获取字符串方法Java中的int变量
这是家庭作业。我只是想把它放在那里。我觉得最好先展示我的代码,然后解释我要做什么获取字符串方法Java中的int变量,java,methods,Java,Methods,这是家庭作业。我只是想把它放在那里。我觉得最好先展示我的代码,然后解释我要做什么 import java.util.Scanner; public class Question1 { public static void main(String[] args){ int length, odd, even, largest; int n = getNumber(); length=odd=even=largest=initialize(); String sequ
import java.util.Scanner;
public class Question1 {
public static void main(String[] args){
int length, odd, even, largest;
int n = getNumber();
length=odd=even=largest=initialize();
String sequence=createSequence(n, largest, odd, even, length);
displaySequence(sequence);
displayStatistics(largest, length, odd, even);
}
private static int getNumber(){
Scanner kb = new Scanner(System.in);
System.out.println("Enter the value of the number: ");
int number = kb.nextInt();
return number;
}
private static int initialize(){
return 0;
}
public static String createSequence(int n, int largest, int odd, int even, int length){
String sequence="";
sequence+=n+" ";
while (n!=1){
n = (n%2==0) ? n/2 : 3*n+1;
System.out.print(", "+n);
sequence+=n+" ";
if(n%2==0){ even++;
}else{ odd++;}
if(n>=largest){ largest = n;
}
length++;
}
return sequence;
}
private static void displaySequence(String sequence){
System.out.println(sequence);
}
public static String displayStatistics(int length, int even, int odd, int largest){
String nil = "";
System.out.println("The largest number in the sequence was "+largest);
System.out.println("The length of the sequence was "+length);
System.out.println("There were "+odd+" odd numbers");
System.out.println("There were "+even+" even numbers");
return nil;
}
}
我需要尝试显示序列中的最大数,序列的长度,序列中有多少偶数,序列中有多少奇数。但是,由于我无法在createSequence方法中返回int值,因此我无法为每个统计信息获取新值。阻止我显示上述统计数据。如何访问这些新变量以在最终方法中使用
注:
要求:
尝试从我的基本代码中重新实现您的代码
public class Question{
public class NumberStats {
int len;
boolean isOdd;
}
private ArrayList<NumberStats> stats = new ArrayList<>();
public static void main(String[] args){
Question q = new Question();
Scanner kb = new Scanner(System.in);
String number = "";
do {
System.out.println("Enter a series of numbers or q to quit: ");
number = kb.next();
q.stats.add(q.parseNumber(number));
} while (number.equals("q")==false);
q.printSummary();
}
private void printSummary(){
int oddCount = 0;
int evenCount = 0;
int longestNumber = 0;
for (NumberStats s : stats){
if (longestNumber<s.len){
longestNumber = s.len;
}
if (s.isOdd){
oddCount+=1;
} else {
evenCount+=1;
}
}
System.out.println(String.format("Longest number length was : %i, Odd Numbers: %i, Even Numbers: %i",longestNumber,oddCount,evenCount));
}
private NumberStats parseNumber(String number){
NumberStats stats = new NumberStats();
Integer lastNumber = Integer.parseInt(String.valueOf(number.charAt(number.length()));
stats.isOdd = true;
if (lastNumber%2==0){
stats.isOdd = false;
}
stats.len = number.length();
return stats;
}
}
公开课问题{
公共类编号状态{
内伦;
布尔isOdd;
}
private ArrayList stats=new ArrayList();
公共静态void main(字符串[]args){
问题q=新问题();
扫描仪kb=新扫描仪(System.in);
字符串编号=”;
做{
System.out.println(“输入一系列数字或q以退出:”);
number=kb.next();
q、 添加(q.parseNumber(number));
}while(number.equals(“q”)==false);
q、 打印摘要();
}
私人文件摘要(){
int oddCount=0;
int evenCount=0;
int longestNumber=0;
for(NumberStats:stats){
if(longestNumber如果您创建了一个Sequence类,您的老师可能会印象更深刻。类属性将是stats(可以通过getter方法访问)。createSequence方法将成为构造函数。您可以实现一个toString方法来返回内容的字符串表示形式。您可以返回一个包含4个变量的数组,而不是返回字符串类型。要添加@LuaiGhunim的注释,该数组可以是一个包含5个字符串的数组,其中arr[0]
是您的序列,arr[1]
-arr[4]
是您想要的4个整数值,但作为字符串,然后当您获取数组时,要从字符串中获取整数,请执行integer.parseInt(arr[1])
等@DavyM方法非常有效。谢谢。