Javascript jquery fancytree在检查时加载并检查所有子节点
我正在使用fancytree插件创建一个树视图。我所有的数据都是通过ajax和json加载到expand上的。如果用户检查父节点,我也会在代码中加载子节点,因为如果该节点没有首先展开,它们在技术上不会加载 我的问题是,如果你的父子关系有三个层次,然后扩展到第二层次,第三层次就不会被检查 本质上我有这样的东西Javascript jquery fancytree在检查时加载并检查所有子节点,javascript,jquery,fancytree,Javascript,Jquery,Fancytree,我正在使用fancytree插件创建一个树视图。我所有的数据都是通过ajax和json加载到expand上的。如果用户检查父节点,我也会在代码中加载子节点,因为如果该节点没有首先展开,它们在技术上不会加载 我的问题是,如果你的父子关系有三个层次,然后扩展到第二层次,第三层次就不会被检查 本质上我有这样的东西 Parent1 -->Child1 ---->Child1-1 ---->Child1-2 ---->Child1-3 -->Child2 现在,如果您从未展
Parent1
-->Child1
---->Child1-1
---->Child1-2
---->Child1-3
-->Child2
现在,如果您从未展开父节点并选中它,则所有节点都将被加载并选中。但是,如果展开“父节点1”以显示子节点1和2,则选中“父节点1”。子节点1-1到3永远不会被加载或选中。下面是我必须在检查时加载子节点的代码,我遗漏了什么
select: function (event, data) { //here's where I need to load the children for that node, if it has them, so they can be set to checked
var node = data.node;
//alert(node.key);
if (node.isSelected()) {
if (node.isUndefined()) {
// Load and select all child nodes
node.load().done(function () {
node.visit(function (childNode) {
childNode.setSelected(true);
});
});
} else {
// Select all child nodes
node.visit(function (childNode) {
childNode.setSelected(true);
});
}
// Get a list of all selected nodes, and convert to a key array:
var selKeys = $.map(data.tree.getSelectedNodes(), function (node) {
treeHash[node.data.treeItemType + node.key] = node.key;
});
}
这里是我的完整JS仅供参考
if ($("entityTree") != null) {
$(function () {
// Create the tree inside the <div id="tree"> element.
$("#entityTree").fancytree({
source: { url: "/Home/GetTreeViewData", cache: true }
, checkbox: true
, icons: false
, cache: true
, lazyLoad: function (event, data) {
var node = data.node;
data.result = {
url: "/Home/GetTreeViewData/" + node.key.replace(node.data.idPrefix, "")
, data: { mode: "children", parent: node.key }
, cache: true
};
}
, renderNode: function (event, data) {
// Optionally tweak data.node.span
var node = data.node;
var $span = $(node.span);
if (node.key != "_statusNode") {
$span.find("> span.fancytree-expander").css({
borderLeft: node.data.customLeftBorder
//borderLeft: "1px solid orange"
});
}
}
, selectMode: 3
, select: function (event, data) { //here's where I need to load the children for that node, if it has them, so they can be set to checked
var node = data.node;
//alert(node.key);
if (node.isSelected()) {
if (node.isUndefined()) {
// Load and select all child nodes
node.load().done(function () {
node.visit(function (childNode) {
childNode.setSelected(true);
});
});
} else {
// Select all child nodes
node.visit(function (childNode) {
childNode.setSelected(true);
});
}
// Get a list of all selected nodes, and convert to a key array:
var selKeys = $.map(data.tree.getSelectedNodes(), function (node) {
treeHash[node.data.treeItemType + node.key] = node.key;
});
}
else {
delete treeHash[node.data.treeItemType + node.key];
//alert("remove " + node.key);
}
for (var i in treeHash) {
alert(treeHash[i]);
}
}
, strings: {
loading: "Grabbing places and events…",
loadError: "Load error!"
},
})
});
}
试试这个,让我知道是否有效。我们需要加载已经加载的子节点的未定义子节点
if (node.isSelected()) {
if (node.isUndefined()) {
// Load and select all child nodes
node.load().done(function () {
node.visit(function (childNode) {
childNode.setSelected(true);
});
});
} else {
// Select all child nodes
node.visit(function (childNode) {
childNode.setSelected(true);
if (childNode.isUndefined()) {
// Load and select all child nodes
childNode.load().done(function () {
childNode.visit(function (itschildNode) {
itschildNode.setSelected(true);
});
});
}
});
}
}