Java 无法为child()firebase错误中的参数“pathString”传递null
这是代码,当我想获取用户密钥getPhone时我有问题,我不能,因为获取null值我是编程新手Java 无法为child()firebase错误中的参数“pathString”传递null,java,android,firebase,firebase-realtime-database,Java,Android,Firebase,Firebase Realtime Database,这是代码,当我想获取用户密钥getPhone时我有问题,我不能,因为获取null值我是编程新手 LayoutInflater inflater = LayoutInflater.from(this); View layout_pwd = inflater.inflate(R.layout.ganti_password_layout,null); final MaterialEditText edtPassword = (MaterialEditText)layout_p
LayoutInflater inflater = LayoutInflater.from(this);
View layout_pwd = inflater.inflate(R.layout.ganti_password_layout,null);
final MaterialEditText edtPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPassword);
final MaterialEditText edtNewPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaru);
final MaterialEditText edtRepeatPassword = (MaterialEditText)layout_pwd.findViewById(R.id.gantiPasswordBaruUlang);
alertDialog.setView(layout_pwd);
//Button
alertDialog.setPositiveButton("GANTI", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
//Ganti Password Disini
final android.app.AlertDialog waitingDialog = new SpotsDialog(Home.this);
waitingDialog.show();
//cek password lama
if(edtPassword.getText().toString().equals(Common.currentUser.getPassword()))
{
//Cek Password Baru dan Ulang Password
if(edtNewPassword.getText().toString().equals(edtRepeatPassword.getText().toString()))
{
Map<String,Object> passwordUpdate = new HashMap<>();
passwordUpdate.put("password",edtNewPassword.getText().toString());
//Update
DatabaseReference user = FirebaseDatabase.getInstance().getReference("User");
user.child(Common.currentUser.getPhone())
.updateChildren(passwordUpdate)
.addOnCompleteListener(new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
}
});
}
else
{
waitingDialog.dismiss();
Toast.makeText(Home.this, "Pengulangan Password Tidak Sesuai", Toast.LENGTH_SHORT).show();
}
}
else
{
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Lama Salah", Toast.LENGTH_SHORT).show();
}
}
});
存在此问题是因为方法Common.currentUser.getPhone返回null 要修复它,只需在子方法调用之前添加简单的null测试 像这样:
String phone = Common.currentUser.getPhone();
if (phone != null)
user.child(phone)
.updateChildren(passwordUpdate)
.addOnCompleteListener(new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
}
});
else {
// do something else here
}
或者编辑getPhone方法,使其永远不会返回nullNullPointerException请添加将用户和密码添加到Common.currentUser的代码?我在第一篇文章中已经添加了该代码,希望您可以帮助Stack和我的应用程序不做任何事情,只需加载
String phone = Common.currentUser.getPhone();
if (phone != null)
user.child(phone)
.updateChildren(passwordUpdate)
.addOnCompleteListener(new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
waitingDialog.dismiss();
Toast.makeText(Home.this, "Password Telah Diganti", Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(Home.this, e.getMessage(), Toast.LENGTH_SHORT).show();
}
});
else {
// do something else here
}