Java 无法正确解析JSON数组

我从一个webserveice得到以下

字符串
响应：

[
    [
        {
            "dgtype": "adhoc",
            "subtypename": "Person",
            "subtypedesc": "null",
            "summary": "Junaid (Self)",
            "subtype": "person",
            "birthdate": "1995-1-23 ",
            "name": "Junaid (Self)"
        },
        {
            "dgtype": "adhoc",
            "subtypename": "Job",
            "subtypedesc": "null",
            "summary": "Exa",
            "subtype": "person",
            "birthdate": "2010-01-30",
            "name": "Junaid (Self)"
        }
    ]
]

在Java中，我尝试执行以下操作：

JSONArray jArray = new JSONArray(result);  

                System.out.println("Response: "+jArray);

                for(int i = 0; i<= jArray.length(); i++){
                    try {
                        JSONObject oneObject = jArray.getJSONObject(i);

                        String dgtype = oneObject.getString("dgtype");
                        String subtypename = oneObject.getString("subtypename");
                        String subtypedesc = oneObject.getString("subtypedesc");
                        String summary = oneObject.getString("summary");
                        String subtype = oneObject.getString("subtype");
                        String birthdate = oneObject.getString("birthdate");
                        String name = oneObject.getString("name");

                        System.out.println(i);
                        System.out.println("dgtype: "+dgtype);
                        System.out.println("subtypename: "+subtypename);
                        System.out.println("subtypedesc: "+subtypedesc);
                        System.out.println("summary: "+summary);
                        System.out.println("subtype: "+subtype);
                        System.out.println("birthdate: "+birthdate);
                        System.out.println("name: "+name);




                    } catch (JSONException e) {
                        System.out.println("JSON Exception: "+e);
                    } 
                }

我正在举一个例子。我哪里做错了？还要注意异常代码段中缺少的长括号
 您有两个阵列，一个在另一个阵列中：

[
   [
    //Your objects
   ]
]

您可以更改数据格式，使其只有一个数组，也可以修改代码：

JSONArray outer = new JSONArray(result);  
JSONArray jArray = outer.getJSONArray(0);

您有两个阵列，一个在另一个阵列中：

[
   [
    //Your objects
   ]
]

您可以更改数据格式，使其只有一个数组，也可以修改代码：

JSONArray outer = new JSONArray(result);  
JSONArray jArray = outer.getJSONArray(0);

jArray
JSONArray包含另一个
JSONArray
，其中包含
JSONObeject
，因此首先获取JSONArray，然后从中获取所有JSONObject：

        JSONArray oneArray = jArray.getJSONArray(i);
        for(int j = 0; j<= oneArray.length(); j++){
          JSONObject oneObject = oneArray.getJSONObject(j);
          // get dgtype,subtypename,subtypedesc,.. from oneObject
        }

JSONArray oneArray=jArray.getJSONArray（i）；
对于（int j=0；j
jArray
JSONArray包含另一个
JSONArray
，其中包含
JSONObeject
，因此首先获取JSONArray，然后从中获取所有JSONObject：

        JSONArray oneArray = jArray.getJSONArray(i);
        for(int j = 0; j<= oneArray.length(); j++){
          JSONObject oneObject = oneArray.getJSONObject(j);
          // get dgtype,subtypename,subtypedesc,.. from oneObject
        }

JSONArray oneArray=jArray.getJSONArray（i）；
对于（intj=0；j，正如它所说的，'JSONArray不能转换为JSONObject'，在另一个数组中有一个数组，所以

JSONArray jArray1 = new JSONArray(result);  

然后

现在它可以工作了。
正如它所说，“JSONArray无法转换为JSONObject”，您在另一个数组中有一个数组，所以

JSONArray jArray1 = new JSONArray(result);  

              for(int i = 0; i<= jArray.length(); i++){
                  final JSONArray innerArray = jArray.getJSONArray(i);
                  for (int a = 0; a < innerArray.length(); a++) { 
                     try {
                        final JSONObject oneObject = innerArray.getJSONObject(i);    
                        String dgtype = oneObject.getString("dgtype");
                        String subtypename = oneObject.getString("subtypename");
                        String subtypedesc = oneObject.getString("subtypedesc");
                        String summary = oneObject.getString("summary");
                        String subtype = oneObject.getString("subtype");
                        String birthdate = oneObject.getString("birthdate");
                        String name = oneObject.getString("name");

                        System.out.println(i);
                        System.out.println("dgtype: "+dgtype);
                        System.out.println("subtypename: "+subtypename);
                        System.out.println("subtypedesc: "+subtypedesc);
                        System.out.println("summary: "+summary);
                        System.out.println("subtype: "+subtype);
                        System.out.println("birthdate: "+birthdate);
                        System.out.println("name: "+name);
                    } catch (JSONException e) {
                        System.out.println("JSON Exception: "+e);
                    } 
                }
             }

然后

现在它可以工作了。
for（int i=0；i
for（int i=0；我想我会改变数据格式，我刚刚意识到相同的！：）我想我会改变数据格式，我刚刚意识到相同的！：）
              for(int i = 0; i<= jArray.length(); i++){
                  final JSONArray innerArray = jArray.getJSONArray(i);
                  for (int a = 0; a < innerArray.length(); a++) { 
                     try {
                        final JSONObject oneObject = innerArray.getJSONObject(i);    
                        String dgtype = oneObject.getString("dgtype");
                        String subtypename = oneObject.getString("subtypename");
                        String subtypedesc = oneObject.getString("subtypedesc");
                        String summary = oneObject.getString("summary");
                        String subtype = oneObject.getString("subtype");
                        String birthdate = oneObject.getString("birthdate");
                        String name = oneObject.getString("name");

                        System.out.println(i);
                        System.out.println("dgtype: "+dgtype);
                        System.out.println("subtypename: "+subtypename);
                        System.out.println("subtypedesc: "+subtypedesc);
                        System.out.println("summary: "+summary);
                        System.out.println("subtype: "+subtype);
                        System.out.println("birthdate: "+birthdate);
                        System.out.println("name: "+name);
                    } catch (JSONException e) {
                        System.out.println("JSON Exception: "+e);
                    } 
                }
             }