Javascript 使用下拉按钮更新choropleth贴图
首先,请原谅我英语不好。Javascript 使用下拉按钮更新choropleth贴图,javascript,csv,d3.js,Javascript,Csv,D3.js,首先,请原谅我英语不好。 我正在做一个带有栅格地图和外部csv的项目 栅格地图不是由矩形或六边形组成的,而是只有将在最后使用的任何类型符号的质心。 所以我有一个带有质心“ID”和质心“坐标”的Topojson文件 外部CSV由若干列组成,第一列具有相同的质心“ID”,另一列具有不同年份的值 "ID","C2001","C2002","C2003","C2004","C2005","C2006","C2007","C2008","C2009","C2010","C2000" 6050,"-5.55
我正在做一个带有栅格地图和外部csv的项目 栅格地图不是由矩形或六边形组成的,而是只有将在最后使用的任何类型符号的质心。
所以我有一个带有质心“ID”和质心“坐标”的Topojson文件 外部CSV由若干列组成,第一列具有相同的质心“ID”,另一列具有不同年份的值
"ID","C2001","C2002","C2003","C2004","C2005","C2006","C2007","C2008","C2009","C2010","C2000"
6050,"-5.55753","-5.55914","-5.75444","-5.76307","-5.81660","-5.99361","-6.02150","-6.15979","-5.73530","-6.30509","-5.52990"
6051,"-5.55753","-5.55914","-5.75444","-5.76307","-5.81660","-5.99361","-6.02150","-6.15979","-5.73530","-6.30509","-5.52990"
这是我的密码
var width = 960,
height = 600;
var options = [
{date: "2000", selected: "+d.C2000"},
{date: "2001", selected: "+d.C2001"},
{date: "2002", selected: "+d.C2002"},
{date: "2003", selected: "+d.C2003"},
{date: "2004", selected: "+d.C2004"},
{date: "2005", selected: "+d.C2005"},
{date: "2006", selected: "+d.C2006"},
{date: "2007", selected: "+d.C2007"},
{date: "2008", selected: "+d.C2008"},
{date: "2009", selected: "+d.C2009"},
{date: "2010", selected: "+d.C2010"},
];
var color = d3.scale.threshold()
.domain([-1985, -1400, -1000, -700, -300, -100, -25, -0])
.range(["#7f0000", "#b30000", "#d7301f", "#ef6548", "#fc8d59", "#fdbb84", "#fdd49e", "#fee8c8", "#fff7ec"]);
var path = d3.geo.path()
.projection(null)
.pointRadius(1.5);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
queue()
.defer(d3.json, "CO2_light.json")
.defer(d3.csv, "tdd_CO2_emissions.csv")
.await(ready);
function ready(error, centroid, CO2) {
var rateById = {};
console.log(rateById); //To
//CO2.forEach(function(d) { rateById[+d.ID] = +d.C2000; }); WORKING FINE = value in rateById
CO2.forEach(function(d) { rateById[+d.ID] = options[0].selected; }); //NOT WORKING = inside rateById "+d.C2000" instead the value
svg.selectAll("path")
.data(topojson.feature(centroid, centroid.objects.CENTROID).features)
.enter().append("path")
.attr("class", "centerGrid")
.attr("d", path)
.style("fill", function(d) { return color(rateById[+d.properties.ID]); });
d3.select(".loading").remove();
现在我把下一个问题的按钮留下,我的注意力集中在下面这两行
//CO2.forEach(function(d) { rateById[+d.ID] = +d.C2000; }); WORKING FINE = value in rateById
CO2.forEach(function(d) { rateById[+d.ID] = options[0].selected; }); //NOT WORKING = inside rateById "+d.C2000" instead the value
如果我使用第一行,我会得到一个很好的网格图(),但是如果我试图用第二行和doconsole.log(rateById)从options
数组访问特定年份的值代码>我明白了
Object
6050: "+d.C2000"
6051: "+d.C2000"
6712: "+d.C2000"
而不是这个
Object
6050: -6.30509
6051: -6.30509
6712: -7.0441
修正如下:
代码中要做的2项更改:
首先,您选择的选项不应包含要执行的javascript代码(+d.
),而应仅包含年份值:
var options = [
{date: "2000", selected: "C2000"},
{date: "2001", selected: "C2001"},
{date: "2002", selected: "C2002"},
{date: "2003", selected: "C2003"},
{date: "2004", selected: "C2004"},
{date: "2005", selected: "C2005"},
{date: "2006", selected: "C2006"},
{date: "2007", selected: "C2007"},
{date: "2008", selected: "C2008"},
{date: "2009", selected: "C2009"},
{date: "2010", selected: "C2010"}
];
然后在循环中,通过访问所选年份的数据d
属性来分配rateById
值,如下所示:
rateById[+d.ID]=+d[选项[0]。选中]代码>
注意:我必须删除JSFIDLE中的部分代码,因为在您的JSFIDLE版本中找不到json质心,导致与此问题无关的错误。rateById[+d.ID]=options[0]。选中代码>只执行您要求它执行的操作。选项[0]的值。所选为“+d.C2000”。您希望查找CO2文件的值,为此,您需要正确格式化csv文件数据(在对象中,以便能够基于年份和质心Id访问值)。您是否介意创建一个JSFIDLE以使其更容易帮助您?它是这样的:Thank a lotIs是rateById函数中必需的+d.ID加号?.ID值是非整数。你不需要ID的+号,你可以去掉它。你回答得太快了,我现在不能在那里。它的工作就像一个魅力!谢谢你!(法语)