Java 如何缩短此代码以适应行限制

所以我有一个任务要做一个游戏，我做了，但它刚刚超过了线的限制。我试着在不破坏语法规则的情况下尽可能多地删除空行和其他内容，并保持适当的形式（大括号）。游戏是，计算机生成4个数字（1-10），并得到一个最终数字，该数字可以从4个数字（随机1或2）中加上或减去，用户需要计算出每个数字是加还是减。代码没有问题，只需要稍微缩短一点。（也许几行？）

这是我的密码：

//ROHAN DATTA (ICS2O8-C) - Magic Operations Game
import java.util.Scanner;
public class MagicNumberOperations {
    public static void main(String[] args) {
        int num1, num2, num3, num4, operation, finalAns = 0;
        String equation = "", userAns, playAgain;
        Scanner input = new Scanner (System.in);
        System.out.println("You are now playing: MAGIC NUMBER OPERATIONS");
        System.out.println("In this game, the computer generates 4 random numbers (1-10), \nand you must choose which operation (+ or -) to use with each number in order to get the final result (Determined by the computer!)");
        do {
            num1 = (int)(Math.random()*(10-1+1)+1);     //Randomly generating 4 numbers
            num2 = (int)(Math.random()*(10-1+1)+1);
            num3 = (int)(Math.random()*(10-1+1)+1);
            num4 = (int)(Math.random()*(10-1+1)+1);
            operation = (int)(Math.random()*(2-1+1)+1);
            if (operation == 1) {               //Determining whether or not to add or subtract
                equation = num1 + "+" + num2;   //Making word equation to compare with user answer later
                finalAns = num1 + num2;         //Creating integer answer to create the final number
            }
            else if (operation == 2) {
                equation = num1 + "-" + num2;
                finalAns = num1 - num2;
            }
            operation = (int)(Math.random()*(2-1+1)+1);
            if (operation == 1) {
                equation += "+" + num3;
                finalAns += num3;
            }
            else if (operation == 2) {
                equation += "-" + num3;
                finalAns -= num3;
            }
            operation = (int)(Math.random()*(2-1+1)+1);
            if (operation == 1) {
                equation += "+" + num4;
                finalAns += num4;
            }
            else if (operation == 2) {
                equation += "-" + num4;
                finalAns -= num4;
            }
            System.out.println("\n\nHere are your 4 numbers: " + num1 + ", " + num2 + ", " + num3 + ", " + num4);       //Statements
            System.out.println("And here is what all the numbers together should be: " + finalAns);
            System.out.print("\nEnter the whole equation (NO SPACES): ");
            userAns = input.nextLine();
            if (!userAns.equals(equation)) {
                System.out.println("Incorrect!");
                System.out.println("The correct answer was: " + equation);
                break;                          //If answer is wrong, loop breaks, GAME OVER!
            } 
            System.out.print("Correct! \n\nWould you like to play again (y / n) ?");
            playAgain = input.nextLine();
        } while (!playAgain.equals("n"));
        input.close();
        System.out.println("\n\nGAME OVER!");
    }
}

---

将部分代码切换到此：

baseNum = (int)(Math.random() * 10 + 1);
equation = baseNum + "";
finalAns = baseNum;
for (int i = 0; i < 3; i++) {
    num = (int)(Math.random() * 10 + 1);
    if (Math.random() * 2 < 1) {
        equation += "+" + num;
        finalAns += num;
    }
    else {
        equation += "-" + num;
        finalAns -= num;
    }
}

baseNum=（int）（Math.random（）*10+1）；
方程=baseNum+“”；
finalAns=baseNum；
对于（int i=0；i<3；i++）{
num=（int）（Math.random（）*10+1）；
if（Math.random（）*2<1）{
方程+=“+”+num；
finalAns+=num；
}
否则{
方程+=“-”+num；
finalAns-=num；
}
}

27行较短：

//ROHAN DATTA (ICS2O8-C) - Magic Operations Game
import java.util.Scanner;
public class MagicNumberOperations {
    public static void main(String[] args) {
        System.out.println("You are now playing: MAGIC NUMBER OPERATIONS");
        System.out.println("In this game, the computer generates 4 random numbers (1-10), \nand you must choose which operation (+ or -) to use with each number in order to get the final result (Determined by the computer!)");
        try (Scanner input = new Scanner(System.in)) {
            do {
                int finalAns, num;
                String equation = "" + (finalAns = (int)(Math.random() * 10 + 1));
                System.out.print("\n\nHere are your 4 numbers: " + equation + ", "); // Statements
                for (int i = 0; i < 3; i++) {
                    System.out.print((num = (int)(Math.random() * 10 + 1)) + (i < 2 ? ", " : "\n"));
                    boolean r = Math.random() * 2 < 1;
                    equation += (r ? "+" : "-") + num;
                    finalAns += r ? num : -num;
                }
                System.out.println("And here is what all the numbers together should be: " + finalAns);
                System.out.print("\nEnter the whole equation (NO SPACES): ");
                if (!input.nextLine().equals(equation)) {
                    System.out.println("Incorrect!");
                    System.out.println("The correct answer was: " + equation);
                    break; // If answer is wrong, loop breaks, GAME OVER!
                }
                System.out.print("Correct! \n\nWould you like to play again (y / n) ?");
            } while (!input.nextLine().equals("n"));
        }
        System.out.println("\n\nGAME OVER!");
    }
}

//罗汉达塔（ICS2O8-C）-魔法操作游戏
导入java.util.Scanner；
公共类MagicNumber操作{
公共静态void main（字符串[]args）{
System.out.println（“您现在正在玩：幻数运算”）；
System.out.println（“在这个游戏中，计算机生成4个随机数（1-10），\n您必须选择对每个数字使用哪种操作（+或-），以获得最终结果（由计算机确定！）；
try（扫描仪输入=新扫描仪（System.in））{
做{
int finalAns，num；
字符串方程=“”+（finalAns=（int）（Math.random（）*10+1））；
System.out.print（“\n\n这是您的4个数字：“+等式+”，”；//语句
对于（int i=0；i<3；i++）{
System.out.print（（num=（int）（Math.random（）*10+1））+（i<2？，“：”\n”）；
布尔r=Math.random（）*2<1；
方程+=（r？“+”：“-”）+num；
finalAns+=r？num:-num；
}
System.out.println（“所有数字加起来应该是：+finalAns”）；
System.out.print（“\n输入整个方程式（无空格）：”；
如果（！input.nextLine（）.equals（等式））{
System.out.println（“不正确！”）；
System.out.println（“正确答案是：“+等式”）；
中断；//若答案是错误的，循环中断，游戏结束！
}
System.out.print（“正确！\n\n是否要再次播放（y/n）？”；
}而（！input.nextLine（）.equals（“n”））；
}
System.out.println（“\n\n名称结束！”）；
}
}

System.out.println（“x”）

后跟

System.out.println（“y”）

可以替换为

System.out.println（“x\ny”）
2-1+1==2
。那么为什么要写
2-1+1
？前3行可以进一步缩短为
equation=“”+（finalAns=（int）（Math.random（）*10+1））
和ìf/else语句可以替换为以下3行：
boolean r=Math.random（）*2<1，
方程+=（r？+：“-”）+num和
finalAns+=r？num:-num。