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Java 如何从parse.com数据库(Android)检索数据?_Java_Android_Parse Platform - Fatal编程技术网

Java 如何从parse.com数据库(Android)检索数据?

Java 如何从parse.com数据库(Android)检索数据?,java,android,parse-platform,Java,Android,Parse Platform,我是Android新手,一直在尝试使用Parse.com。他们网站上提供的代码片段非常有用。我已经能够将数据从我的应用程序发送到数据库,这意味着它正在连接到正确的数据库。但我无法从中检索到正确的数据。无论我使用什么对象ID,它总是返回null或0(取决于它是字符串还是整数)。我的代码如下: public class MainActivity extends ActionBarActivity { TextView tv; Button b; String playe

我是Android新手,一直在尝试使用Parse.com。他们网站上提供的代码片段非常有用。我已经能够将数据从我的应用程序发送到数据库,这意味着它正在连接到正确的数据库。但我无法从中检索到正确的数据。无论我使用什么对象ID,它总是返回null或0(取决于它是字符串还是整数)。我的代码如下:

public class MainActivity extends ActionBarActivity {



    TextView tv;
    Button b;
    String playerName;
    ParseQuery<ParseObject> query = ParseQuery.getQuery("GameScore");
    //int score;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        setContentView(R.layout.activity_main);
        tv=(TextView) findViewById (R.id.tv);
        b=(Button) findViewById (R.id.button1);
        Parse.initialize(this, "n12BWwZwk*************3dyKnuIUU", "vVi4TwI***************4peRD1VwyJ9CHw");
        final ParseObject gameScore = new ParseObject("GameScore");
       /* gameScore.put("score", 900);
        gameScore.put("playerName", "Pranav");
        gameScore.put("cheatMode", false);
        gameScore.saveInBackground();
      */


        query.whereEqualTo("objectId", "PnfRaUtHjB");
        query.findInBackground(new FindCallback<ParseObject>() {

            @Override
            public void done(List<ParseObject> arg0, ParseException arg1) {
                // TODO Auto-generated method stub
                if (arg1==null)
                {
                    int score=gameScore.getInt("score");
                    tv.setText("Player score - "+score);
                    Log.d("PTesting", "Player Score");
                    //Toast.makeText(getApplicationContext(), "Reached till Toast "+score,
                        //     Toast.LENGTH_LONG).show();

                }
                else
                {
                    Log.d("score", "Error: " + arg1.getMessage());
                }
            }

        });

}
}
返回的值为0或null

数据库如下所示:


您使用了错误的对象进行检索。 试试这个

ParseQuery<ParseObject> query=ParseQuery.getQuery("GameScore");
        query.getInBackground("YsHLfJ7tUB", new GetCallback<ParseObject>() {

            @Override
            public void done(ParseObject arg0, ParseException arg1) {
                // TODO Auto-generated method stub

                if (arg1==null)
                {
                    int score = arg0.getInt("score");
                    playerName = arg0.getString("playerName");
                    boolean cheatMode = arg0.getBoolean("cheatMode");
                    tv.setText("Updating "+playerName);

                }
                else
                {
                    Log.d("score", "Error: " + arg1.getMessage());
                }
            }
ParseQuery query=ParseQuery.getQuery(“游戏分数”);
getInBackground(“YsHLfJ7tUB”,新的GetCallback(){
@凌驾
公共无效完成(ParseObject arg0,ParseException arg1){
//TODO自动生成的方法存根
如果(arg1==null)
{
int score=arg0.getInt(“分数”);
playerName=arg0.getString(“playerName”);
boolean cheatMode=arg0.getBoolean(“cheatMode”);
tv.setText(“更新”+播放名称);
}
其他的
{
Log.d(“分数”,“错误:+arg1.getMessage());
}
}
我建议使用子类进行解析。

非常感谢Vivart!我没有意识到!我想我需要改进我的基础知识!谢谢你的提示!我真的很感激!
ParseQuery<ParseObject> query=ParseQuery.getQuery("GameScore");
        query.getInBackground("YsHLfJ7tUB", new GetCallback<ParseObject>() {

            @Override
            public void done(ParseObject arg0, ParseException arg1) {
                // TODO Auto-generated method stub

                if (arg1==null)
                {
                    int score = arg0.getInt("score");
                    playerName = arg0.getString("playerName");
                    boolean cheatMode = arg0.getBoolean("cheatMode");
                    tv.setText("Updating "+playerName);

                }
                else
                {
                    Log.d("score", "Error: " + arg1.getMessage());
                }
            }