Javascript 回应，我刚刚开始编码，我有一个问题

我现在正在做一个tic-tac-toe游戏，我想在单击另一个对象后更改随机MyClickable对象的类名，但我找不到方法。谢谢你的帮助

导出默认类框扩展组件{
render（）{
返回(
);
}
}
让botPlay=（）=>{
可点击性--
}
让超时=（）=>{
设置超时（botPlay，1500）
}
让点击率=0
类MyClickable扩展组件{
状态={
类名：“a”
}

tl；dr您需要将游戏板存储为状态，并将值作为道具传递给

MyClickable

。然后

MyClickable

只需查看它的

值
道具-例如
null
、
X
或
O
，它根据
值
道具管理自己的类名

完整解决方案：

因此，从你的州开始-它应该可以重新预订一个tic-tac趾板，看起来像这样：

[
  [null,null,null],
  [null,null,null],
  [null,null,null],
]

现在我们还需要知道轮到谁了，所以让我们也把它添加到state中（我们将从X开始）

很好，现在我们知道我们的状态应该是什么样子了，让我们制作组件：

expport class Board extends React.Component = {

   constructor() {
     this.state = {
       playerTurn: 'X',
       board: [
        [null,null,null],
        [null,null,null],
        [null,null,null],
      ]
     }
   }

   // when this is called, we update our board state and we change the player turn from X to O (or vice versa)
   handleClick = (row,col) => {
      // number 1 rule of React - don't mutate state (or props, or anything really)
      const nextBoard = [...this.state.board];

      // change the next turn to X, or O, depending on whose turn it is currently
      const nextTurn = this.state.playerTurn === 'X' ? 'O': 'X';


      // set the value of the board at row/col to X or O, depending on whose turn it is currently
      nextBoard[row][col] = this.state.playerTurn;

      // at this point you can determine if the game is over or not

      this.setState({playerTurn:nextTurn,board:nextBoard});
   }

   // helper - tells us if the game is over
   winner = () => {
     // return X if X has one, based on the state, or O is O has won, or null if nobody has won
     // leave this up to you to implement
   }

   render() {

     // if we have a winner, we can show who won!
     const winner = this.winner();
     if(winner) {
       return <div>{winner} won!</div>
     }

     // if we don't have a winner, show the game board
     return (
       <div className="box">
        {
          this.state.board.map((row,i) =>
            row.map((value,m) => (
              <MyClickable 
               // if this already has a value, pass undefined as `onClick`
               onClick={value ? undefined : () => this.handleClick(i,m)} 
               value={value}
             />
            ))
          )
         }
       </div>
     )
   }

}

如果要更改由
MyClickable
组件呈现的div的类名，只需查看
value
——它将是
null
、
X
或
O
：

const MyClickable = ({onClick,value}) => {

  return (
    <div className={value == null ? 'clickable' : 'already-clicked'} onClick={onClick}>
      {value}
    </div>
  )

}

constmyclickable=（{onClick，value}）=>{
返回(
{value}
)
}
您需要类似于
…
的东西。现在更改状态以更改类名。此外，（即，将九个框中的每个框的状态改为父框的状态，并使用道具将其传递下去）感谢您的帮助！
const MyClickable = ({onClick,value}) => {

  return (
    <div onClick={onClick}>
      {value}
    </div>
  )

}

const MyClickable = ({onClick,value}) => {

  return (
    <div className={value == null ? 'clickable' : 'already-clicked'} onClick={onClick}>
      {value}
    </div>
  )

}