Javascript Ajax：使用PHP检查电子邮件可用性
如果我输入了一封不在数据库中的电子邮件，如果该电子邮件在数据库中，则始终与该警报保持相同的警报。我的编码有什么问题 我输入电子邮件'irsyadfahmy@gmail.com'我输入结果，而不是'电子邮件地址可以使用'应该'电子邮件地址已经在使用'Javascript Ajax：使用PHP检查电子邮件可用性,javascript,php,ajax,Javascript,Php,Ajax,如果我输入了一封不在数据库中的电子邮件，如果该电子邮件在数据库中，则始终与该警报保持相同的警报。我的编码有什么问题 我输入电子邮件'irsyadfahmy@gmail.com'我输入结果，而不是'电子邮件地址可以使用'应该'电子邮件地址已经在使用' <html> <head> <!-- sweet alert --> <link rel="stylesheet" type="text/css" href="cs
<html>
<head>
<!-- sweet alert -->
<link rel="stylesheet" type="text/css" href="css/sweetalert.css">
<script type="text/javascript" src="js/sweetalert.min.js"></script>
<!-- end sweet alert -->
<script type="text/javascript">
$(document).ready(function(){
$('#email').blur(function(){
var email = $(this).val();
$.ajax({
type : 'POST',
url : 'check-email.php',
data : 'email='+email,
success : function(data){
if(data==0)
{
swal({
title: "Email Address can used",
text: "",
type: "success"
});
}
else
{
swal({
title: "Email Address Already in Use",
text: "",
type: "warning"
});
}
},
});
});
});
</script>
</head>
<body>
<form class="form-horizontal" method="POST" name="form">
<input type="email" name="email" id="email" class="form-control" required>
</form>
</body>
</html>
$（文档）.ready（函数（）{
$（'#email'）.blur（函数（）{
var email=$（this.val（）；
$.ajax({
键入：“POST”，
url:“check email.php”，
数据：“电子邮件=”+电子邮件，
成功：功能（数据）{
如果（数据==0）
{
游泳({
标题：“可以使用电子邮件地址”，
正文：“，
类型：“成功”
});
}
其他的
{
游泳({
标题：“电子邮件地址已在使用”，
正文：“，
类型：“警告”
});
}
},
});
});
});
<?php
include 'libraries/config.php';
$email = $_POST['email'];
$cekdata=mysqli_query($conn,"SELECT * FROM user_csr WHERE email = '$email'");
?>
作为您的程序场景，只需在success函数中交换if主体，这里是代码片段
success : function(data){
if(data==0)
{
swal({
title: "Email Address Already in Use",
text: "",
type: "warning"
});
}
else
{
swal({
title: "Email Address can used",
text: "",
type: "success"
});
}
},
请检查这段代码，我有一些PHP代码和JS代码
<?php
include 'libraries/config.php';
$email = isset($_POST['email'])?$_POST['email']:'';
if(!empty($email)){
$cekdata=mysqli_query($conn,"SELECT * FROM user_csr WHERE email = '$email'");
return $cekdata->num_rows; // if email found it returns 1 else 0
}else{
return 0;
}
您需要使用echo
或print
将数据发送回ajax（在这种情况下，我使用die（）
）。我也倾向于使用json
来响应。您至少应该检查电子邮件是否有效，但您应该绑定电子邮件值，而不是将其注入sql字符串：
PHP:
您是否收到任何错误？在控制台.log（数据）
之后，您在控制台中看到了什么？
<script type="text/javascript">
$(document).ready(function () {
$('#email').blur(function () {
var email = $(this).val();
if(email==""){
alert('Please enter email address');
return false;
}
$.ajax({
type: 'POST',
url: 'check-email.php',
data: 'email=' + email,
success: function (data) {
if (data == 0)
{
swal({
title: "Email Address can use",
text: "",
type: "success"
});
} else
{
swal({
title: "Email Already Exists",
text: "",
type: "warning"
});
}
},
});
});
});
</script>
<?php
include('libraries/config.php');
# Set a default response
$def = ['alert'=>true];
# Remove empty values
$email = trim($_POST['email']);
# First check this is an actual email
if(!filter_var($email,FILTER_VALIDATE_EMAIL))
die(json_encode($def));
# You should bind/prepare $email, not insert variable into string
$query = mysqli_query($conn, "SELECT COUNT(*) as count FROM `user_csr` WHERE `email` = '{$email}'");
# Check that the query succeeded and get the count
if($query)
# Fetch the results of the count
$result = mysqli_fetch_assoc($query);
# Write json respons
die(json_encode([
# If succeeded, write the count
'counted' => ($query)? $result['count'] : 0
]));
<script type="text/javascript">
$(document).ready(function(){
$('#email').blur(function(){
var email = $(this).val();
$.ajax({
type: 'POST',
url: 'check-email.php',
data: 'email='+email,
success: function(response){
// Parse response
response = JSON.parse(response);
// See if alert is set (email is not valid)
if(typeof response.alert !== "undefined") {
// Set an program alert
alert('A program error occurred.');
// Stop
return false;
}
var counted = response.counted;
swal({
title: (counted == 1)? "Email Address Already in Use" : "Email Address can used",
text: "",
type: (counted == 1)? "warning" : "success"
});
},
});
});
});
</script>