Javascript 引导模式不显示信息
我已经实习了6个月,目前正在使用Bootstrap模式开发一个web系统。我遇到一个问题,我的模态视图无法显示任何信息。脚本中没有错误,但我不知道如何修复它。它只是一片空白。有什么建议吗 这是员工详细信息的模式视图,不显示任何信息: 下面是用于显示模态视图的两个文件中的代码 index.htmlJavascript 引导模式不显示信息,javascript,ajax,bootstrap-modal,Javascript,Ajax,Bootstrap Modal,我已经实习了6个月,目前正在使用Bootstrap模式开发一个web系统。我遇到一个问题,我的模态视图无法显示任何信息。脚本中没有错误,但我不知道如何修复它。它只是一片空白。有什么建议吗 这是员工详细信息的模式视图,不显示任何信息: 下面是用于显示模态视图的两个文件中的代码 index.html <?php //index.php $connect = mysqli_connect("localhost", "root", "", "testing"); $query = "SELE
<?php
//index.php
$connect = mysqli_connect("localhost", "root", "", "testing");
$query = "SELECT * FROM tbl_user ORDER BY user_id DESC";
$result = mysqli_query($connect, $query);
?>
<!DOCTYPE html>
<html>
<head>
<title>ADD NEW USER</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
</head>
<body>
<br /><br />
<div class="container" style="width:700px;">
<h3 align="center">Admin Log Site </h3>
<br />
<div class="table-responsive">
<div align="right">
<button type="button" name="age" id="age" data-toggle="modal" data-target="#add_data_Modal" class="btn btn-warning">Add New User</button>
</div>
<br />
<div id="employee_table">
<table class="table table-bordered">
<tr>
<th width="70%">Staff Name</th>
<th width="30%">View</th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["uname"]; ?></td>
<td><input type="button" name="view" value="view" id="<?php echo $row["user_id"]; ?>" class="btn btn-info btn-xs view_data" /></td>
</tr>
<?php
}
?>
</table>
</div>
</div>
</div>
</body>
</html>
<!-- modal insert division -->
<div id="add_data_Modal" class="modal fade">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">ADMIN SITE</h4>
</div>
<div class="modal-body">
<form method="post" id="insert_form">
<label>Enter Staff Username</label>
<input type="text" name="uname" id="uname" class="form-control" />
<br />
<label>Enter Staff ID</label>
<input type="text" name="staff_number" id="staff_number" class="form-control" />
<br />
<label>Staff Roles</label>
<select name="staff_role" id="staff_role" class="form-control">
<option value="Administration">Administration</option>
<option value="Project Manager">Project Manager</option>
<option value="Staff">Staff</option>
</select>
<br />
<label>Password</label>
<input type="text" name="password" id="password" class="form-control" />
<br />
<input type="submit" name="insert" id="insert" value="Add user" class="btn btn-success" />
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<!-- modal view employer -->
<div id="dataModal" class="modal fade">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Staff Details</h4>
</div>
<div class="modal-body" id="employee_detail">
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<script>
$(document).ready(function(){
$('#insert_form').on("submit", function(event){
event.preventDefault();
if($('#uname').val() == "")
{
alert("Name is required");
}
else if($('#staff_number').val() == "")
{
alert("Staff id is required");
}
else if($('#staff_role').val() == "")
{
alert("Staff role is required");
}
else if($('#password').val() == "")
{
alert("password is required");
}
else
{
$.ajax({
url:"insertdata.php",
method:"POST",
data:$('#insert_form').serialize(),
beforeSend:function(){
$('#insert').val("Inserting");
},
success:function(data){
$('#insert_form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#employee_table').html(data);
}
});
}
});
$(document).on('click', '.view_data', function(){
//$('#dataModal').modal();
var user_id = $(this).attr("user_id");
$.ajax({
url:"view.php",
method:"POST",
data:{user_id:user_id},
success:function(data){
$('#employee_detail').html(data);
$('#dataModal').modal('show');
}
});
});
});
</script>
添加新用户
管理日志站点
添加新用户
职员姓名
看法
您的问题是您的$.ajax
POST正在发送JSON
数据,但您的PHP
视图正在$\u POST
中查找项目
要设置$\u POST
值,请尝试以下操作:
$.ajax({
url:“view.php”,
方法:“张贴”,
数据:“用户id=”+用户id,
成功:功能(数据){
$(“#员工详细信息”).html(数据);
$('#dataModal').modal('show');
}
});代码>请花一点时间阅读:这里没有足够的信息来回答/理解您的问题。对此表示抱歉。我已经改进了我的问题。谢谢你提供的新信息。它帮助我理解您的问题,并编辑您的问题以使您的问题更清楚。您能否将success函数更改为success:function(data){console.log(data);}
并将所记录的内容发布到控制台。感谢您的解释。我将努力寻找这个答案。谢谢你的回答。它帮助我找出我的代码出了什么问题。再次感谢@Alexander。你的回答很好。
<?php
//select.php
if(isset($_POST["user_id"]))
{
$output = '';
$connect = mysqli_connect("localhost", "root", "", "testing");
$query = "SELECT * FROM tbl_user WHERE user_id = '".$_POST["user_id"]."'";
//$query = "SELECT * FROM tbl_user WHERE user_id = '".$_POST["id"]."'";
$result = mysqli_query($connect, $query);
$output .= '
<div class="table-responsive">
<table class="table table-bordered">';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td width="30%"><label> Staff Name</label></td>
<td width="70%">'.$row["uname"].'</td>
</tr>
<tr>
<td width="30%"><label>Staff Id</label></td>
<td width="70%">'.$row["staff_number"].'</td>
</tr>
<tr>
<td width="30%"><label>Staff Role</label></td>
<td width="70%">'.$row["staff_role"].'</td>
</tr>
<tr>
<td width="30%"><label>password</label></td>
<td width="70%">'.$row["password"].'</td>
</tr>
';
}
$output .= '</table></div>';
echo $output;
}
?>