Javascript Wordpress-针对单个帖子,而不是帖子类型。AJAX/PHP
我试图在单击文章标题时将单击时的单个文章信息加载到页面中。我已经设法让我的脚本在帖子数组中循环浏览标题,然后单击将帖子标题再次加载到一个div中。我希望这样做是为了在单击时加载单个帖子信息 PHP Post数组函数-Javascript Wordpress-针对单个帖子,而不是帖子类型。AJAX/PHP,javascript,php,ajax,wordpress,Javascript,Php,Ajax,Wordpress,我试图在单击文章标题时将单击时的单个文章信息加载到页面中。我已经设法让我的脚本在帖子数组中循环浏览标题,然后单击将帖子标题再次加载到一个div中。我希望这样做是为了在单击时加载单个帖子信息 PHP Post数组函数- add_action( "wp_ajax_success_stories", "sa_get_paginated_posts" ); add_action( "wp_ajax_nopriv_success_stories", "sa_get_paginated_posts" );
add_action( "wp_ajax_success_stories", "sa_get_paginated_posts" );
add_action( "wp_ajax_nopriv_success_stories", "sa_get_paginated_posts" );
function sa_get_paginated_posts(){
$args = array(
'posts_per_page' => -1,
'post_type' => 'success-stories',
'orderby' => 'post_date',
'order' => 'DESC'
);
$the_query = new WP_Query( $args );
$queryitems = $the_query->get_posts();
$alldata = array();
if ($queryitems){
foreach ($queryitems as $query_item){
$success_story = array();
$success_story["ID"] = $query_item->ID;
$success_story["title"] = $query_item->post_title;
$alldata[] = $success_story;
}
}
$encoded_data = json_encode($alldata);
echo $encoded_data;
die();
}
function sa_get_posts($post_amount, $post_type){
$args = array(
'posts_per_page' => $post_amount,
'post_type' => $post_type,
'offset' => 0,
'orderby' => 'post_date',
'order' => 'ASC'
);
使用此函数循环通过-
<? if ($success_stories): //success story posts ?>
<ul class="small-block-grid-3">
<? foreach ($success_stories as $success_story):
$title = $success_story->post_title; ?>
<li><a data-id="<? echo $success_story->ID; ?>" class="success-extra" href="#" title=""><? echo $title; ?></a></li>
<? endforeach; ?>
</ul>
<div id="success-list"></div>
<a class="success-close" href="#" title="">CLOSE</a>
<? endif; ?>
Javascript/AJAX调用
var $json_response_box = $("#success-list");
function get_ajax_success_posts() {
//this line gets the id attribute from the link
var current_story = $(this).attr("data-id");
console.log(current_story);
jQuery.ajax({
type: "GET",
url: "WORDPRESSDIRECTORY/admin-ajax.php",
cache: true,
data: {
action: "success_stories"
},
dataType: "JSON",
success: function(data) {
var arrayLength = data.length;
for (var i = 0; i < arrayLength; i++) {
var success_id = data[i].ID;
var success_title = data[i].title;
console.log(success_id);
story = '<ul>';
story += '<li>';
story += success_title;
story += '</li>';
story += '</ul>';
$json_response_box.append(story).fadeIn(1000);
}
},
error: function(errorThrown) {
console.log("fail-posts");
}
});
}
var$json_response_box=$(“#成功列表”);
函数get\u ajax\u success\u posts(){
//此行从链接中获取id属性
var current_story=$(this.attr(“数据id”);
console.log(当前_故事);
jQuery.ajax({
键入:“获取”,
url:“WORDPRESSDIRECTORY/admin ajax.php”,
是的,
数据:{
行动:“成功故事”
},
数据类型:“JSON”,
成功:功能(数据){
var arrayLength=data.length;
对于(变量i=0;i”;
故事+=“”;
故事+=成功与头衔;
故事+=' ';
故事+=””;
$json\u response\u box.append(story).fadeIn(1000);
}
},
错误:函数(错误抛出){
控制台日志(“失败日志”);
}
});
}
感谢您的建议
D如果我正确理解了您的问题,您只需添加另一个php函数和AJAX调用,就可以在单击时获得帖子,类似这样的内容(我还添加了nonce以添加一些secutiry,将其添加到AJAX调用中总是一个好主意) HTML: JS:
希望这能有所帮助。嗯,我不太明白。你的PHP代码是什么?您可以轻松地将数据id添加到标题中,单击“通过AJAX将其提交到您的插件”,使用get_post($id)获取帖子详细信息并将其返回到AJAX成功函数……您好,我刚刚用所使用的PHP函数更新了帖子。我只是想知道如何编辑AJAX函数来针对特定的帖子。是的,关于这个问题,代码多于解释。我不明白这一点:“我希望这是加载个人张贴信息,而不是点击”。阅读代码不会告诉我任何问题。观察结果:1)函数sa_get_posts()与问题有什么关系?2) 我只需要做
$queryitems=get_posts($args)代码>完美答案,非常感谢
<li><a data-id="<? echo $success_story->ID; ?>" data-nonce="<?php wp_create_nonce('get_post'.$success_story->ID); ?>" class="success-extra" href="#" title=""><? echo $title; ?></a></li>
add_action( "wp_ajax_sa_get_post", "sa_get_post" );
add_action( "wp_ajax_nopriv_sa_get_post", "sa_get_post" );
function sa_get_post(){
if ( ! wp_verify_nonce( $nonce, 'get_post_'.$POST['id'] ) ) {
// This nonce is not valid.
$response['status'] = 'fail';
} else {
// The nonce was valid.
$post = get_post($POST['id']);
$response['status'] = 'success';
$response['post'] = $post;
}
echo json_encode($response);
exit(); // this is needed, as otherwise the AJAX returns an extra 0
}
$('.success-extra').on('click', function () {
jQuery.ajax({
type: "POST",
url: "WORDPRESSDIRECTORY/admin-ajax.php",
cache: false,
data: {
action: "sa_get_post",
id: $(this).attr('data-id'),
nonce: $(this).attr('data-nonce')
},
success: function(data) {
var result = $.parseJSON(data);
if (result.status != 'success') {
// display error messago or something
} else {
// do whatever you want with your result.post
}
}
})