创建使用intellisense的javascript函数

我想利用visual studio intellisense，因此我阅读了：

不管怎样，为什么我不能通过以下方式获得智能感知：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

function Test() {
    /// <returns type="Customer"></returns>

    var c = new Object();
    $.ajax({
        async: false,
        dataType: "json",
        url: "Ajax/GetCustomer.aspx",
        success: function (foundCustomer) {
            // I know that found customer is of type Customer
            c = foundCustomer;
        }
    });

    return c;
}

var x = Test();
x. // No intellicense! why?

我得到了很多json对象，我想使用这个helper函数来转换它们

---

临时解决办法： 这就是我最后做的：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {
        // this will never be true on real browser. It is always true in visual studio (visual studio will now think that found customer is of type Customer ;)
        if (document.URL.length == 0) foundCustomer = new Customer();

        foundCustomer.// Intellisense works!!!!
    }
});

---

如果将Customer函数更改为接受参数：

function Customer(opts) {
    var opts = opts || {};

    this.id = 0;
    this.firstName = '';
    this.lastName = '';

    for (var i in opts) {
        if (opts.hasOwnProperty(i)) this[i] = opts[i];
    }
}

---

然后在

Test

函数中，将

c=foundCustomer

更改为

c=newcustomer（foundCustomer）

。我猜这可能会触发intellicense？

您正在初始化

对象的返回值，因此它是Intellisense所基于的。如果将其初始化为空的
客户
，则Intellisense将检测到它正在返回
客户

function Test() {

    var c = new Customer(); //only for Intellisense

    $.ajax({...});

    return c;
}

Test(). //Customer members now appear


您还可以使用
//
指定参数类型：

$.ajax({
    ...

        success: function (foundCustomer) {
           /// <param name='foundCustomer' type='Customer' />
           foundCustomer. //Customer members appear            
        }
});

您希望Intellisense在这里说什么，您还没有在类型
Customer
本身中添加任何内容？Id、FirstName和LastName。。。与我在何处操作相同的智能：
var x=new Customer（）；x、 //智能许可证将起作用是的，我喜欢
如果（document.URL.length）c=this我将在制作演员阵容之前使用它，避免编写类似以下内容：
/
$.ajax({
    ...

        success: function (foundCustomer) {
           /// <param name='foundCustomer' type='Customer' />
           foundCustomer. //Customer members appear            
        }
});

Object.prototype.CastToCustomer = function() {

  var c = new Customer();
  if (document.URL.length) c = this;
  return c;

}