Javascript 如何在CreateJS中更改图形的填充颜色_Javascript_Createjs

Javascript 如何在CreateJS中更改图形的填充颜色

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Javascript 如何在CreateJS中更改图形的填充颜色,javascript,createjs,Javascript,Createjs,我用它来改变颜色的填充创建js这是不工作的 var shape_rect = new createjs.Shape(); shape_rect.graphics.beginFill("#FFD64B").drawRect(61, 253, 398, 25); shap_rect3.addEventListener('mouseover', function (evt) { shap_rect3.graphics.beginFill("#FFD64B").drawRect(61, 253,

我用它来改变颜色的填充创建js这是不工作的

var shape_rect = new createjs.Shape();
shape_rect.graphics.beginFill("#FFD64B").drawRect(61, 253, 398, 25);
shap_rect3.addEventListener('mouseover', function (evt) {
    shap_rect3.graphics.beginFill("#FFD64B").drawRect(61, 253, 398, 25);
    stage.update();
});

这里有几件事：

首先，我注意到eventListener链接到shap_rect3，但这还没有定义（至少在您的示例中没有定义）。鼠标盖的颜色也与声明的颜色相同，因此您不会看到任何更改

假设形状3是一个打字错误，这应该对您有用

loadGame = function() {
    var canvas = document.getElementById('canvas');
    var stage = new createjs.Stage(canvas);

    stage.enableMouseOver(); //Enable MouseOver events

    var shape_rect = new createjs.Shape(); //Create your shape variable
    shape_rect.graphics.beginFill("#FFD64B").drawRect(61, 253, 398, 25); //Draw initial rectangle

    shape_rect.on('mouseover', function(evt) { //Change colour on mouseOver
        shape_rect.graphics.beginFill("#FF5400").drawRect(61, 253, 398, 25);
        stage.update(evt);
    });

    //Add this if you want to simulate a hover state and return the rectangle back to it's original colour
    shape_rect.on('mouseout', function(evt) { //.on gives the same result as .addEventListener (at least from a visual perspective, I'm not sure about resource usage)
        shape_rect.graphics.beginFill("#FFD64B").drawRect(61, 253, 398, 25);
        stage.update(evt);
    });

    stage.addChild(shape_rect);
    stage.update();
}

我不熟悉createJS和easelJS，但这是实现这一点的一种方法。然后只需运行loadGame函数onLoad：

<body onLoad="loadGame()">
    <canvas id="canvas" width="640" height="640"></canvas>
</body>