在Javascript对象中显示字典
我正在从服务器返回此响应:在Javascript对象中显示字典,javascript,dictionary,Javascript,Dictionary,我正在从服务器返回此响应: callback({"City": "Miami", "State": "FL", "Street": "9th Street", "Name": "Big 12", "Zip": "65201", "Lat": -48.219999999999999, "Telephone": "5732168906", "Long": 32.0, "Events": "[{\"End Time\": \"2011-01-22 23:36:31\", \"Name\": \"Mar
callback({"City": "Miami", "State": "FL", "Street": "9th Street", "Name": "Big 12", "Zip": "65201", "Lat": -48.219999999999999, "Telephone": "5732168906", "Long": 32.0, "Events": "[{\"End Time\": \"2011-01-22 23:36:31\", \"Name\": \"Margaritas\", \"Start Time\": \"2011-01-22 15:36:31\"}, {\"End Time\": \"2011-01-22 19:36:39\", \"Name\": \"Dollar Bottles\", \"Start Time\": \"2011-01-22 15:36:39\"}, {\"End Time\": \"2011-01-23 23:36:31\", \"Name\": \"All You Can Drink\", \"Start Time\": \"2011-01-23 15:36:31\"}]"})
这里是我试图解析响应并在“今晚列表”中显示它的地方。使用data.Events,我可以在屏幕上显示整个字典数组
function callback(data){
console.log(data);
$("#tonight-list").append("<li role='option' tabindex='0' class='ui-li ui-li-static ui-btn-up-c'>Starts:" +
data.Events +
"<li>");
函数回调(数据){
控制台日志(数据);
$(“#今晚列表”).append(开始:“+
数据.事件+
“ ”;
但是,我不知道如何访问每个元素(开始时间、结束时间、名称等)。当我尝试data.Events[0]时,它只给出data.Events中的第一个字符
如何访问事件数组中的每个字典键?我只是想不出语法-如果我能看到此对象类型的所有选项,那就太好了。提前感谢您的帮助!JSON dude!只需从服务器返回有效的JSON并使用evalJSON。然后您就可以通过相应的键访问每个对象 编辑: 基本上是
data.responseText.evalJSON();将JSON响应中的
事件设置为实数组,而不是字符串,然后您可以这样使用它:
var obj = JSON.parse(reponseText);
var event = obj.Events[0];
alert(event["End Time"]); // hurray
JSON响应
callback({
"City": "Miami",
"State": "FL",
"Street": "9th Street",
"Name": "Big 12",
"Zip": "65201",
"Lat": -48.219999999999999,
"Telephone": "5732168906",
"Long": 32.0,
"Events": [{
"End Time": "2011-01-22 23:36:31",
"Name": "Margaritas",
"Start Time": "2011-01-22 15:36:31"
},
{
"End Time": "2011-01-22 19:36:39",
"Name": "Dollar Bottles",
"Start Time": "2011-01-22 15:36:39"
},
{
"End Time": "2011-01-23 23:36:31",
"Name": "All You Can Drink",
"Start Time": "2011-01-23 15:36:31"
}]
});
我知道我需要这样的东西!每当我调用data.evalJSON()时;它声明对象没有evalJSON方法。我需要返回与服务器不同的内容吗?content_type='application/javascript;charset=utf-8'是我当前返回的内容。application/json或者您可以返回文本响应。无论哪种方式,您都需要从响应对象获取responseText。谢谢galambalazs!Changing var obj=JSON.parse(data.Events)的第一行;使一切按需工作:)