js在javascript中不止一个值不是从外部打开的
我做错了什么,我需要打印ex_域值['phaze.co'],['katzddl.org']js在javascript中不止一个值不是从外部打开的,javascript,variables,call,Javascript,Variables,Call,我做错了什么,我需要打印ex_域值['phaze.co'],['katzddl.org'] 请帮帮我。这就是你想要的吗 var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]]; var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]]; var my_site = 'katzbb.com'; var e
请帮帮我。这就是你想要的吗
var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]];
var exclude_domains = [['lx5.in'],['backlink.lx5.in'],ex_domains,[my_site]];
var my_site = 'katzbb.com';
var ex_domains = ['phaze.co','katzddl.org'];
var exclude_domains = ['lx5.in','backlink.lx5.in'];
var excluded = exclude_domains.concat(ex_domains,my_site);