Java 如何让扫描仪读取我的布尔结果?
我正在制作一个包含大量布尔真或假语句的程序,我想让扫描仪读取布尔值的输出,并将其作为某种输出,有没有办法做到这一点 例:Java 如何让扫描仪读取我的布尔结果?,java,Java,我正在制作一个包含大量布尔真或假语句的程序,我想让扫描仪读取布尔值的输出,并将其作为某种输出,有没有办法做到这一点 例: 基本上,我要求用户输入一个数字,它会将其转换为实际月份的名称,并通过转换数字告诉他们的生日,但当我这样做时,我只是将其打印出来。我想让扫描器先读取输入1,然后将其写为“您的生日是1月1日”您可以使用switch语句,根据输入的数字设置响应字符串,并在打印语句中使用 String response; switch(day){ case 1: response = "fir
基本上,我要求用户输入一个数字,它会将其转换为实际月份的名称,并通过转换数字告诉他们的生日,但当我这样做时,我只是将其打印出来。我想让扫描器先读取输入1,然后将其写为“您的生日是1月1日”您可以使用switch语句,根据输入的数字设置响应字符串,并在打印语句中使用
String response;
switch(day){
case 1: response = "first";
break;
case 2: response = "second";
break;
/*
And so on...
*/
}
尝试以下方法:
public static void main(String[] args) {
final String[] months = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
Scanner sc = new Scanner(System.in);
System.out.println("Type month: ");
int month = 0;
while(sc.hasNextInt()) {
month = sc.nextInt();
// get month from 1 to 12
if (month > 0 && month < 12) {
break;
} else {
System.out.println("Type valid month: ");
continue;
}
}
System.out.println("Type day: ");
while (sc.hasNextInt()) {
int day = sc.nextInt();
int numDays = 0;
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
numDays = 31; break;
case 4:
case 6:
case 9:
case 11:
numDays = 30; break;
case 2: numDays = 28; break;
}
// get day taking under consideration amount of days in the month
if (day > 0 && day <= numDays) {
System.out.println("Your birthday is " + day + " " + months[month-1]);
return;
} else {
System.out.println("Type valid day: ");
continue;
}
}
}
publicstaticvoidmain(字符串[]args){
最终字符串[]月={“一月”、“二月”、“三月”、“四月”、“五月”、“六月”、“七月”、“八月”、“九月”、“十月”、“十一月”、“十二月”};
扫描仪sc=新的扫描仪(System.in);
System.out.println(“类型月份:”);
整月=0;
while(sc.hasnetint()){
月份=sc.nextInt();
//从1月到12月
如果(月>0和月<12){
打破
}否则{
System.out.println(“键入有效月份:”);
继续;
}
}
System.out.println(“键入日期:”);
while(sc.hasnetint()){
int day=sc.nextInt();
int numDays=0;
开关(月){
案例1:
案例3:
案例5:
案例7:
案例8:
案例10:
案例12:
numDays=31;中断;
案例4:
案例6:
案例9:
案例11:
numDays=30;中断;
案例2:numDays=28;中断;
}
//考虑到月内的天数,获取天数
如果(天>0&&D天)
public static void main(String[] args) {
final String[] months = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
Scanner sc = new Scanner(System.in);
System.out.println("Type month: ");
int month = 0;
while(sc.hasNextInt()) {
month = sc.nextInt();
// get month from 1 to 12
if (month > 0 && month < 12) {
break;
} else {
System.out.println("Type valid month: ");
continue;
}
}
System.out.println("Type day: ");
while (sc.hasNextInt()) {
int day = sc.nextInt();
int numDays = 0;
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
numDays = 31; break;
case 4:
case 6:
case 9:
case 11:
numDays = 30; break;
case 2: numDays = 28; break;
}
// get day taking under consideration amount of days in the month
if (day > 0 && day <= numDays) {
System.out.println("Your birthday is " + day + " " + months[month-1]);
return;
} else {
System.out.println("Type valid day: ");
continue;
}
}
}