Javascript 如何发送php选择框值？

如附图所示，将输出以下代码。

在test16中选择Select框的值，然后按“test19”按钮，这是要修改的Select框的值。 我想知道如何在php中传递选择框的值，以及如何接收传递的值

<?php


    if($result = mysqli_query($link, $sql)){               

            $test = 'test';
            if(mysqli_num_rows($result) > 0){

            echo "<table id='datatable1' class = table style = 'width: 100%; background-color:#dee2e6'>";
                echo "<thead >";
                echo "<tr>";
                echo "<th>No</th>";
                echo "<th>test1</th>";
                echo "<th>test2</th>";
                echo "<th>test3</th>";
                echo "<th>test4</th>";      
                echo "<th>test5</th>"; 
                echo "<th>test6</th>";
                echo "<th>test7</th>";
                echo "<th>test8</th>";                                                      
                echo "<th>test9</th>"; 
                echo "<th>test10</th>";
                echo "<th>test11</th>";
                echo "<th>test12</th>";
                echo "<th>test13</th>";
                echo "<th>test14</th>";
                echo "<th>test15</th>";
                echo "<th>test16</th>";
                echo "<th>test17</th>"; 
                echo "<th>test18</th>";  
                echo "<th>test19</th>";                                           
                echo "</tr>";
                echo "</thead>";

                echo "<tbody>";
            while($row = mysqli_fetch_array($result)){
                echo "<tr>";
                echo "<td>" . $row['id'] . "</td>";
                echo "<td>" . $row['chart_num'] . "</td>"; 
                echo "<td>" . $row['chart_name'] . "</td>";                                        
                echo "<td>" . $row['visit'] . "</td>";
                echo "<td>" .  number_format($row['total_medical_bills']) . "</td>";
                echo "<td>" .  number_format($row['total_amount']) . "</td>";   
                echo "<td>" .  number_format($row['amount_asked']) . "</td>";
                echo "<td  style = 'font-weight: bold'>" .  number_format($row['medical_bills_payment']) . "</td>";
                echo "<td  style = 'font-weight: bold'>" .  number_format($row['personal_liability_amount']) . "</td>";                                                  
                echo "<td  style = 'font-weight: bold'>" .  number_format($row['non_payment']) . "</td>";
                echo "<td>" . $row['insurance_division'] . "</td>";
                echo "<td>" . $row['division'] . "</td>";
                echo "<td>" .  number_format($row['cash_amount_received']) . "</td>";
                echo "<td>" .  number_format($row['card_amount_received']) . "</td>";
                echo "<td style = 'font-weight: bold'>" .  number_format($row['treatment_fees_difference']) . "</td>";
                echo "<td>" . $row['treatment_fees_check_division'] . "</td>";


                echo "<td><select name='". $test ."'>";
                echo "<option value='". $test ."'>First</option>";
                echo "<option value='". $test ."'>Second</option>";
                echo "<option value='". $test ."'>Third</option>";
                echo "</select></td>";



                echo "<td>" . $row['treatment_fees_check'] . "</td>";
                echo "<td>" . $row['treatment_fees_check_modify'] . "</td>";
                echo "<td>";                                          

                    if($row['medical_bills_payment'] == $row['personal_liability_amount'] + $row['non_payment']){ 
                            echo "수정불가";
                    }

                    else{                    
                            echo "<a href='treatment_fees_check_update.php?id=". $row['id'] ." title='수정' data-toggle='tooltip'><span class='icon ion-edit'></span></a>";
                    }
                echo "</td>";

                echo "</tr>";
            }


                echo "</tbody>";                            
                echo "</table>";

                mysqli_free_result($result);                                  
            } 


        }     

    else{
    echo "ERROR: Could not able to execute $sql2. " . mysqli_error($link);
    } 

    // Close connection
    mysqli_close($link);   
?>

---

您需要的原则是为下拉列表中的每一个选项指定一个id，这样您就可以发送特定值的id，与数据库中的相同id进行比较（如果存在），然后您将在数据库中有一列包含需要修改的值，但是首先在选择框中为每个选项添加正确的id。
因为您可以有很多选择框，您需要给它们一个id，以便我们可以引用相应的字段。让我们添加/更改您的代码，如下所示：

$rowCount=0;
while($row = mysqli_fetch_array($result)){
                echo "<tr>";
                echo "<td>" . $row['id'] . "</td>";

                ...

                echo "<td><select id='MySelect".$rowCount."' name='". $test ."'>";
                echo "<option value='". $test ."'>First</option>";
                echo "<option value='". $test ."'>Second</option>";
                echo "<option value='". $test ."'>Third</option>";
                echo "</select></td>";

                ...

                echo "<td>";                                          

                if($row['medical_bills_payment'] == $row['personal_liability_amount'] + $row['non_payment']){ 
                            echo "수정불가";
                    }
                    else{                    
                            echo '<a href="javascript:GetMySelectValue(\'MySelect'.$rowCount.'\','.$row['id'].')" title="수정" data-toggle="tooltip"><span class="icon ion-edit"></span></a>';
                    }
                echo "</td>";

   $rowCount++;


希望它能帮助您。
您需要添加一些javascript代码。有几种方法可以做到这一点。1.在javascript代码中，您可以构建url，如处理费检查更新。php？id=xxx&field16=yyy。2.您可以使用表单提交。要做到这一点，你可以用标签包装一张桌子。详细解释请使用@Sandro Benevides的第一个答案。如果select标记的ID和“javascript:GetMySelectValue（xxxx，uuu）”中的ID字符串相同，他会写正确的代码；在关闭之前，同时阻塞。很抱歉我刚刚编辑了答案。
<script>
function GetMySelectValue(select,objId){
   document.location.href= "yoursite.com/treatment_fees_check_update.php?id="+objId+"&myselect="+document.getElementById(select).value;
}
</script>

$rowid=$_GET['id'];
$myselect=$_GET['myselect'];