Javascript筛选器方法不使用if和else if

我有一个包含多（10）个对象的对象

1对象如下所示：

bracket: null
bracket_id: null
game_site: null
game_site_id: null
id: 88462
next_game_for_loser: null
next_game_for_loser_id: null
next_game_for_winner: null
next_game_for_winner_id: null
next_team_for_loser: 1
next_team_for_winner: 1
number_of_sets: 5
pool: Object
pool_id: 18739
pool_round: Object
pool_round_id: 21984
season: Object
season_id: 20167
start_time: "2013-03-04T13:00:00+01:00"
swiss_round: null
swiss_round_id: null
team_1: Object
team_1_id: 21202
team_1_score: 3
team_2: Object
team_2_id: 21206
team_2_score: 1
time_created: "2012-12-09T12:46:33.626319+00:00"
time_last_updated: "2012-12-09T12:46:33.626361+00:00"
timezone: "Europe/Amsterdam"
tournament: Object
tournament_id: 18519
winner: Object
winner_id: 21202

var inverted;
var game = games.objects.filter(function (gameInfo) { 
    if (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID) {
        inverted = 0;
        return true;
    } else if (gameInfo.team_1_id == team2ID && gameInfo.team_2_id == team1ID) {
        inverted = 1;
        return true;
    } // else
        return false;
});

// Shorter, using the comma operator:

var game = games.objects.filter(function (gameInfo) { 
    return (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID && (inverted = 1, true)
        || (gameInfo.team_1_id == team2ID && gameInfo.team_2_id == team1ID && (inverted = 0, true);
});

我想过滤匹配上的对象（团队id）

我喜欢这样：

var game = games.objects.filter(function (gameInfo) { 

            if (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID) {
                return (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID) && (inverted = 1);
            } 

            else if (gameInfo.team_1_id == team2ID && gameInfo.team_2_id  == team1ID) {
                return (gameInfo.team_1_id == team2ID && gameInfo.team_2_id  == team1ID) && (inverted = 0);
            }
        });

我有两个变量来设置团队id：

var team1ID = 21206;
var team2ID = 21202;

我希望filter函数返回与teamID1和teamID2匹配的特定对象。如果

gameInfo.team\u 1\u id==team1ID&&gameInfo.team\u 2\u id==team2ID

但是当我这样反转它时：

else如果（gameInfo.team\u 1\u id==team2ID&&gameInfo.team\u 2\u id==team1ID）

那么对象

game

总是空的……为什么

(inverted = 0)

这里是赋值，不是比较。结果值（

0

）将始终为falsy，并且过滤器函数将返回一个空的

game

数组

此外，您还应首先检查

倒

标志，不要重复其他不必要的比较：

var game = games.objects.filter(function (gameInfo) { 
    return inverted == 1
      ? gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID
      : gameInfo.team_1_id == team2ID && gameInfo.team_2_id == team1ID;
});

如果要设置它，它应该如下所示：

bracket: null
bracket_id: null
game_site: null
game_site_id: null
id: 88462
next_game_for_loser: null
next_game_for_loser_id: null
next_game_for_winner: null
next_game_for_winner_id: null
next_team_for_loser: 1
next_team_for_winner: 1
number_of_sets: 5
pool: Object
pool_id: 18739
pool_round: Object
pool_round_id: 21984
season: Object
season_id: 20167
start_time: "2013-03-04T13:00:00+01:00"
swiss_round: null
swiss_round_id: null
team_1: Object
team_1_id: 21202
team_1_score: 3
team_2: Object
team_2_id: 21206
team_2_score: 1
time_created: "2012-12-09T12:46:33.626319+00:00"
time_last_updated: "2012-12-09T12:46:33.626361+00:00"
timezone: "Europe/Amsterdam"
tournament: Object
tournament_id: 18519
winner: Object
winner_id: 21202

var inverted;
var game = games.objects.filter(function (gameInfo) { 
    if (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID) {
        inverted = 0;
        return true;
    } else if (gameInfo.team_1_id == team2ID && gameInfo.team_2_id == team1ID) {
        inverted = 1;
        return true;
    } // else
        return false;
});

// Shorter, using the comma operator:

var game = games.objects.filter(function (gameInfo) { 
    return (gameInfo.team_1_id == team1ID && gameInfo.team_2_id == team2ID && (inverted = 1, true)
        || (gameInfo.team_1_id == team2ID && gameInfo.team_2_id == team1ID && (inverted = 0, true);
});

---

是的，目的是将一个值赋给“inversed”，当inversed=1时，我做某事，当inversed=0时，我做其他事情。稍后在我的代码中，我想知道TeamID何时被反转。因此，当gameInfo.team_1_id==team2ID&&gameInfo.team_2_id==team1id时，请参见。我仍然不知道为什么要使用

过滤器

然后返回特定对象（与过滤器匹配）并查看团队是否反转。是的，我的最后两个片段就是这样做的，不是吗？