如何在JavaFX中显示非矩形的窗格?
我在JavaFX中遇到了一个问题 这就是Jasperserver(一个服务器)、Adhoc模型(一个服务器模型)中显示的内容 如您所见,粉红色区域是一种HTML如何在JavaFX中显示非矩形的窗格?,javafx,flowpane,Javafx,Flowpane,我在JavaFX中遇到了一个问题 这就是Jasperserver(一个服务器)、Adhoc模型(一个服务器模型)中显示的内容 如您所见,粉红色区域是一种HTML标记。它可以显示非矩形形状的UI。像俄罗斯方块 然而,我正试图在JavaFX中做同样的事情,但失败了 我使用了一个流程窗格作为窗格a,并在窗格a中添加了一些标签。然后我使用了一个小流程窗格作为窗格B,也在窗格B中添加了一些标签。最后,我将窗格B添加到窗格a中 如下图所示 如您所见,我未能显示非矩形形状的窗格B。我认为要做到这一点并不
如果有人需要我的密码,请告诉我。我将重写一些简单的代码并放在这里。非常感谢@James\u D 我编写了一个自定义窗格,它扩展了FlowPane,并重写了layoutChildren()函数 它起作用了 以下是我的代码:
import java.util.ArrayList;
import java.util.List;
import javafx.geometry.HPos;
import javafx.geometry.Insets;
import javafx.geometry.VPos;
import javafx.scene.Node;
import javafx.scene.control.Label;
import javafx.scene.layout.FlowPane;
import javafx.scene.layout.GridPane;
import javafx.scene.layout.Region;
public class LayoutFlowPane extends FlowPane {
private class Child {
Node node;
double x, y, w, h;
double blft, midy;
public Child(Node node,
double x, double y, double w, double h,
double blft, double midy) {
super();
this.node = node;
this.x = x;
this.y = y;
this.w = w;
this.h = h;
this.blft = blft;
this.midy = midy;
}
}
private List<Child> children = new ArrayList<>();
private List<Double> midys = new ArrayList<>();
public LayoutFlowPane() {
super();
}
@Override protected void layoutChildren() {
super.layoutChildren();
Insets insets = getInsets();
double width = getWidth();
double height = getHeight();
double top = insets.getTop();
double left = insets.getLeft();
double bottom = insets.getBottom();
double right = insets.getRight();
double maxw = width - left - right;
double maxh = height - top - bottom;
double hgap = snapSpace(this.getHgap());
double vgap = snapSpace(this.getVgap());
storeChildren();
adjustChildren(maxw, maxh, hgap, vgap);
children.forEach(child -> {
layoutInArea(
child.node, child.x, child.y,
child.w, child.h, child.blft, getMargin(child.node),
getColumnHalignmentInternal(), getRowValignmentInternal()
);
});
}
private void storeChildren() {
children = new ArrayList<>();
for (int i = 0; i < getChildren().size(); i ++) {
Node child = getChildren().get(i);
double x = child.getLayoutX();
double y = child.getLayoutY();
double w = 0;
double h = 0;
if (child instanceof Region) {
Region region = (Region) child;
w = region.getWidth();
h = region.getHeight();
} else {
throw new UnknowTypeException("Unknow type found.");
}
double blft = child.getBaselineOffset();
double midy = (y + y + h) / 2;
Child newChild = new Child(child, x, y, w, h, blft, midy);
children.add(newChild);
}
midys = new ArrayList<>();
for (int i = 0; i < children.size(); i ++) {
Child child = children.get(i);
if (midys.isEmpty() || midys.get(midys.size()-1) != child.midy) {
midys.add(child.midy);
}
}
}
private void adjustChildren(double maxw, double maxh, double hgap, double vgap) {
for (int i = 1; i < children.size(); i ++) { // begin with 1
