Javascript 使用Php和Ajax发送部分电子邮件的联系人表单
我已经设计了以下光滑的表单，并将其与PhP和ajax一起使用以提交。。。其工作正常，包括向目标电子邮件ID发送电子邮件。。总共有七个07字段应该由访问者填写。问题是，当有人提交包含所有字段的表单时，我只能收到三个03字段名称、电子邮件和消息。。。。其余四个04字段电话、国家/地区、预算和选择未显示在电子邮件中。。。我确信我的Php一定有问题。请告诉我在下面的Php中我错在哪里Javascript 使用Php和Ajax发送部分电子邮件的联系人表单,javascript,php,jquery,html,ajax,Javascript,Php,Jquery,Html,Ajax,我已经设计了以下光滑的表单，并将其与PhP和ajax一起使用以提交。。。其工作正常，包括向目标电子邮件ID发送电子邮件。。总共有七个07字段应该由访问者填写。问题是，当有人提交包含所有字段的表单时，我只能收到三个03字段名称、电子邮件和消息。。。。其余四个04字段电话、国家/地区、预算和选择未显示在电子邮件中。。。我确信我的Php一定有问题。请告诉我在下面的Php中我错在哪里 <?php // Define some constants define( "RECIPIENT_NAME",
<?php
// Define some constants
define( "RECIPIENT_NAME", "John Smith" );
define( "RECIPIENT_EMAIL", "example@example.com" );
define( "EMAIL_SUBJECT", "Visitor Message" );
// Read the form values
$success = false;
$senderName = isset( $_POST['senderName'] ) ? preg_replace( "/[^\.\-\' a-zA-Z0-9]/", "", $_POST['senderName'] ) : "";
$senderEmail = isset( $_POST['senderEmail'] ) ? preg_replace( "/[^\.\-\_\@a-zA-Z0-9]/", "", $_POST['senderEmail'] ) : "";
$senderPhone = isset( $_POST['senderPhone'] ) ? preg_replace( "/[^\.\-\_\@a-zA-Z0-9]/", "", $_POST['senderPhone'] ) : "";
$senderCountry = isset( $_POST['senderCountry'] ) ? preg_replace( "/[^\.\-\_\@a-zA-Z0-9]/", "", $_POST['senderCountry'] ) : "";
$senderBudget = isset( $_POST['senderBudget'] ) ? preg_replace( "/[^\.\-\_\@a-zA-Z0-9]/", "", $_POST['senderBudget'] ) : "";
$senderSelect = isset( $_POST['senderSelect'] ) ? preg_replace( "/[^\.\-\_\@a-zA-Z0-9]/", "", $_POST['senderSelect'] ) : "";
$message = isset( $_POST['message'] ) ? preg_replace( "/(From:|To:|BCC:|CC:|Subject:|Content-Type:)/", "", $_POST['message'] ) : "";
// If all values exist, send the email
if ( $senderName && $senderEmail && $senderPhone && $senderCountry && $senderBudget && $senderSelect && $message ) {
$recipient = RECIPIENT_NAME . " <" . RECIPIENT_EMAIL . ">";
$headers = "From: " . $senderName . " <" . $senderEmail . ">";
$success = mail( $recipient, EMAIL_SUBJECT, $message, $headers );
}
// Return an appropriate response to the browser
if ( isset($_GET["ajax"]) ) {
echo $success ? "success" : "error";
} else {
?>
<html>
<head>
<title>Thanks!</title>
</head>
<body>
<?php if ( $success ) echo "<p>Thanks for sending your message! We'll get back to you shortly.</p>" ?>
<?php if ( !$success ) echo "<p>There was a problem sending your message. Please try again.</p>" ?>
<p>Click your browser's Back button to return to the page.</p>
</body>
</html>
<?php
}
?>
您在邮寄时未添加电话、国家/地区、预算和选择字段。试试这个：
if ( $senderName && $senderEmail && $senderPhone && $senderCountry && $senderBudget && $senderSelect && $message ) {
$msgToSend = "Name: ".$senderName."\r\n";
$msgToSend .= "Email: ".$senderEmail."\r\n";
$msgToSend .= "Phone: ".$senderPhone."\r\n";
$msgToSend .= "Sender Country: ".$senderCountry."\r\n";
$msgToSend .= "Sender Budget: ".$senderBudget."\r\n";
$msgToSend .= "Sender Select: ".$senderSelect."\r\n";
$msgToSend .= "Message: ".$message;
$recipient = RECIPIENT_NAME . " <" . RECIPIENT_EMAIL . ">";
$headers = "From: " . $senderName . " <" . $senderEmail . ">";
$success = mail( $recipient, EMAIL_SUBJECT, $msgToSend, $headers );
}
太多的代码。您需要自己更好地解决这个问题。我们不是调试器。您需要隔离问题并从中进行调试。如果你陷入困境，请清楚地解释什么东西不适合你。我建议阅读一个好的问题，并对问题进行修改，以便更好地理解。。。