Javascript ES6“从导入导出*”？

是否有一种使用ES6、ES7或babel的语法可以让我轻松地将多组子文件捆绑在一起

例如，给定：

./action_creators/index.js
./action_creators/foo_actions.js
./action_creators/bar_actions.js

让index.js导入foo和bar操作，然后重新导出它们，这样我就可以

import {FooAction, BarAction} from './action_creators/index.js'

---

如果要更改将对象本身组织到的文件，我不想记住/更改引用

是，ES6支持直接导出导入的模块：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

---

您还可以使用

*

语法重新导出导入模块的所有导出内容：

export * from …;

export * from './action_creators/index.js';

---

---

默认值导出为默认值：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

---

默认值导出为命名：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

命名导出为默认值：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

命名导出为命名：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

命名导出为重命名：

export { name1, name2, …, nameN } from …;

export {FooAction, BarAction} from './action_creators/index.js'

export {default} from './something';

export {default as foo} from './something';

export {foo as default} from './something';

export {foo} from './something';

export {foo as bar} from './something';

---

这对我来说是有效的

export{defaultasfoo}from./foo'。这不起作用
从“/something”
将*导出为某物。有什么想法吗？@Qwerty您目前无法像那样导出命名名称空间。请参阅，以了解其建议。在此期间，您可以做的一件事是：“`import*as something from./something'；export{Something}``如果
export*from…
的后续两行以相同的名称导出命名函数，会发生什么情况？我的意思是，如果
从'a'导出*
和
export*from'b'
，这两个
a
和
b
都定义了一个同名函数并将其导出，例如：
export function fn（）{…}
…我来这里是想知道为什么我不能将
export*用作来自…
的东西。。。。哈哈哈如何
export*from./something'