Javascript 如何使用Jquery/Ajax调用将中的数据显示为表?
我使用Ajax/Jquery调用将数据集返回给客户端。我想将此数据显示为表格。但我不确定我怎么能做到这一点? 此外,我想添加一个可点击的链接按钮或在每一行的东西 服务器端:Javascript 如何使用Jquery/Ajax调用将中的数据显示为表?,javascript,jquery,asp.net,ajax,Javascript,Jquery,Asp.net,Ajax,我使用Ajax/Jquery调用将数据集返回给客户端。我想将此数据显示为表格。但我不确定我怎么能做到这一点? 此外,我想添加一个可点击的链接按钮或在每一行的东西 服务器端: [System.Web.Services.WebMethod] public static string GetPopUpDataWM() { //return "Hello " + name + Environment.NewLine + "The Current Time is: "
[System.Web.Services.WebMethod]
public static string GetPopUpDataWM()
{
//return "Hello " + name + Environment.NewLine + "The Current Time is: "
// + DateTime.Now.ToString();
DataTable table = new DataTable();
table.Columns.Add("Dosage", typeof(int));
table.Columns.Add("Drug", typeof(string));
table.Columns.Add("Patient", typeof(string));
table.Rows.Add(25, "Indocin", "David");
table.Rows.Add(50, "Enebrel", "Sam");
table.Rows.Add(10, "Hydralazine", "Christoff");
table.Rows.Add(21, "Combivent", "Janet");
table.Rows.Add(100, "Dilantin", "Melanie");
return JsonConvert.SerializeObject(table);
}
客户端:
<script type="text/javascript">
$(document).ready(function () {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "test1.aspx/GetPopUpDataWM",
data: "{}",
dataType: "json",
success: function (data) {
for (var i = 0; i < data.d.length; i++) {
Console.log(data.d[i].UserId);
$("#tbDetails").append("<tr><td>" + data.d[i].UserId + "</td><td>" + data.d[i].UserName + "</td><td>" + data.d[i].Location + "</td></tr>");
}
},
error: function (result) {
alert("Error");
}
});
});
</script>
<script type = "text/javascript">
</script>
<table id="tbDetails">
<tbody>
<tr>
<td>Code</td><td>Description</td>
</tr>
<tr>
<td>100</td><td>abc</td>
<td>101</td><td>mno</td>
<td>102</td><td>xyz</td>
</tr>
</tbody>
</table>
[{"Dosage":25,"Drug":"Indocin","Patient":"David"},
{"Dosage":50,"Drug":"Enebrel","Patient":"Sam"},
{"Dosage":10,"Drug":"Hydralazine","Patient":"Christoff"},
{"Dosage":21,"Drug":"Combivent","Patient":"Janet"},
{"Dosage":100,"Drug":"Dilantin","Patient":"Melanie"}]
请尝试var jObject=$(“#tbDetails”).find(“”).append(。。。
jObject.单击(您的函数);
但是,您不能使用data.d[i].UserId,但:
$.each(data, function( index, value ) {
echo value['Dosage']
});
还有一件事:您可以使用data.length et not data.d.length:)测试长度。您能告诉我们Ajax调用的响应吗?您到底遇到了什么问题?除了您使用的是
Console.log
而不是Console.log
,您的Javascript代码在我看来还不错。当然,Console.log
会抛出一个异常,而您的其余代码甚至不会执行。