Javascript 谷歌登录API-如何使用PHP注销某人?
在谷歌的页面底部有一个部分,展示了如何使用Javascript注销用户:Javascript 谷歌登录API-如何使用PHP注销某人?,javascript,php,google-signin,google-api-php-client,Javascript,Php,Google Signin,Google Api Php Client,在谷歌的页面底部有一个部分,展示了如何使用Javascript注销用户: <a href="#" onclick="signOut();">Sign out</a> <script> function signOut() { var auth2 = gapi.auth2.getAuthInstance(); auth2.signOut().then(function () { console.log('User signed o
<a href="#" onclick="signOut();">Sign out</a>
<script>
function signOut() {
var auth2 = gapi.auth2.getAuthInstance();
auth2.signOut().then(function () {
console.log('User signed out.');
});
}
</script>
函数签出(){
var auth2=gapi.auth2.getAuthInstance();
auth2.signOut().then(函数(){
log('User signed out');
});
}
我一直在寻找,但我找不到一种方法来像这样使用PHP注销用户
我确实发现了如何让用户完全退出谷歌,但我不想这样。我还知道我可以删除保存访问代码的$\u SESSION
变量,但这仍然不是我想要的
有人知道我如何使用PHP将某人从我的Google应用程序中注销吗?JavaScript是为不同于您的域操作Cookie的唯一方法。如果您想让用户在服务器端的
auth2.signOut()
上注销(虽然是python,但您应该知道)
这取决于您如何构造会话,但您可以在
注销()之前向服务器发送ajax请求。
检查此项,它将对您起作用
header('Location:https://www.google.com/accounts/Logout?continue=https://appengine.google.com/_ah/logout?continue=http://www.domain.com');
为什么不让您的注销脚本看起来像这样:
<?php
session_start();
session_unset();
session_destroy();
?>
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script src="https://apis.google.com/js/platform.js?onload=onLoadCallback" async defer></script>
<script>
window.onLoadCallback = function(){
gapi.load('auth2', function() {
gapi.auth2.init();
var auth2 = gapi.auth2.getAuthInstance();
auth2.signOut().then(function () {
document.location.href = 'login.php';
});
});
};
</script>
</body>
</html>
window.onLoadCallback=函数(){
load('auth2',function(){
gapi.auth2.init();
var auth2=gapi.auth2.getAuthInstance();
auth2.signOut().then(函数(){
document.location.href='login.php';
});
});
};
这应该行得通,我修复了Mark Guinn代码的问题,即gapi.auth2.init()代码>方法的任务未完成执行.then()
'it解决了这个问题
<?php
session_start();
session_unset();
session_destroy();
?>
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script src="https://apis.google.com/js/platform.js?onload=onLoadCallback" async defer></script>
<script>
window.onLoadCallback = function(){
gapi.load('auth2', function() {
gapi.auth2.init().then(function(){
var auth2 = gapi.auth2.getAuthInstance();
auth2.signOut().then(function () {
document.location.href = 'login.php';
});
});
});
};
</script>
</body>
</html>
window.onLoadCallback=函数(){
load('auth2',function(){
gapi.auth2.init(){
var auth2=gapi.auth2.getAuthInstance();
auth2.signOut().then(函数(){
document.location.href='login.php';
});
});
});
};
所以上面的脚本只是删除了cookie?javascript控制台中出现错误:ReferenceError:找不到变量:gap
是否正在加载google api?您是否尝试过我的建议,使用window.load或onready处理程序?对,所以api没有加载。看起来您需要这样做:(同时更新我的答案)现在它返回TypeError:undefined不是对象(评估'gapi.auth2.getAuthInstance')
对不起,我以为您以前实际使用过这个库。。。请参见要发布的编辑。确保你在写着你的客户id的地方填写你的客户id。我希望我能投两次赞成票。找了这么久
<?php
session_start();
session_unset();
session_destroy();
?>
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script src="https://apis.google.com/js/platform.js?onload=onLoadCallback" async defer></script>
<script>
window.onLoadCallback = function(){
gapi.load('auth2', function() {
gapi.auth2.init();
var auth2 = gapi.auth2.getAuthInstance();
auth2.signOut().then(function () {
document.location.href = 'login.php';
});
});
};
</script>
</body>
</html>
<?php
session_start();
session_unset();
session_destroy();
?>
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script src="https://apis.google.com/js/platform.js?onload=onLoadCallback" async defer></script>
<script>
window.onLoadCallback = function(){
gapi.load('auth2', function() {
gapi.auth2.init().then(function(){
var auth2 = gapi.auth2.getAuthInstance();
auth2.signOut().then(function () {
document.location.href = 'login.php';
});
});
});
};
</script>
</body>
</html>