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js在javascript中不止一个值不是从外部打开的_Javascript_Variables_Call - Fatal编程技术网

js在javascript中不止一个值不是从外部打开的

js在javascript中不止一个值不是从外部打开的,javascript,variables,call,Javascript,Variables,Call,我做错了什么,我需要打印ex_域值['phaze.co'],['katzddl.org'] 请帮帮我。这就是你想要的吗 var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]]; var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]]; var my_site = 'katzbb.com'; var e

我做错了什么,我需要打印ex_域值['phaze.co'],['katzddl.org']
请帮帮我。

这就是你想要的吗

var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]];

var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]];
var my_site = 'katzbb.com';
var ex_domains = ['phaze.co','katzddl.org'];
var exclude_domains = ['lx5.in','backlink.lx5.in'];

var excluded = exclude_domains.concat(ex_domains,my_site);