Child pc = children.get(i-1);
Child ch = children.get(i);
boolean bothGridPane = (pc.node instanceof GridPane) && (ch.node instanceof GridPane);
double x = pc.x + pc.w + (bothGridPane ? 0 : hgap);
double midy;
if (x + ch.w <= maxw) { // ThisLine
midy = pc.midy;
ch.x = x;
ch.y = gety(ch.y, ch.midy, midy);
ch.midy = midy;
} else { // NextLine
midy = getNextMidy(pc.midy);
ch.x = children.get(0).x;
ch.y = gety(ch.y, ch.midy, midy);
ch.midy = midy;
}
}
}
private double getNextMidy(double midy) {
for (int i = 0; i < midys.size(); i ++) {
if (i + 1 < midys.size() && midys.get(i) == midy && midys.get(i+1) != midy) {
return midys.get(i+1);
} else if (i + 1 == midys.size() && midys.get(i) == midy) {
return midys.get(i);
}
}
throw new NotFoundException("Next midy not found.");
}
private double gety(double oldy, double oldMidy, double newMidy) {
return oldy + (newMidy - oldMidy);
}
private HPos getColumnHalignmentInternal() {
HPos localPos = getColumnHalignment();
return null == localPos ? HPos.LEFT : localPos;
}
private VPos getRowValignmentInternal() {
VPos localPos = getRowValignment();
return null == localPos ? VPos.CENTER : localPos;
}
private class UnknowTypeException extends RuntimeException {
private static final long serialVersionUID = 1L;
public UnknowTypeException(String message) {
super(message);
}
}
private class NotFoundException extends RuntimeException {
private static final long serialVersionUID = 1L;
public NotFoundException(String message) {
super(message);
}
}
}
import java.util.ArrayList;
导入java.util.List;
导入javafx.geometry.HPos;
导入javafx.geometry.Insets;
导入javafx.geometry.VPos;
导入javafx.scene.Node;
导入javafx.scene.control.Label;
导入javafx.scene.layout.FlowPane;
导入javafx.scene.layout.GridPane;
导入javafx.scene.layout.Region;
公共类LayoutFlowPane扩展了FlowPane{
私班儿童{
节点;
双x,y,w,h;
双盲板,midy;
公共子节点(节点,
双x,双y,双w,双h,
双盲双盲){
超级();
this.node=节点;
这个.x=x;
这个。y=y;
这个.w=w;
这个,h=h;
this.blft=blft;
this.midy=midy;
}
}
private List children=new ArrayList();
private List midys=new ArrayList();
公共布局流程窗格(){
超级();
}
@重写受保护的void layoutChildren(){
super.layoutChildren();
Insets Insets=getInsets();
double width=getWidth();
双倍高度=getHeight();
double-top=insets.getTop();
左双=insets.getLeft();
双底=insets.getBottom();
double right=insets.getRight();
double maxw=宽度-左-右;
double maxh=高度-顶部-底部;
double hgap=snapSpace(this.getHgap());
double vgap=snapSpace(this.getVgap());
储存儿童();
调整子项(最大值、最大值、hgap、vgap);
children.forEach(child->{
布局区(
child.node、child.x、child.y、,
child.w、child.h、child.blft、getMargin(child.node),
GetColumnHaligmentInternal(),GetRowValigmentInternal()
);
});
}
私家子女(){
children=newarraylist();
对于(int i=0;i 如果(x+ch.w)如果可能的话,您必须使用自定义窗格,并自己定义布局。我将通过设置单个子节点的样式来实现这一点(在您的示例中,IIUCLabel
s)。只需使用一个流程窗格
,并将相关标签的样式设置为粉红色背景。感谢您的回复@James_D。您有任何建议的自定义窗格吗?或者您有任何简单的代码来定义布局本身吗?谢谢:这样做一点都不简单。您必须对窗格
进行子类化,然后覆盖layoutChildren()
,然后布局各个子节点以获得所需的效果。简单的建议有什么问题?谢谢。它很有效!