Javascript 如何根据两个可能的值进行验证？

如何让下面的函数根据两个值进行验证。e、 g.将表格输入与man和stevesho.com匹配，而不仅仅是man

function access()
{
    if(document.getElementById('letters').value=='man')
        location.href='http://www.google.com'
    else if(document.getElementById('letters').value=='woman')
        location.href='http://www.dynamicdrive.com'
    else if(document.getElementById('letters').value=='cat')
        location.href='http://www.youtube.com'
    else if(document.getElementById('letters').value=='dog')
        location.href='http://www.dailymotion.com'
    else alert('Access denied. Try again.')
}

它可以是：

function access()
{
    var s = document.getElementById('letters').value;
    if(s =='man' || s = 'stevesho.com')
        location.href='http://www.google.com'
    else if(s =='woman')
        location.href='http://www.dynamicdrive.com'
    else if(s =='cat')
        location.href='http://www.youtube.com'
    else if(s =='dog')
        location.href='http://www.dailymotion.com'
    else alert('Access denied. Try again.')
}

---

你在找OR接线员吗？看

另一个可能感兴趣的选择

var key = document.getElementById('letters').value

var collection = {
    "key1" : "url1",
    "key2" : "url2",
    "key3" : "url3",
    "man" : "http://www.google.com",
    "stevesho.com" : "http://www.google.com"
};

if (collection[key]) {
    var url = collection[key];
    alert(key + " = " + url); // DEBUG
    //location.href = url;
}
else {
    alert("Access denied. Try again.");
}

---

你的问题不是很清楚。您的访问功能似乎正确。什么不起作用？关于你在一个分区的警报箱，我不明白。加上div联系表单是什么？我已经编辑了它，忘记了validationTry:var letters=document.getElementById'letters'.value；

var letter = document.getElementById('letters').value

if (letter == 'man' || letter == 'stevesho.com')
    location.href = 'http://www.google.com'

var key = document.getElementById('letters').value

var collection = {
    "key1" : "url1",
    "key2" : "url2",
    "key3" : "url3",
    "man" : "http://www.google.com",
    "stevesho.com" : "http://www.google.com"
};

if (collection[key]) {
    var url = collection[key];
    alert(key + " = " + url); // DEBUG
    //location.href = url;
}
else {
    alert("Access denied. Try again.");
}