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为什么会出现java.lang.IllegalArgumentException错误?_Java_Oauth - Fatal编程技术网

为什么会出现java.lang.IllegalArgumentException错误?

为什么会出现java.lang.IllegalArgumentException错误?,java,oauth,Java,Oauth,为什么会出现此错误:java.lang.IllegalArgumentException:此使用者需要org.apache.http.HttpRequest类型的请求 CommonsHttpOAuthConsumer consumer = new CommonsHttpOAuthConsumer (CONSUMER_KEY,CONSUMER_SECRET); consumer.setTokenWithSecret(oaut_token, tokenSecret); U

为什么会出现此错误:java.lang.IllegalArgumentException:此使用者需要org.apache.http.HttpRequest类型的请求

CommonsHttpOAuthConsumer  consumer = new CommonsHttpOAuthConsumer (CONSUMER_KEY,CONSUMER_SECRET);
            consumer.setTokenWithSecret(oaut_token, tokenSecret);

URL url = new URL(targetURL);
request = (HttpURLConnection) url.openConnection();

// sign the request
consumer.sign(request);
// send the request
request.connect();
编辑: 只是更新已接受的答案,因为它不再相关。路标文档有点过时,建议在Android中使用CommonHttpOAuthConsumer,因为HttpURLConnection上有bug。这些已经被修复,现在Android删除了ApacheHTTP,因此处理路标的正确方法现在是通过DefaultOAuthConsumer

DefaultOAuthConsumer  consumer = new DefaultOAuthConsumer (CONSUMER_KEY,CONSUMER_SECRET);
            consumer.setTokenWithSecret(oaut_token, tokenSecret);

URL url = new URL(targetURL);
request = (HttpURLConnection) url.openConnection();

// sign the request

consumer.sign(request);

在您发布的代码中应该很明显,
request
不是
HttpRequest
类型

request = (HttpURLConnection) url.openConnection();
consumer.sign(request);

当方法需要参数类型且接收到另一种类型的参数时,会引发异常java.lang.IllegalArgumentException。
在这种情况下,方法是
符号
,参数是
请求

consumer.sign(request); 

它正在等待接收
HTTPRequest
类型,而它正在接收另一个类型。

路标在android上使用非常简单,lol,一旦你通过了那些不是真正最新的、不完整的、或者不是特别有用的教程

无论如何,这里有一种方法可以使用ApacheHTTP而不是本机android来实现这一点,为了简洁起见,这有点难看,但应该可以让您启动并运行

对代码进行了一些修改以使其工作,您可能希望使HttpClient在调用之间保持一致,但我只是将所有这些都内联。我还注意到您正在反序列化令牌,因此我将假设您已经实现了实际的OAuth流

祝你好运

    CommonsHttpOAuthConsumer consumer = null;
    consumer = new CommonsHttpOAuthConsumer(CONSUMER_KEY,CONSUMER_SECRET);
    consumer.setTokenWithSecret(oaut_token, tokenSecret);

   // Use the apache method instead - probably should make this part persistent until
   // you are done issuing API calls    
   HttpParams parameters = new BasicHttpParams();
   HttpProtocolParams.setVersion(parameters, HttpVersion.HTTP_1_1);
   HttpProtocolParams.setContentCharset(parameters, HTTP.DEFAULT_CONTENT_CHARSET);
   HttpProtocolParams.setUseExpectContinue(parameters, false);
   HttpConnectionParams.setTcpNoDelay(parameters, true);
   HttpConnectionParams.setSocketBufferSize(parameters, 8192);

   HttpClient httpClient = new DefaultHttpClient();

   SchemeRegistry schReg = new SchemeRegistry();
   schReg.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
   ClientConnectionManager tsccm = new ThreadSafeClientConnManager(parameters, schReg);

   httpClient = new DefaultHttpClient(tsccm, parameters);

   HttpGet get = new HttpGet(targetURL); 

    // sign the request
    consumer.sign(get);

    // send the request & get the response (probably a json object, but whatever)
    String response = httpClient.execute(get, new BasicResponseHandler());

    // shutdown the connection manager - last bit of the apache code 
    httpClient.getConnectionManager().shutdown();

    //Do whatever you want with the returned info 
    JSONObject jsonObject = new JSONObject(response);

就是这样

那么你是说这个网站是正确的您正在使用ApacheCommonsHTTP吗?你是为Android写这篇文章的吗?那篇文章中有很多警告。这可能与此相关:如果您需要对其他HTTP请求类型的请求进行签名,请查看中的示例SupportedHttpLibraries@Fabii-是的,那里的教程没有显示Apache Http的使用,这是Android应用程序所必需的,因为Android处理程序中有一个bug。特拉维斯给你指出了正确的方向。看看我下面的答案,看看能与android和Signpost@Idistic你的答案现在在上面| o |看看我提供的答案(两人一起)遇到了同样的问题,概述的解决方案对我有效。是否有生成签名的内置路标方法?@Fabii不确定我是否完全理解你的问题,sign方法为您处理几乎所有的事情,或者您是否正在寻找一种半自动的助手方法来自己构造签名,以便您可以修改?(比如nonce、令牌等)我想知道,既然HttpClient在android中已被弃用,HTTPUrlConnection是如何做到这一点的
public class BlockTicketPostOauth extends AsyncTask<String, Void, Integer> {
    ProgressDialog pd;
    String response;
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        pd=new ProgressDialog(BusPassengerInfo.this);
        pd.setMessage("wait continue to payment....");
        pd.show();

    }

    @Override
    protected Integer doInBackground(String... params) {
        InputStream inputStream = null;
        String ul ="http://api.seatseller.travel/blockTicket";

        String  JSONPayload=params[0];
        Integer result = 0;
        try {

            OAuthConsumer consumer = new CommonsHttpOAuthConsumer(YOUR CONSUMER KEY,YOUR CONSSUMER SECRETE); consumer.setTokenWithSecret(null, null);

            /* create Apache HttpClient */
            HttpClient httpclient = new DefaultHttpClient();

            /* Httppost Method */
            HttpPost httppost = new HttpPost(ul);

            // sign the request
            consumer.sign(httppost);

            // send json string to the server
            StringEntity paras =new StringEntity(JSONPayload);

            //seting the type of input data type
            paras.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

            httppost.setEntity(paras);

            HttpResponse httpResponse= httpclient.execute(httppost);

            int statusCode = httpResponse.getStatusLine().getStatusCode();

            Log.i("response json:","status code is:"+statusCode);
            Log.i("response json:","status message?:"+httpResponse.getStatusLine().toString());

            /* 200 represents HTTP OK */
            if (statusCode ==  200) {
                /* receive response as inputStream */
                inputStream = httpResponse.getEntity().getContent();
                response = convertInputStreamToString(inputStream);

                Log.i("response json:","json response?:"+response);

                Log.i("response block ticket :","status block key:"+response);

                result = 1; // Successful
            } else{
                result = 0; //"Failed to fetch data!";
            }
        } catch (Exception e) {
            Log.d("response error", e.getLocalizedMessage());
        }
        return result; //"Failed to fetch data!";
    }

    @Override
    protected void onPostExecute(Integer result) {

        if(pd.isShowing()){
            pd.dismiss();
        }
        /* Download complete. Lets update UI */
        if(result == 1){

            Toast.makeText(BusPassengerInfo.this,"response is reult suceess:"+response,Toast.LENGTH_SHORT).show();
        }else{
            Log.e("response", "Failed to fetch data!");
            Toast.makeText(BusPassengerInfo.this,"response is reult fail",Toast.LENGTH_SHORT).show();
        }

    }
}