Javascript 如何知道是否正在src="；内调用php文件&引用；？
在我的网站上我有Javascript 如何知道是否正在src="；内调用php文件&引用；？,javascript,php,src,Javascript,Php,Src,在我的网站上我有 <script src="js.php"></script> 问题很简单，但我不知道答案： 在js.php中，如何检查文件是否已通过脚本src=“…”调用 其目的是根据调用此php脚本文件的方式（直接访问或脚本src=“…”）更改返回的js.php HTML代码。方法是在调用js.php文件之前将会话变量赋值为true session_start(); $_SESSION['src'] = true; <script src="js.php"
<script src="js.php"></script>
其目的是根据调用此php脚本文件的方式（直接访问或脚本src=“…”）更改返回的js.php HTML代码。方法是在调用js.php文件之前将会话变量赋值为true
session_start();
$_SESSION['src'] = true;
<script src="js.php"></script>
很酷的问题。让我来帮你 我将在这里提供一些非100%可靠的方法，这些方法将在标准的非用户恶意案例中工作 弗斯特 对于此解决方案，您需要从下载mimeparser。您可以选择要使用哪种MIME解析器，我发现这只是为了回答这个问题 理论 理论上，浏览器正在发送头，响应期间脚本应该匹配头，以便进行适当的浏览器端解析。特别是在这里，我想到了
HTTP\u ACCEPTtest.php<?php // test.php
//https://code.google.com/p/mimeparse/
include_once('mimeparse.php');
$mimeMatch = Mimeparse::best_match(array('text/javascript', 'text/css', 'text/html', 'application/xhtml+xml', 'application/xml', 'image/*'), $_SERVER['HTTP_ACCEPT']);
switch($mimeMatch) {
case 'text/javascript': // via <script src>
echo('alert("this is loaded as script");');
break;
case 'image/*': // via <image src>
header('Location: http://i.stack.imgur.com/sOq8x.jpg?s=128&g=1');
break;
case 'text/css': // via <link href>
echo('body::before{content: "this is written via CSS"}');
break;
default:
var_dump('detected standard file request by matching to ' . $mimeMatch);
// if __FILE__ is first on a list, its not included
if(__FILE__ !== array_shift(get_included_files())) {
var_dump('file was included or required');
} else {
var_dump('file runs on its own');
}
// additional detect for ajax request.
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
var_dump('loaded via AJAX request');
} else {
var_dump('loaded via not-AJAX request');
}
break;
}
die();
<html>
<head>
<link rel="stylesheet" type="text/css" href="test.php"/>
</head>
<body>
<script src="test.php"></script>
<img src="test.php"></img>
<?php require('test.php'); ?>
index.php<?php // test.php
//https://code.google.com/p/mimeparse/
include_once('mimeparse.php');
$mimeMatch = Mimeparse::best_match(array('text/javascript', 'text/css', 'text/html', 'application/xhtml+xml', 'application/xml', 'image/*'), $_SERVER['HTTP_ACCEPT']);
switch($mimeMatch) {
case 'text/javascript': // via <script src>
echo('alert("this is loaded as script");');
break;
case 'image/*': // via <image src>
header('Location: http://i.stack.imgur.com/sOq8x.jpg?s=128&g=1');
break;
case 'text/css': // via <link href>
echo('body::before{content: "this is written via CSS"}');
break;
default:
var_dump('detected standard file request by matching to ' . $mimeMatch);
// if __FILE__ is first on a list, its not included
if(__FILE__ !== array_shift(get_included_files())) {
var_dump('file was included or required');
} else {
var_dump('file runs on its own');
}
// additional detect for ajax request.
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
var_dump('loaded via AJAX request');
} else {
var_dump('loaded via not-AJAX request');
}
break;
}
die();
<html>
<head>
<link rel="stylesheet" type="text/css" href="test.php"/>
</head>
<body>
<script src="test.php"></script>
<img src="test.php"></img>
<?php require('test.php'); ?>
使用Apache服务和Chrome阅读进行测试。不应习惯使用
=true“true”获取包含的文件（）