Javascript d3.js共同特征图

Javascript d3.js共同特征图,javascript,d3.js,Javascript,D3.js,在创建一个关系图的过程中——显示了共同的特征——我正在努力创建与点的位置相匹配的曲线 绘制这些弧以使其下降到地平线以下的最佳方法是什么 var data = [{ "userName": "Rihanna", "userImage": "https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcSTzjaQlkAJswpiRZByvgsb3CVrfNNLLwjFHMrkZ_bzdPOWdxDE2Q", "use

在创建一个关系图的过程中——显示了共同的特征——我正在努力创建与点的位置相匹配的曲线

绘制这些弧以使其下降到地平线以下的最佳方法是什么

   var data = [{
     "userName": "Rihanna",
     "userImage": "https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcSTzjaQlkAJswpiRZByvgsb3CVrfNNLLwjFHMrkZ_bzdPOWdxDE2Q",
     "userDetails": [{
       "Skills & Expertise": [{
         "id": 2,
         "tag": "Javascript"
       }, {
         "id": 3,
         "tag": "Design"
       }],
       "Location": [{
         "id": 0,
         "tag": "London"
       }, {
         "id": 1,
         "tag": "Germany"
       }],
       "Company": [{
         "id": 0,
         "tag": "The Old County"
       }]
     }]
   }, {
     "userName": "Brad",
     "userImage": "https://lh3.googleusercontent.com/-XdASQvEzIzE/AAAAAAAAAAI/AAAAAAAAAls/5vbx7yVLDnc/photo.jpg",
     "userDetails": [{
       "Skills & Expertise": [{
         "id": 0,
         "tag": "JAVA"
       }, {
         "id": 1,
         "tag": "PHP"
       }, {
         "id": 2,
         "tag": "Javascript"
       }],
       "Location": [{
         "id": 0,
         "tag": "London"
       }],
       "Company": [{
         "id": 0,
         "tag": "The Old County"
       }, {
         "id": 1,
         "tag": "Bakerlight"
       }]
     }]
   }]



   var viz = d3.select("#viz")
     .append("svg")
     .attr("width", 600)
     .attr("height", 600)
     .append("g")
     .attr("transform", "translate(40,100)")


   var patternsSvg = viz
     .append('g')
     .attr('class', 'patterns');


   function colores_google(n) {
     var colores_g = ["#f7b363", "#448875", "#c12f39", "#2b2d39", "#f8dd2f"];
     return colores_g[n % colores_g.length];
   }


   function getRadius(d) {
     var count = d.commonTags.split(",").length;
     var ratio = count * 2.3;

     if (count == 1) {
       ratio = 8;
     }

     return ratio;
   }






   //create patterns for user images
   $.each(data, function(index, value) {
     var defs = patternsSvg.append('svg:defs');
     defs.append('svg:pattern')
       .attr('id', index + "-" + value.userName.toLowerCase())
       .attr('width', 1)
       .attr('height', 1)
       .append('svg:image')
       .attr('xlink:href', value.userImage)
       .attr('x', 0)
       .attr('y', 0)
       .attr('width', 75)
       .attr('height', 75);


     console.log(value.userDetails[0]);


   });




   //create common data assement


   var data1 = [{
     "commonLabel": "Groups",
     "commonTags": "test1, test2, test3, test4, test5, test6, test7"
   }, {
     "commonLabel": "Skills & Expertise",
     "commonTags": "test1, test2, test3, test1, test2, test3, test1, test2, test3, test1, test2"
   }, {
     "commonLabel": "Location",
     "commonTags": "test1"
   }, {
     "commonLabel": "Company",
     "commonTags": "test1"
   }]



   //add curved paths
   var distanceBetween = 70;

   var pathStart = -400;

   var path = viz.append("svg:g").selectAll("path")
     .data(data1)

   path
     .enter().append("svg:path")
     .attr("class", function(d) {
       return "link "
     })

   path.attr("d", function(d, i) {
     var sx = 0;
     var tx = 235;

     var sy = 120;
     var ty = 120;


     pathStart += 125;

     var dx = 0;
     var dy = getRadius(d) + (distanceBetween * i) - pathStart;
     var dr = Math.sqrt(dx * dx + dy * dy);

     console.log("dy", dy);

     return "M" + sx + "," + sy + "A" + dr + "," + dr + " 0 0,1 " + tx + "," + ty;
   });
   //add curved paths





   //create circles to hold the user images
   var circle = viz.append("svg:g").selectAll("circle")
     .data(data);

   //enter
   circle
     .enter()
     .append("svg:circle")
     .attr("id", function(d) {
       return d.userName;
     })
     .attr("r", function(d) {
       return "30";
     })
     .attr("cx", function(d, i) {
       return "235" * i;
     })
     .attr("cy", function(d, i) {
       return "120";
     })
     .style("fill", function(d, i) {
       return "url(#" + i + "-" + d.userName.toLowerCase() + ")";
     })


   var distanceBetween = 65;
   var circle = viz.append("svg:g").selectAll("circle")
     .data(data1);

   //enter
   circle
     .enter()
     .append("svg:circle")
     .attr("id", function(d) {
       return d.commonLabel;
     })
     .attr("r", function(d) {
       return getRadius(d);
     })
     .attr("cx", function(d, i) {
       return 125;
     })
     .attr("cy", function(d, i) {
       return distanceBetween * i;
     })
     .style("fill", function(d, i) {
       return colores_google(i);
     });



   var text = viz.append("svg:g").selectAll("g")
     .data(data1)

   text
     .enter().append("svg:g");

   text.append("svg:text")
     .attr("text-anchor", "middle")
     .attr("x", "125")
     .attr("y", function(d, i) {
       return getRadius(d) + 15 + (distanceBetween * i);
     })
     .text(function(d) {
       return d.commonLabel;
     })
     .attr("id", function(d) {
       return "text" + d.commonLabel;
     });



   var counters = viz.append("svg:g").selectAll("g")
     .data(data1)

   counters
     .enter().append("svg:g");

   counters.append("svg:text")
     .attr("text-anchor", "middle")
     .attr("x", "125")
     .attr("y", function(d, i) {
       return ((getRadius(d) / 2) + (distanceBetween * i)) - 3;
     })
     .text(function(d) {
       var count = d.commonTags.split(",").length;
       if (count > 1) {
         return count;
       }
     })
     .attr("id", function(d) {
       return "textcount" + d.commonLabel;
     });
现场演示:

首先,您应该删除所有的幻数,以保持代码的干净性和可移植性

例如,这个:

pathStart += 125;
如何正确地画圆弧是一个数学问题。代码如下:

path.attr("d", function (d, i) {
    const sx = 0;    
    const sy = height/2;

    const a=width/2;
    const b = ((data1.length-1)/2-i)*distanceBetween;
    const c = Math.sqrt(a * a + b * b);
    const angle=Math.atan(a/b);
    let r;
    if(b===0){
        r=0;
    }else{
        r=1/2*c/Math.cos(angle);//also equals c/b*(c/2)
//  r=c/b*(c/2);
    }

    return `M${sx},${sy} A${r},${r} 0 0,${b>0?1:0} ${width},${height/2}`;
});
图中:


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