字符串。。！

if("Yes".equals(decision))

 if("Yes".equalsIgnoreCase(decision))

if(descision.equals("Yes"));