Java 如何将两条短信合并为一条短信？

我使用以下代码创建广播：

public class IncomingSms extends BroadcastReceiver {

    // Get the object of SmsManager
    final SmsManager sms = SmsManager.getDefault();

    public void onReceive(Context context, Intent intent) {

        // Retrieves a map of extended data from the intent.
        final Bundle bundle = intent.getExtras();

        try {

            if (bundle != null) {

                final Object[] pdusObj = (Object[]) bundle.get("pdus");

                for (int i = 0; i < pdusObj.length; i++) {

                    SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
                    String phoneNumber = currentMessage.getDisplayOriginatingAddress();

                    String senderNum = phoneNumber;
                    String message = currentMessage.getMessageBody();

                    Log.i("SmsReceiver", "senderNum: " + senderNum + "; message: " + message+"; Date="+currentMessage.getTimestampMillis());
//sending to API
                   } // end for loop
            } // bundle is null

        } catch (Exception e) {
            Log.e("SmsReceiver", "Exception smsReceiver" +e);

        }
    }

此消息的唯一日期不同

---

如何检查它是否是一条短信的一部分？SmsMessage中是否有任何字段表示这是一条消息？

您需要手动连接多部分消息。 在您的代码中，您需要做一些修改来分别处理多部分消息，如下所示

public class IncomingSms extends BroadcastReceiver {
    // Get the object of SmsManager
    final SmsManager sms = SmsManager.getDefault();
    public void onReceive(Context context, Intent intent) {
        // Retrieves a map of extended data from the intent.
        final Bundle bundle = intent.getExtras();
        SmsMessage messages = null;
        try {
            if (bundle != null) {
                final Object[] pdusObj = (Object[]) bundle.get("pdus");
                messages = new SmsMessage[pdus.length];
                for (int i = 0; i < pdusObj.length; i++) {
                    messages[i] = SmsMessage.createFromPdu((byte[]) pdusObj[i]);

                   } // end for loop
            } // bundle is null
        } catch (Exception e) {
            Log.e("SmsReceiver", "Exception smsReceiver" +e);
        }
        SmsMessage sms = messages[0];
        String message;
        try {
            if (messages.length == 1 || sms.isReplace()) {

                String phoneNumber = sms.getDisplayOriginatingAddress();
                    String senderNum = phoneNumber;
                     message = sms.getMessageBody();
                    Log.info("SmsReceiver", "senderNum: " + senderNum + "; message: " + message+"; Date="+sms.getTimestampMillis());
//sending to API
            } else {
            StringBuilder bodyText = new StringBuilder();
            for (int j = 0; j < messages.length; j++) {
                bodyText.append(messages[j].getMessageBody());
            }
            message = bodyText.toString();
        }
        } catch (Exception e) {

        }

    }
}

public class IncomingSms扩展广播接收器{
//获取SmsManager的对象
final smsmsmanager sms=smsmsmanager.getDefault（）；
公共void onReceive（上下文、意图）{
//从意图检索扩展数据的映射。
final Bundle=intent.getExtras（）；
SmsMessage messages=null；
试一试{
if（bundle！=null）{
最终对象[]pdusObj=（对象[]）bundle.get（“pdus”）；
消息=新的SmsMessage[pdus.length]；
对于（int i=0；i

但如果我收到来自不同电话号码的消息，它不会崩溃吗？因为，您先收到第一条消息，然后再从其他用户处添加正文。即使同时收到来自不同用户的多条消息，这也非常完美。

public class IncomingSms extends BroadcastReceiver {
    // Get the object of SmsManager
    final SmsManager sms = SmsManager.getDefault();
    public void onReceive(Context context, Intent intent) {
        // Retrieves a map of extended data from the intent.
        final Bundle bundle = intent.getExtras();
        SmsMessage messages = null;
        try {
            if (bundle != null) {
                final Object[] pdusObj = (Object[]) bundle.get("pdus");
                messages = new SmsMessage[pdus.length];
                for (int i = 0; i < pdusObj.length; i++) {
                    messages[i] = SmsMessage.createFromPdu((byte[]) pdusObj[i]);

                   } // end for loop
            } // bundle is null
        } catch (Exception e) {
            Log.e("SmsReceiver", "Exception smsReceiver" +e);
        }
        SmsMessage sms = messages[0];
        String message;
        try {
            if (messages.length == 1 || sms.isReplace()) {

                String phoneNumber = sms.getDisplayOriginatingAddress();
                    String senderNum = phoneNumber;
                     message = sms.getMessageBody();
                    Log.info("SmsReceiver", "senderNum: " + senderNum + "; message: " + message+"; Date="+sms.getTimestampMillis());
//sending to API
            } else {
            StringBuilder bodyText = new StringBuilder();
            for (int j = 0; j < messages.length; j++) {
                bodyText.append(messages[j].getMessageBody());
            }
            message = bodyText.toString();
        }
        } catch (Exception e) {

        }

    }
}