Javascript 使用querySelectorAll从html页面提取latex方程块

Javascript 使用querySelectorAll从html页面提取latex方程块,javascript,jquery,html,Javascript,Jquery,Html,我尝试从HTML页面(使用latex2html生成)中提取latex方程公式,以便用mathjax公式替换latex方程图像 首先,我有以下想法,这里有一个例子: <div align="CENTER" class="mathdisplay"><a name="eq407"></a><!-- MATH \begin{equation} \text{d}\,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M'

我尝试从HTML页面(使用
latex2html
生成)中提取latex方程公式,以便用
mathjax
公式替换latex方程图像

首先,我有以下想法,这里有一个例子:

<div align="CENTER" class="mathdisplay"><a name="eq407"></a><!-- MATH
 \begin{equation}
\text{d}\,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mathbf{n}-\mathbf{V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=\text{d}\,\mathbf{V}\,\cdot\,\mathbf{n}
\end{equation}
 -->
<table class="equation" cellpadding="0" width="100%" align="CENTER">
<tr valign="MIDDLE">
<td nowrap align="CENTER"><span class="MATH">d<img width="538" height="38" align="MIDDLE" border="0" src="img1929.gif" alt="$\displaystyle \,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mat...
...V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=$">d<img width="56" height="34" align="MIDDLE" border="0" src="img1930.gif" alt="$\displaystyle \,\mathbf{V}\,\cdot\,\mathbf{n}$"></span></td>
<td nowrap class="eqno" width="10" align="RIGHT">
(<span class="arabic">5</span>.<span class="arabic">70</span>)</td></tr>
</table></div>
输入:

  <div align="CENTER" class="mathdisplay"><a name="eq402"></a><!-- MATH
 \begin{equation}
\text{d}\,v_{k}=\partial_{j}\,v_{k}\,\dfrac{\text{d}\,y^{j}}{\text{d}\,s}\,\text{d}\,s
\end{equation}
 -->
<table class="equation" cellpadding="0" width="100%" align="CENTER">
<tr valign="MIDDLE">
<td nowrap align="CENTER"><span class="MATH">d<img width="150" height="65" align="MIDDLE" border="0" src="img1919.gif" alt="$\displaystyle \,v_{k}=\partial_{j}\,v_{k}\,\dfrac{\text{d}\,y^{j}}{\text{d}\,s}\,\text{d}\,s$"></span></td>
<td nowrap class="eqno" width="10" align="RIGHT">
(<span class="arabic">5</span>.<span class="arabic">65</span>)</td></tr>
</table></div>
这可能足够了,但我注意到,有时在HTML页面中,我为“
alt
”属性设置了一个不完整的公式,下面是一个示例:

<div align="CENTER" class="mathdisplay"><a name="eq407"></a><!-- MATH
 \begin{equation}
\text{d}\,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mathbf{n}-\mathbf{V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=\text{d}\,\mathbf{V}\,\cdot\,\mathbf{n}
\end{equation}
 -->
<table class="equation" cellpadding="0" width="100%" align="CENTER">
<tr valign="MIDDLE">
<td nowrap align="CENTER"><span class="MATH">d<img width="538" height="38" align="MIDDLE" border="0" src="img1929.gif" alt="$\displaystyle \,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mat...
...V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=$">d<img width="56" height="34" align="MIDDLE" border="0" src="img1930.gif" alt="$\displaystyle \,\mathbf{V}\,\cdot\,\mathbf{n}$"></span></td>
<td nowrap class="eqno" width="10" align="RIGHT">
(<span class="arabic">5</span>.<span class="arabic">70</span>)</td></tr>
</table></div>
任何帮助都很好

您可以使用本机支持实用节点过滤策略的,如
NodeFilter.SHOW\u COMMENT

var walker=document.createTreeWalker(
document.documentElement,
NodeFilter.SHOW\u注释
),
frag=document.createDocumentFragment(),
li,节点;
while(node=walker.nextNode()){
li=document.createElement('li');
li.textContent=node.textContent;
frag.appendChild(李);
}
document.getElementById('comment-list').appendChild(frag)

<div align="CENTER" class="mathdisplay"><a name="eq407"></a><!-- MATH
 \begin{equation}
\text{d}\,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mathbf{n}-\mathbf{V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=\text{d}\,\mathbf{V}\,\cdot\,\mathbf{n}
\end{equation}
 -->
<table class="equation" cellpadding="0" width="100%" align="CENTER">
<tr valign="MIDDLE">
<td nowrap align="CENTER"><span class="MATH">d<img width="538" height="38" align="MIDDLE" border="0" src="img1929.gif" alt="$\displaystyle \,(\mathbf{V}\,\cdot\,\mathbf{n})=\mathbf{V_{M}}(M')\,\cdot\,\mat...
...V}(M)\,\cdot\,\mathbf{n}=[\mathbf{V_{M}}(M')-\mathbf{V}(M)]\,\cdot\,\mathbf{n}=$">d<img width="56" height="34" align="MIDDLE" border="0" src="img1930.gif" alt="$\displaystyle \,\mathbf{V}\,\cdot\,\mathbf{n}$"></span></td>
<td nowrap class="eqno" width="10" align="RIGHT">
(<span class="arabic">5</span>.<span class="arabic">70</span>)</td></tr>
</table></div>
 var text = document.createTextNode(puretext);
                    img.parentNode.insertBefore(text, img);
                    img.style.display = 'none';